search for: col2rgb

Hello Core Folk. Quite by accident I discovered today that col2rgb, when fed factors, acts on the integer representation of those factors: td <- as.factor(rainbow(5)) # not how I discovered the issue! td res <- col2rgb(td) res # but col2rgb("#FF0000FF") # this is td[1] but does not produce the same answer res[,1] # moreover as.integer(td) col2rgb(...

...I have a lot of colored objects and want each one printed as a foreground against a slightly lighter background. I thought I could try something like changing the alpha channel by first converting it to rgb. But prior to trying that, I'm stuck with how to get the color after converting using col2rgb() to be interpreted again as a color, rather than a simple vector? Anyone have any help/ or alternative suggestion... Thanks, -c ---------------------- TRYING WITH A SINGLE COLOR: mycol<-"red" > col2rgb(mycol) [,1] red 255 green 0 blue 0 > rgb(col2rgb(mycol),...

Hello I have a palette vector of colour blind colours (in hexadecimal) which I?m using for plots, but they are not see-through, and as I wanted to overlay some histograms I wanted to convert these colours to rgb, when you can set the opacity. I have found the function col2rgb(), which works in the sense that it gives a vector of numbers but these don?t work directly in rgb because they are too big. If I divide through to make them all less than 1 I don?t get the corresponding colour-blind hue, but something somewhat off. Here is the colour-blind palette in a plot: *...

...gt; Hello I have a palette vector of colour blind colours (in hexadecimal) > which I?m using for plots, but they are not see-through, and as I wanted to > overlay some histograms I wanted to convert these colours to rgb, when you > can set the opacity. > > I have found the function col2rgb(), which works in the sense that it gives > a vector of numbers but these don?t work directly in rgb because they are > too big. If I divide through to make them all less than 1 I don?t get the > corresponding colour-blind hue, but something somewhat off. > > Here is the colour-bli...

...of colour blind colours (in hexadecimal) > > which I?m using for plots, but they are not see-through, and as I wanted > to > > overlay some histograms I wanted to convert these colours to rgb, when > you > > can set the opacity. > > > > I have found the function col2rgb(), which works in the sense that it > gives > > a vector of numbers but these don?t work directly in rgb because they are > > too big. If I divide through to make them all less than 1 I don?t get > the > > corresponding colour-blind hue, but something somewhat off. > &gt...

...s (in hexadecimal) >>> which I?m using for plots, but they are not see-through, and as I wanted >> to >>> overlay some histograms I wanted to convert these colours to rgb, when >> you >>> can set the opacity. >>> >>> I have found the function col2rgb(), which works in the sense that it >> gives >>> a vector of numbers but these don?t work directly in rgb because they are >>> too big. If I divide through to make them all less than 1 I don?t get >> the >>> corresponding colour-blind hue, but something somew...

...s (in hexadecimal) >>> which I?m using for plots, but they are not see-through, and as I wanted >> to >>> overlay some histograms I wanted to convert these colours to rgb, when >> you >>> can set the opacity. >>> >>> I have found the function col2rgb(), which works in the sense that it >> gives >>> a vector of numbers but these don?t work directly in rgb because they are >>> too big. If I divide through to make them all less than 1 I don?t get >> the >>> corresponding colour-blind hue, but something somew...

Hi all, I'm trying to convert a series of rgb codes into a color name. What is my easiest option? So far I'm stuck with just converting to hex using rgb() and I know R knows a number of colours() but a mapping of the two has failed me. Any help in this regard will be highly appreciated. Regards, George

Hm..., Should these two versions produce the same solution? Unfortunately and shame to confess, I don't know much about the colors in R: myColors <- c("#FF7C00","#00BF40","#FFFF00") Colors=rgb2hsv(col2rgb(myColors)) apply(Colors,1,mean) h s v 0.2122974 1.0000000 0.9163399 * * * * * # Average the 1st two by taking the middle colour of a 3 colour palette x <- colorRampPalette(c("#FF7C00","#00BF40"), space = "Lab")(3)[2] # Average in the thi...

Win2k, R1.7.1: I am currently working with some growth curve data from a biotoxicology experiment. Each of 12 subjects had their blood drawn at 0, 2, 4, 6, 8, and 10 weeks. For the purposes of the project, it would be helpful if I were able to do the following: a. Produce 12 panels, each displaying the *same* data, with the "strip" at the top of a particular panel showing

...in the grDevices package (other others) to manipulate them. E.g., you can convert them to various color spaces and perhaps use the mean in one of those spaces as your 'average color'. > myColors <- c(One="#FF7C00",Two="#00BF40",Three="#FFFF00") > col2rgb(myColors) One Two Three red 255 0 255 green 124 191 255 blue 0 64 0 > rgb2hsv(col2rgb(myColors)) One Two Three h 0.08104575 0.3891798 0.1666667 s 1.00000000 1.0000000 1.0000000 v 1.00000000 0.7490196 1.0000000 Bill Dunlap TIBCO Softwa...

... and if you need to convert back: ?as.hexmode -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Sat, Apr 16, 2016 at 8:20 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > ?strtoi > > You'll have to remove

...ia the new 'alpha' argument to the rgb() and hsv() functions, or as a string of the form "#RRGGBBAA". NOTE: most devices draw nothing if a colour is not opaque, but PDF and Quartz devices will render semitransparent colours. A new argument 'alpha' to the function col2rgb() provides the ability to return the alpha component of colours (as well as the red, green, and blue components). I'm using R 2.0.0 on Windows 2000 and wanted to try this feature. The following simple test works fine: pdf("c:/alpha.pdf") plot(rnorm(1:100),rnorm(1:100),col=&quot...

On 16/04/2016 8:47 AM, Atte Tenkanen wrote: > Hi, > > How would you calculate the "mean colour" of several colours, for > example c("#FF7C00","#00BF40","#FFFF00")? > Bert answered your subject line question. Your text is asking something else: if those are colours, you don't want to treat each of them as a single integer. A

Hi Martin, Great that you follow this. My original intention was to be able to translate colornames to hsv because this would allow using colornames to cut out a certain part of the colorwheel for colorcoding (HSV component H, see my code below) I think internally we might have colors represented as Colornames, ColorIntegers, ColorHexcodes, ColorRGBs, ColorHSVs (ColorCMYs?) however the R-user

...ow much about fuzzy matching. For example, following some examples I found in the archives and the wiki, I wrote this little function to create a table of official R colors and sort it if desired: colorSpecTable <- function(col = colors(), sort = NULL){ require(gplots) rgbcodes <- t(col2rgb(col)) names <- col hex <- col2hex(col) df <- data.frame(name = names, hex.code = hex, rgbcodes) # additional elements for other color spaces could be added if (!identical(sort, NULL)) df <- sort.data.frame(df, by = sort) } Note that sort.data.frame is from the R-...

Hi, I'm trying to draw a 2D plot using multiple tints of red. The (simplified) setup is the following: || year | x | y || My idea is that each year is plotted with a different tint of red. Older year (lightest) -> Later year (darkest). I've managed to plot this with different scales of grays simply by doing: palette(gray(length(years):0/length(years))) before the plot and for each

How does one get a list of all the color names supported by R and the mapping between color names and hex codes? Color names are things like "red", "salmon", etc. I am using Windows 2000 Professional and R 1.7.1.

...d identical results. Can someone explain how to make this happen? I need to be able to specify an array of rgb values for the 'col' parameter. colnames.col <- c("black", "red", "blue", "green") colnames.rgb <- apply(as.matrix(colnames.col), 1, col2rgb) dimnames(colnames.rgb)[[2]] <- colnames.col baseline <- 1:32 offset2 <- 2*baseline offset3 <- 3*baseline offset4 <- 4*baseline offsets <- cbind(offset2, offset3, offset4) # Produces expected result X11() matplot(baseline, col = colnames.col[1], type = "l") matlines(of...

...Should these two versions produce the same solution? I wouldn't expect them to. Duncan Murdoch Unfortunately and > shame to confess, I don't know much about the colors in R: > > myColors <- c("#FF7C00","#00BF40","#FFFF00") > Colors=rgb2hsv(col2rgb(myColors)) > apply(Colors,1,mean) > > h s v > 0.2122974 1.0000000 0.9163399 > > * * * * * > > # Average the 1st two by taking the middle colour of a 3 colour palette > x <- colorRampPalette(c("#FF7C00","#00BF40"), space = &...