search for: column1

Displaying 20 results from an estimated 74 matches for "column1".

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2006 Jun 07
4
Question: coding protected methods
...and coding Ruby in Rails, however it''s my 3rd day with this beast :) so I''m asking : When I added protected methods to the model before it was like: protected method.................... end Would this be a valid way to write a protected method as well ?: attr_protected :column1, :column2 Perhaps this particular call is already protected inherent to the call, yet do I need to surround it with "protected" and "end" ? TIA Stuart -------------- next part -------------- An HTML attachment was scrubbed... URL: http://wrath.rubyonrails.org/pipermail/rails/...
2010 Jun 22
0
Scrolling a tkcanvas non-starter
Hello, Is it possible to scroll a canvas that has a column of listboxes in it? Does scrolling only work with listboxes and text widgets? The following code displays the scrollbar, but - it has no thumb - does not respond to mouse clicks. - the vertical height of the tkcanvas (i.e. column1) is unconstrained. It's lower edge is out of view, and the lower button on the scrollbar is out of view. I expected the scrollbar and canvas to have a height of 200 pixels and to be able to use the scrollbar to bring different listboxes into view. I created this from examples on the forum, but...
2010 May 31
2
accessing a data frame with row names
Readers, I have entered a file into r: ,column1,column2 row1,0.1,0.2 row2,0.3,0.4 using the command: dataframe<-read.table("/path/to/file.csv",header=T,row.names=1) When I try the command: dataframe[,2] I receive the response: NULL I was expecting: row1 0.2 row2 0.4 What is my error with the syntax please? Yours, r251 man...
2004 Nov 23
5
number of pairwise present data in matrix with missings
is there a smart way of determining the number of pairwise present data in a data matrix with missings (maybe as a by-product of some statistical function?) so far, i used several loops like: for (column1 in 1:99) { for (column2 in 2:100) { for (row in 1:500) { if (!is.na(matrix[row,column1]) & !is.na(matrix[row,column2])) { pairs[col1,col2] <- pairs[col1,col2]+1 } } } } but this seems neither the most elegant nor an utterly fast solution. thanks for suggesti...
2008 Feb 26
1
Split data.frames depeding values of a column
Hello to all is there a function wich splits a data.frame (column1,column2,column3,....) into data1 <-(column1,column3....) #column2 = 1 data2 <-(column1,column3....) #column2 = 2 data3 <-(column1,column3....) #column2 = 3 ... Regards Knut
2009 May 14
2
Function to read a string as the variables as opposed to taking the string name as the variable
I am writing a custom function that uses an R-function from the reshape package: cast. However, my question could be applicable to any R function. Normally one writes the arguments directly into a function, e.g.: result=cast(table1, column1 + column2 + column3 ~ column4, mean) (1) I need to be able to write this statement as follows: result=cast(table1, string_with_columns ~ column4, mean) (2) string_with_columns = group of functions that ultimately outputs: "column1 + column2 + column3" Statement 1...
2009 Jul 07
2
How to separate the string?
Hi everyone, Hi want to separate the string(column1) for example column1 column2 column3 column4 column5 column6 bear b e a r cat c a t tiger t i g e r I know how to do this in excel where using MID function. Now I want...
2006 Apr 12
9
Showing Images from a file store
Hi all. I am wrting a small content management tool for my company and was trying to display some images from our file store shown below. <td> <img src="\\xx.xx.xxx.xx\xx\xx\xxx\abc.gif"/> The app was displaying the image when it is under the \public\images directory. Is there anything special we need to do to get a file from outside the root of the application? Any help
2010 Feb 27
1
New Variable from Several Existing Variables
...be "Yes", however if any one of the three existing variables is a "No", then then new variable should be a "No". I would then use that new variable as an exclusion for data in a new or existing dataset (i.e., if NewVariable = "No" then delete): Take this: Column1, Column2, Column3 Yes, Yes, Yes Yes, No, Yes No, No, No No, Yes, No Yes, Yes, No Generate this: Column1, Column2, Column3, NewVariable1 Yes, Yes, Yes, Yes Yes, No, Yes, No No, No, No, No No, Yes, No, No Yes, Yes, No, No And end up with this: Column1, Column2, Column3, NewVariable1 Yes, Yes, Yes,...
2009 Jun 15
2
Help with syntax error
Hi, I have written boxplot commands of this form before, but I don''t quite understand why the function call is reporting a syntax error in this instance. All parameters passed to the function are strings. Thanks in advance. Payam > simplevar <- function(wframe,column1,column2) { + tframe <- get(wframe) + x1 <- which(names(wframe)==column1) + x2 <- which(names(wframe)==column2) + print(tframe[x1]) + print(tframe[x2]) + gtitle <- paste(names(tframe[x2])," vs. ", names(tframe[x1]) + quartz(width=7,height=5,dpi=200)...
2012 May 21
3
Replace a variable by its value
I have a dataset called "raw-data" . I am trying to use the following code - col_name<-names(raw_data) for (i in 1:(length(names(raw_data))-2)) { tbl=table(raw_data$Pay.Late.Dummy, raw_data$col_name[i]) chisqtest<-chisq.test(tbl) } Say the 1st column of my raw_data is Column1. The idea is when i=1 then raw_data$col_name[i] will automatically become raw_data$Column1 , which is not happening. Kindly help? -- View this message in context: http://r.789695.n4.nabble.com/Replace-a-variable-by-its-value-tp4630734.html Sent from the R help mailing list archive at Nabble.com.
2003 Aug 07
2
Question about 'NA'
Hi all, Ive got a database with 10 columns (different variables) for 100 subjects, each column with different # of NA's. I'd like to know if it is possible to use a function to exclude the NA's using only a specific column, lets say: Data2 <- omit.exclude(Data1$column1) ??, then Data3 <- omit.exclude(Data1$column2) and so on I tried the code above but with no results Thanks for any help CM __________________________________ Yahoo! SiteBuilder - Free, easy-to-use web site design software
2013 Mar 21
2
Displaying median value over the horizontal(median)line in the boxplot
...a median value of 7.642552 but I only want it to be displayed as 7.6. Thank you so much for your help. I am very sorry for troubling you but I am very very new to this programming and to R as you can see. <quote author='arun kirshna'> Hi, Lines1<-readLines(textConnection("Column1 -1,2,3,4,5,6,6,7 COlumn2- 3,4,5,6,7,8,8 Column3-- 45,66,7,8,89, COlumn4-5,6,7,7,8,9 Column5 -5,6,7,8,8")) vec1<-unlist(strsplit(Lines1,"-")) dat1<-as.data.frame(t(read.table(text=vec1[grepl(",",vec1)],sep=",",fill=TRUE))) row.names(dat1)<-NULL colnames(...
2004 Oct 25
2
Reading sections of data files based on pattern matching
...s which I want to analyze plot etc. Since this will be used many people at the department I wanted to make sure that will do this in the best way. For instance I want to read a snippets of data from a text that look like this. ------------------------------- Lots of stuff ... @@Start Values@@ Column1 Column2 Column3 ... Row1 1 2 3 ... ... @@End Values@@ More stuff ... @@Start OtherValues@@ Column1 Column2 Column3 ... Row1 1 2 3 ... ... @@End OtherValues@@ I looked in the help files and found grep which operates on character strings, do I have to like this then? 1. Read file with readLines...
2007 Dec 24
2
expand.grid function
...several times and like the results it gives me. I am now trying something with it that I have not been able to get to work. For any n column matrix I would like to run this function on those n columns and store the results. For example, if my matrix has 1 column then this is just expand.grid(x = column1). If my matrix has two columns, then I want expand.grid(x = column1, y = column2), and so on for any number of columns... In a program I am writing, the user can specify any matrix. Does anyone know of a way for R to calculate this based on what the input matrix is? e.g. if this user gives a 3...
2009 Jun 17
6
script help
Hi ? I have a file. list.txt (two columns) ? column1??? column2 name??????? address ? ? I need to put in the letter file letter.txt eg: ? Dear: Chloe Address: CA ? Can I use this ? for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt ? Thank you for your help ? ? ? ? ? __________________________________________________...
2006 May 09
9
Active Record HELP!!!!!
Hello, Can someone kindly tell what the heck creating a relationship does in active record? I understand the idea of joining the tables and such. But how do I use it? Is it available in a scaffold? How about when I want to view a record and want to see all the joined data from the other table? Do I have to manually code the data I want from the other table? Does this automatically make the
2005 Dec 31
3
Semi-Dynamic table sorting (without AJAX)
...a simple method for doing so by using links in the titles. Having actually tried to implement this strategy, I have come across several refinements that I would like to share. First... your table view should look like this... ... <table> <tr> <th><%= link_to ''Column1'', :sort=>''column1'' %> <th><%= link_to ''Column2'', :sort=>''column2'' %> </tr> ..... </table> ... your ''model'' controller ''list'' action should look like this.... def...
2006 Apr 06
1
reshape question
Hi, I have a data fram like this: date column1 column2 column3 value1 value2 value3 1-1 A B C 10 5 2 2-1 A B D 5 2 0 3-1 A B E 17 10 7 How can I reshape it to: date column1 column2 column3 v x 1-1 A B C value1 10 1-1 A B C value2 5 1-1 A B C value3 2 2-1 A B D value1 5 2-1 A B D value2 2 2-1 A B D value3 0 3-1 A B E value1 17 3-1 A B E value2...
2006 Apr 20
0
parsing arguments of a function
Hi, I have a simple problem writing a function that is to be called like Myfunction( Column1 = low, Column2 = high, Column3 = all, Column4 = all, data = mydata) {. contourplot(z ~ mydata$Column3* mydata$Column3) . } Where Column1 and Column1 are the names of the dataframe mydata. How do I parse the arguments to obtain both, name and value of the argument. I tried strsplit(Column1, "...