search for: caracteristics

...14'), values = c(0, 1, 2, 3, 4, 5, 6)) + theme_bw()+ geom_abline(aes(intercept = Intercept, slope = Slope, colour = treatment, linetype=treatment), data = lines) Thank you, Sigrid -- View this message in context: http://r.789695.n4.nabble.com/nesting-scale-manual-caracteristics-in-ggplot-tp4017171p4017171.html Sent from the R help mailing list archive at Nabble.com.

Hi All. I am beginning a project of Call center and predictive diales, my call center have 50 operators, I have 50 analog phone line with the company PTT in my country. I have the following questions: 1- Can I to work this project with Asterisk? 2- What caracteristic of hardware need for my servers? 3- For 50 analog phone line what tipe of card digium I need? Thanks in advanced, Regards.

...rmware 1.6.3.0067) - 1 Polycom IP301 (same firmware) - 2 Grandstream HT487 1.0.7.11 ATA - 1 2*BRI ISDN card from Beronet working in P2P TE mode - Standard Supermicro server P4 3.0GHz 1GB RAM RAID 1 The problem only occurs with Polycom phones, since we add the 301 (never used) on the network. SIP caracteristics: * no reinvite (occurs also with reinvite) * ulaw * No NAT, dynamic addresses * 240 seconds between registrations RTP on ports 2220 to 31000 After sniffing packets while not working, it seems packets are correctly sent on the negotiated ports, example: INVITE from asterisk to polycom with RTP 1...

Hi Guys environment: Debian Sarge + Samba3.0.2 desktops WInXP Just a newbie question How can a manage samba administrator to change user profiles and others caracteristics of WinXP desktops??? What I have done till now. [global] unix charset = ISO-8859-1 workgroup = MGO realm = SERVIDOR DE REDE DA MGO netbios name = HERCULES server string = %h server update encrypted = Yes obey pam restrictions = Yes pa...

Hi everyone, I need your help to solve a problem with occurrence and two dataframes. I have an excel table of 15200 lines. Each line correspond to a tree analyzed for its structures. I have all the structures in columns (48 structures). The occurrence of these structures has been counted on every tree. For example, the tree 12607 has 3 structures CV11, 1 structure IN12 and none (0) of the rest of

Do you have a simplified example with a code? It is not clear to me what do you mean by tree but if you refer to tree data structure, maybe you could change the data structure to tree (https://cran.r-project.org/web/packages/data.tree/vignettes/data.tree.html) and try to write comparison of two tree objects. It might be easier that data.frame alone. On 12 September 2017 at 12:27, C?line L?scher

Hello everybody I don't understand how I'm supposed to use svydesign caracteristics to explain to R that my sampling design is the following one Data base = tab1 here are the five first rows of the database (nrow = 11792) num esp Quarters Totcat Totshp Totgt Tbtpos fpc1 Totanim Id_An 10 2045 G...

Yes of course, I can share this short view of the datas. Here is the head() of data100, containing all the trees with a final value higher than 100?: CV11 CV12 CV13 CV14 CV15 CV21 CV22 CV23 CV24 CV25 CV26 CV31 CV32 CV33 CV41 CV42 CV43 CV44 CV51 CV52 IN11 IN12 IN13 1291 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1083 0 4 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3919 0 0 0 0 0 0 0 0 0 0 0 2 0

Hi C?line, Looks like you are looking for a statistical test between two sets of distributions, such as KS test, for example, generate histogram for each row in an identical way and run KS test. But if you are after simple difference you may use compare package ( https://cran.r-project.org/web/packages/compare/index.html). Best, -m PS: Data is already plural :) datas does not exist. On 12

Hello I have the following problem : group the lines of a dataframe when no information change (Matricule, Nom, Sexe, DateNaissance, Contrat, Pays) and when the value of Debut of lines i = value Fin of lines i-1 I can obtain it with a do loop. Is it possible to avoid the loop ? The dataframe initial is df1 dput(df1) structure(list(Matricule = c(1L, 1L, 1L, 6L, 6L, 6L, 6L, 6L, 6L, 8L, 8L, 8L,

...ID Teacher.exp Teacher.Other Teacher.RE 1 3 Modi School A Sage, Kendell 27.87402 0 -0.04372723 2 4 Modi School A Delgado, Vanessa 26.20701 0 -0.88280564 Es decir, cada observación es un aula en una escuela con informacion sobre el grado, nombre del maestro, otras caracteristics del maestro. Muchas gracias por la ayuda. On Mon, Jul 13, 2015 at 6:37 PM Carlos Ortega <cof en qualityexcellence.es> wrote: > Hola, > > No entiendo muy bien. > El número de clases lo puedes modificar a tu gusto, en la variable "numDi". > > He puesto un valor...

Gracias Carlos, Tu codigo es un gran paso en el sentido correcto pero no produce exactamente lo que estoy buscando. Mi "solucion" en stackoverflow <http://stackoverflow.com/questions/31137940/randomly-assign-teachers-to-classrooms-imposing-restrictions/31143808#31143808> produce un data frame `schoolGrade` con 240 observaciones y 7 variables. Mi objetivo es poder generar un data