search for: cvlm

Hi All, when doing CVlm cross validation, I would just like to view the overall MS but i am having trouble getting just this value. I'm kina new to R. Any help really appreciates. Cheers, Ben -- View this message in context: http://r.789695.n4.nabble.com/Returning-overall-ms-for-CVlm-tp4664690.html Sent from the R...

Hello, I did a cross-validation using cvlm from DAAG package but wasn't sure how to assess the result. Does this result means my model is a good model? I understand that the overall ms is the mean of sum of squares. But is 0.0987 a good number? The response (i.e. gailRel5yr) has min,1st Quantile, median, mean and 3rd Quantile, and max a...

...on, the best model selected with backward selection and so on...). Afterwards I would like to perform internal cross validation of all 4 selected models and choose 1 out of 4 which has the lowest average mean squared error (MSE). I used to do it using the code below: library(DAAG) val.daag<-CVlm(df=training, m=1, form.lm=formula(Y ~ X1+X2+X3)) val.daag<-CVlm(df=training, m=1, form.lm=formula(Y ~ X1+X2+X4)) val.daag<-CVlm(df=training, m=1, form.lm=formula(Y ~ X3+X4+X5)) val.daag<-CVlm(df=training, m=1, form.lm=formula(Y ~ X4+X5+X7)) For the best selected model (the lowest MSE) I w...

Can anyone help explain to me why the two codes below have different result? I thought I can use log(time)~. to replace log(time)~dist+climb+timef.I am using CVlm from DAAG package. I think nihills is preloaded with the package. Thanks in advance. > CVlm(df=nihills, form.lm=formula(log(time)~.),plotit="Observed",m=2)Analysis of Variance Table Response: log(time) Df Sum Sq Mean Sq F value Pr(>F) dist 1 6.34 6.34 384.31...

...obtain this error (it must be sth related to df) that I don't understand, any help would be appreciated. cv.lm(df= dat, lm2.52f, m=3) Error en `[.data.frame`(df, , ynam) : undefined columns selected lm2.52f is my lm object, dat is a dataframe where the variables involved in .lm are I tried CVlm also but the same error Thanks, user at host.com -- View this message in context: http://r.789695.n4.nabble.com/cv-lm-syntax-error-tp3334889p3334889.html Sent from the R help mailing list archive at Nabble.com.

Hello, I used the cv.lm function to validate a linear regression model fit<-lm(y ~ x1+x2+x3+x4+0, data=mydata) without intercept I tried to validate the model by performing a leave one out cross validation procedure usinfg the cvlm function: CVlm(df=mydata, fit, m=196) But how can I get the adjusted R? from the output of this function. Or is there any other function to perform a leave one out cross validation procedure. Thank you very much in advance. A GRATIS f?r alle WEB.DE Nutzer: Die maxdome Movie-F...

...th 3 partitions: 1- 256MB on /boot; 2- 2GB on / for my dom0 (Debian 5.0) (eth0 default bridge for guests LAN); 3- 498GB exported with vblade-persist to my network (eth1 for the AoE protocol). On dom0 hypervisor01: vblade-persist setup 0 0 eth1 /dev/sda3 vblade-persist start all How to create a CVLM VG with /dev/etherd/e0.0 on each of my dom0s? Including the hypervisor01! I do not want to use GFS2/OCFS2 on top of CLVM, since I just want to provide live-motion. I''ll never try to setup two simultaneous domUs accessing the same CVLMs logical volumes. If someone can help me I will app...

Dear community, I have fitted a model using comands above, (rlm, lmrob or lmRob). I don't have new data to validate de models obtained. I was wondering if exists something similar to CVlm in robust regression. In case there isn't, any suggestion for validation would be appreciated. Thanks, user at host.com -- View this message in context: http://r.789695.n4.nabble.com/cross-validation-when-rlm-lmrob-or-lmRob-tp3382189p3382189.html Sent from the R help mailing list archive at...