Displaying 20 results from an estimated 565 matches for "cberri".
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cberry
2009 Oct 13
7
lapply() reccursively
Hi all,
I was wondering whether it is possible to use the lapply() function
to alter the value of the input, something in the spirit of :
a1<-runif(100)
a2<-function(i){
a1[i]<-a1[i-1]*a1[i];a1[i]
}
a3<-lapply(2:100,a2)
Something akin to a for() loop, but using the lapply() infrastructure.
I haven't been able to get rapply() to do this.
The reason is that the "real"
2006 Dec 10
4
sample "n" random positions from a matrix
Hi there,
I have a binary matrix (dim 100x100) filled with values 0 and 1. I need select a record "n" positions of that matrix when values are 1. How can I do that?
Thanks for all,
Miltinho
Brazil
---------------------------------
[[alternative HTML version deleted]]
2019 Jun 07
2
[R] Open a file which name contains a tilde
> On Jun 6, 2019, at 2:04 PM, Richard O'Keefe <raoknz at gmail.com> wrote:
>
> How can expanding tildes anywhere but the beginning of a file name NOT be
> considered a bug?
>
>
I think that that IS what libreadline is doing if one allows a whitespace separated list of file names.
As reported in R-help,
https://www.mail-archive.com/r-help at
2010 Jul 07
3
How do I test against a simple null that two regressions coefficients are equal?
Hi there,
I run two regressions:
y = a1 + b1 * x + e1
y = a2 + b2 * z + e2
I want to test against the null hypothesis: b1 = b2. How do I design the test?
I think I can add two equations together and divide both sides by 2:
y = 0.5*(a1+a2) + 0.5*b1 * x + 0.5*b2 * z + e3, where e3 = 0.5*(e1 + e2).
or just y = a3 + 0.5*b1 * x + 0.5*b2 * z + e3
If I run this new regression, I can test against
2019 Mar 03
2
bug: sample( x, size, replace = TRUE, prob= skewed.probs) produces uniform sample
When `length( skewed.probs ) > 200' uniform samples are generated in R-devel.
R-3.5.1 behaves as expected.
`epsilon` can be a lot bigger than illustrated and still the uniform distribution is produced.
Chuck
> set.seed(123)
>
> epsilon <- 1e-10
>
> ## uniform to 200 then small
> p200 <- prop.table( rep( c(1, epsilon), c(200, 999-200)))
> ## uniform to 201
2001 Nov 29
1
rug(x) clip warning incorrect if par("xlog")==TRUE (PR#1188)
To wit:
> plot(1:2,1:2,log="x")
> rug(1:2) # should not warn
Warning message:
some values will be clipped in: rug(1:2)
> plot(1:2,1:2,log="x")
> rug(c(0,.1,.2)) # should warn, but does not
>
I believe this fixes the problem:
% diff -c /tmp/orig.rug.R /tmp/cberry.rug.R
*** /tmp/orig.rug.R Thu Nov 29 12:59:00 2001
--- /tmp/cberry.rug.R Thu Nov 29
2010 Nov 27
1
Bug in parseNamespaceFile or switch( , ... ) ?
parseNamespaceFile() doesn't seem to detect misspelled directives. Looking
at its code I see
switch(as.character(e[[1L]]),
<lots of args omitted here>,
stop(gettextf("unknown namespace directive: %s",
deparse(e)), call. = FALSE, domain = NA))
but this doesn't seem to function as I expect, viz. to stop with an error
if I type a wrong directive.
2011 Dec 21
4
qqnorm & huge datasets
Hi,
When qqnorm on a vector of length 10M+ I get a huge pdf file which
cannot be loaded by acroread or evince.
Any suggestions? (apart from sampling the data).
Thanks.
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 11.10 (oneiric) X 11.0.11004000
http://mideasttruth.com http://honestreporting.com http://camera.org
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2011 Jan 24
2
Help with expression
I have a problem with expressions. I am trying to create a title where
the parameter of interest is displayed as a Greek character. Which
parameter is being considered is stored in a character variable.
As an example, if I have
param <- "alpha"
and then do
plot(0, 0, main = bquote(Parameter==.(param)))
then in the title I get "Parameter = alpha",
whereas I want the
2019 Jun 05
6
Open a file which name contains a tilde
Hi,
As I can see via path.expand a filename which contains a tilde anywhere gets automatically crippled.
+> path.expand("a ~ b")
[1] "a /home/user b"
+> path.expand("a ~ b ~")
[1] "a /home/user b /home/user"
I want to open a file regardless whether its name contains any character unless 0.
The unix filesystem allow the creation of such files, it
2019 Jun 05
6
Open a file which name contains a tilde
Hi,
As I can see via path.expand a filename which contains a tilde anywhere gets automatically crippled.
+> path.expand("a ~ b")
[1] "a /home/user b"
+> path.expand("a ~ b ~")
[1] "a /home/user b /home/user"
I want to open a file regardless whether its name contains any character unless 0.
The unix filesystem allow the creation of such files, it
2008 May 27
4
help with simple function
I have a matrix of frequency counts from 0-160.
x<-as.matrix(c(0,1,0,0,1,0,0,0,1,0,0,0,0,1))
I would like to apply a function creating a new column (x[,2])containing
values equal to:
a) log(x[m,1]) if x[m,1] > 0; and
b) for all x[m,1]= 0, log(next x[m,1] > 0 / count of preceding zero values
+1)
for example, x[1,2] should equal log(x[2,1]/2) = log(1/2) = -0.6931472
whereas x[3,2] should
2008 Dec 11
3
check if a certain ... argument has been passed on to my user-defined function
Hi,
How can I check if a certain ... argument has been passed on to my
user-defined function or not?
foo <- function(data, ...)
{
### here I want to check whether xlab was passed with the ... arguments
### or if the ... arguments did not contain an xlab argument
}
I tried missing(xlab) , exists(xlab) and several other things but did not
find a solution.
TIA,
Mark
2008 Dec 09
2
Better way to find distances between points in a set?
I was playing around a bit to see how I could find the two points in a
set of points (or ordered pairs) furthest from each other.
Here's what I did:
1) created a Nrow by 2col matrix, so each row contains an x,y coordinate
pair.
2) fed the matrix to a nested mapply (cv is my matrix):
mapply(function(k,l) mapply(function(x,y,a,b)
+
2007 Feb 22
4
Crosstabbing multiple response data
Using R version 2.4.1 (2006-12-18) on Windows, I have a dataset which resembles this:
id att1 att2 att3
1 1 1 0
2 1 0 0
3 0 1 1
4 1 1 1
ratings <- data.frame(id = c(1,2,3,4), att1 = c(1,1,0,1), att2 = c(1,0,0,1), att3 = c(0,1,1,1))
I would like to get a cross tab of counts of co-ocurrence, which might resemble this:
2008 Jan 23
4
image question
Hi,
I have a question regarding the image function. Is there a way to specify a
separate color set for each column in the matrix?
TIA,
ajar.
[[alternative HTML version deleted]]
2006 Dec 31
4
Does SQL group by have a heavy duty equivalent in R
I have hundreds of humans who have undergone SNP genotyping at hundreds of
loci. Some have even undergone the procedure twice or thrice (kind of an
internal control).
So obviously I need to find those replications, and confirm that the results
are the same. If there is discordance then I need to address it.
I tried to use the aggregate function
nr.attempts
2008 Oct 30
3
why does sample(x, n) give the same n items in every separate runs?
Hello R users,
I have gene expression data of two groups of genes (large and small). Gene expression intensities of those genes are classified into 1 to 10 levels. What I want is to make a random set of genes that have the same levels as the small group from large group using sample().
I used smallvec to hold the number of genes in each levels (1 to 10) for small group, largevec for large group.
2005 Oct 20
2
md5sum for R-2.2.0-win32.exe ??
I get
c1279b77fcccf40379f59a83523a440e *R-2.2.0-win32.exe
but I see
e8bdf765fe8013129045314c8e2605fd *rw2011.exe
on several USA mirrors.
I hope the latter is merely in need of a replacement and not an
indication of a problem with the web sites.
Chuck
Charles C. Berry (858) 534-2098
Dept of Family/Preventive Medicine
E
2005 Oct 26
1
unexpected '[<-.data.frame' result
Is this a bug?
If not, I am curious to know why '[<-.data.frame' was designed to yield
a.frame$y != a.frame$z rather than refusing to carry out the operation at
all.
> a.frame <- data.frame( x=letters[1:5] )
> a.frame[ 2:5, "y" ] <- letters[2:5]
> a.frame[[ "z" ]][ 2:5 ] <- letters[2:5]
> a.frame
x y z
1 a b <NA>
2 b c