search for: cast_df

.../10", "202 2006/10", "215 2006/10", "61 2006/12", "119 2006/12", "148 2006/12", "179 2006/12", "185 2006/12", "BC 2006/12", "190 2006/12", "HC 2006/12", "198 2006/12"), class = c("cast_df", "data.frame"))) replace(taxa, taxa>0, 1) #Is preforms as I would like except that I only want to do this on columns 5:19 and I can't just use replace(taxa, taxa[,5:19]>0, 1) #any suggestions Stephen Sefick -- Stephen Sefick Let's not spend our time and resourc...

...uot;none", "weak", "moderate", "severe", "verysevere"), class = c("ordered", "factor")), p = c(0.04, 0.02, 0.26, 0.6, 0.07, 0.07, 0.05, 0.33, 0.42, 0.14)), .Names = c("dur", "score", "p"), class = c("cast_df", "data.frame")) # columns do not ad to 100% because of rounding; never mind qplot(dur,p,data=cf1, fill=score)+ geom_area() -- View this message in context: http://n4.nabble.com/Strange-tick-in-ggplot-geom-area-and-ordering-again-tp1294692p1294692.html Sent from the R help mail...

...d=c("Sample.Name", "SNP")) Error in if (!missing(id.var) && !(id.var %in% varnames)) { : missing value where TRUE/FALSE needed > traceback() 4: melt_check(data, id.var, measure.var) 3: melt.data.frame(as.data.frame(data), id = attr(data, "idvars")) 2: melt.cast_df(subset(t.norm1, select = c("Sample.Name", "SNP", "Pool", "polar.1", "polar.2")), id = c("Sample.Name", "SNP"), measure = c("polar.1", "polar.2")) 1: melt(subset(t.norm1, select = c("Sample.N...

..., 4, 4, 4, 4, 3)), .Names = c("DC", "week6", "week7", "week8", "week9", "week10", "week11", "week12", "week13", "week14", "week15", "week16", "week17"), class = c("cast_df", "data.frame"), row.names = c(NA, 39L)) # This fails mod.ok <- lm(as.matrix(dat[,-1]) ~ DC, data=dat) (av.ok <- Anova(mod.ok, idata=idata, idesign=~week)) # But this works dat[,-1] <- apply(dat[,-1],2, jitter ) mod.ok <- lm(as.matrix(dat[,-1]) ~ DC, data=dat) (av.ok...

...A, NA, NA, 13.5, 9.3, 14.3, 35.8), `2012` = c(99459, 2013, 81313, 0.1, 5.9, 7.5, 1223, NA, NA, 20.5, NA, 8.6, NA, NA, NA, NA, NA, NA, NA, NA)), .Names = c("", "2005", "2009", "2010", "2011", "2012"), row.names = c(NA, 20L), class = c("cast_df", "data.frame")) hi<-format(f,big.mark=",",scientific=F) regexpr("\\.", hi) #don't know to get location of "." in a dataframe of chars nam2<- structure(list(var1 = c("GDP (LCU,bn)", "GDP ($, bn)", "GDP per capi...

...128.125, 231.25, 50, 140.625, 0, 0, 0, 0, 0, 3.125, 12.5, 9.375, 18.75, 18.75, 3.125, 3.125, 0, 0, 0, 6.25, 0, 15.625, 21.875, 31.25, 15.625, 28.125, 15.625 )), .Names = c("CD", "GC", "GF", "P", "PR", "SC", "SH"), class = c("cast_df", "data.frame"), row.names = c("119 2006/10", "119 2006/12", "119 2007/02", "119 2007/04", "119 2007/06", "119 2007/08", "119 2007/10", "119 2008/01", "148 2006/05", "148 2006/10", &qu...

...ucture(list(DayOfYear = c(3L, 30L, 149L, 156L, 165L, 171L, 187L, 198L, 212L, 215L, 216L, 218L, 221L, 224L, 226L, 227L), Quantity = c(1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L)), .Names = c("DayOfYear", "Quantity" ), row.names = c(NA, 16L), class = c("cast_df", "data.frame"), idvars = "DayOfYear", rdimnames = list( structure(list(DayOfYear = c(3L, 30L, 149L, 156L, 165L, 171L, 187L, 198L, 212L, 215L, 216L, 218L, 221L, 224L, 226L, 227L )), .Names = "DayOfYear", row.names = c("3", "30", &q...

...", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21"), class = "data.frame")), class = c("cast_df", "data.frame"))

dear R wizards:? I am wrestling with reshape.? I have a long data set that I want to convert into a wide data set, in which rows are firms and columns are years. > summary(rin) firm fyear sim1 Min. :1004.00 Min. :1964.0 Min. : -1.00000 1st Qu.:1010.00 1st Qu.:1979.0 1st Qu.: -0.14334 Median :1016.00 Median :1986.0 Median : 0.00116 Mean