search for: cars93

Cordial saludo, Estoy haciendo una grafica de la base de datos Cars93 conde relaciono Manufacturer con Price con este codigo library(MASS) with(Cars93,plot(Manufacturer, Price, las=2, ylab="Precio (en $1,000)")) necesito el comando para que queden ordenados de manera ascendente como en la grafica 2, muchas gracias por su ayuda Grafica 1 [image: M-P.JP...

Hi all, I would like to strip the R prompt from a series of code lines and copy the resulting text into a R script. For example, consider the following : ##### str1<-" > library(MASS) > data(Cars93) > attach(Cars93) > imosaic(data.frame(AirBags,Cylinders,Origin))" str2<-gsub('>','',str1) ###### This gives, as expected .? > str2 [1] "\n library(MASS)\n data(Cars93)\n attach(Cars93)\n imosaic(data.frame(AirBags,Cylinders,Origin))" How can I now act...

...mucked things up, but that's another story). Anyhow, when I ran ``make check'' I got an error right toward the end. Looking in the directory ``tests'' I found that the error was associated with the file reg-tests-3.R, and the complaint was that it couldn't find the object Cars93 from the MASS package. So I edited reg-tests-3.R and stuck in the line ``data(Cars93)'': ===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+=== ## lm.influence where hat[1] == 1 if(require(MASS)) { # data(Cars93) # <------------------------- INSERTED LINE #...

Hello, i'm newbie of R and think it is a really good alternative to SPSS. But i have more problems using elementary things comparable with using advanced methods. (1) How can i value label i.e the variable X in data.frame DATA with the labels ( 1=very good ) (2=good). spss syntax when DATA is in Spreadsheet is: value labels X 1 'very good'. 2 'good'. execute. (2) How can i

Hi, I am trying to "convince" lattice to use bold face in an expression containing Greek characters without any luck. Example code (without Greek characters, renders the expression in bold) library(lattice) data(Cars93,package=="MASS") splom(~Cars93[,5:8]|Origin,data=Cars93,panel=function(x,y,...) { panel.splom(x,y,...) dum<-format(cor(x,y,use="complete",method="kendal"),dig=2) panel.text(30,40,bquote(.(dum)),font=2) },pscales=0,col="gray" ) Example code (with Greek ch...

...k.rstudio.com/jclow/Archive20130725HistogramApp/ To run the app, select ?Use Sample Data? , then select ?MPG.city? under choose a column, then finally select box plot. Sample code: Below is a snippet of my code to demonstrate the problems I have. library(ggplot2) #sample data from ggplot2 data(Cars93, package = "MASS") dataSet <- Cars93 #variables to calculate the range to extend the axis dataVector <- unlist(dataSet[,"MPG.city"]) dataRange <- max(dataVector) - min(dataVector) graphRange <- c(min(dataVector) - dataRange/5, max(dataVector) + da...

Dear R users, I have a question regarding how to make row labels readable in a heat map. I have successfully made a heat map using function "heatmap.2" in the package "gplots". However, as there are many rows in the heat map, I have difficulties labeling them (heatmap.2 provides a parameter "labRow" to label the row names, but as I have too many rows, I can not make

I would like to plot two different samples on the same scatterplot in R using different symbols for the different groups. Could someone please let me know how this can be done? Thank you very much. Thad ***************************************************************************** Thaddeus Tarpey Phone: (937) 775-2861 Wright State University

...tbl=tb.table(iris, k=5) print(tbl) levels(iris$Species) tbl=tb.table(iris, k=5, by='Species') length(tbl) names(tbl) print(tbl) tbl=tb.table(iris, k=5, by='Species', right=T) print(tbl) tbl=tb.table(iris, breaks='FD', by='Species') print(tbl) library(MASS) levels(Cars93$Origin) tbl=tb.table(Cars93, k=5, by='Origin') names(tbl) print(tbl) tbl=tb.table(Cars93, breaks='FD', by='Origin') print(tbl) I find that this package would be very useful and would like to hear the opinion of the interested parties in participating. Best regards, -- J...

R version 1.0.1 OS RedHat Linux 6.1 In attempting to test for numeric vectors in a data frame, I tried: apply(dataframe,2,is.numeric) and found that it returned FALSE for all vectors whether they were numeric or not. I tracked this to the fact that as.array() was converting the data frame to character vectors, and thought I could solve it by using array(), which preserved the mode of the

...was my first thought). I am not having problems building other packages. Any thoughts? * creating vignettes ... ERROR Error in namespaceExport(ns, exports) : undefined exports: abbey, accdeaths, Aids2, Animals, anorexia, austres, bacteria, beav1, beav2, biopsy, birthwt, Boston, cabbages, caith, Cars93, cats, cement, chem, coop, cpus, crabs, Cushings, DDT, deaths, drivers, eagles, epil, farms, fdeaths, fgl, forbes, GAGurine, galaxies, gehan, genotype, geyser, gilgais, hills, housing, immer, Insurance, leuk, lh, mammals, MASS.data.load, mcycle, mdeaths, Melanoma, menarche, michelson, minn38, motor...

...325 3.600828 3.569987 3.592482 3.599979 3.580547 3.600799 3.599768 73 74 75 76 77 78 79 80 @@ -432,44 +433,57 @@ Potentially influential observations of lm(formula = 1000/MPG.city ~ Weight + Cylinders + Type + EngineSize + DriveTrain, data = Cars93) : - dfb.1_ dfb.Wght dfb.Cyl4 dfb.Cyl5 dfb.Cyl6 dfb.Cyl8 dfb.Cyln dfb.TypL -8 -0.16 0.00 -0.10 -0.07 -0.24 -0.44 0.01 0.12 -19 -0.03 0.09 -0.01 -0.03 0.00 -0.01 -0.03 0.08 -28 0.11 -0.15 0.04 0.02 0.02 0.02 0.04 0.07 -39 -0.1...