search for: bxp

Hi all, I've been using the scatterplot3d function (from the scatterplot3d library) to create 3D plots. I was wondering whether there is anyway to group the points according to a particular group variable. For example I used the plot function as plot( factor( <GROUPINGVAR> ) , <PLOTVARS> ) to organise the results in a according to the grouping variable. I was wondering

Full_Name: Steve Ellison Version: 2.4.1 OS: Windows, Linux Submission from: (NULL) (194.73.101.157) bxp() allows specifcation of box locations with at=, but neither adjusts xlim= to fit at nor does it respect xlim provided explicitly. This is because bxp() now includes explicit xlim as c(0.5, n+0.5), without checking for explicitly supplied xlim (or ylim if horizontal). This also prevents simple ad...

...the cloud() function. Is there a way I can draw lines along each axis on the plot. Any help would be greatly appreciated. Many Thanks Rishabh THE SCRIPT: s3d <- scatterplot3d(x, y, z, type="n", xlab="x", ylab="y", zlab="z") for (g in unique(G)) { bxp.stx <- boxplot.stats(x[G==levels(G)[g]]) bxp.sty <- boxplot.stats(y[G==levels(G)[g]]) bxp.stz <- boxplot.stats(z[G==levels(G)[g]]) lines(s3d$xyz.convert(bxp.stx$stats[c(3, 3)], bxp.sty$stats[c(3, 3)], bxp.stz$stats[c(1, 5)])) lines(s3d$xyz.convert(bxp.stx$stats[c(3, 3)], b...

Full_Name: Christian Ritter Version: 1.3.1 OS: win/nt Submission from: (NULL) (130.104.139.32) not a bug but lack of feature: outlier symbol can't be changed in bxp in bxp: ... points(rep(x, length(out)), out, col = border) ... as you can see, no pty or pch argument is used. -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info&...

Good Afternoon- I was wanting to alter the boxplot to remove the lower whisker, both the whisker line and staple just on the lower end. Is there a way to do this? As my code is currently: boxplot(log_loads~ind,data=nfmaum, horizontal=TRUE, notch=T, outline=FALSE, whisker=0, main="Maumee River Near Future Climate Scenarios", ylab="Log Load",xlab="Climate Scenarios")

...vignette as well as slides by Paul Murrell, I have tried to implement a boxplot using the graphical primitives from the grid package. I, however, always seem to have problems with the scale or rather, the data do not match the axis. Below is the function and code run. I am using R2.9.0 # Function bxplt <- function(x, range = 2){ require(grid) bxp <- boxplot(x, range = range, plot = FALSE) O <- bxp$out On <- length(O) grid.yaxis() grid.lines( rep(unit(0.5, "npc"), 2), c(unit(bxp$stats[1], "native"), unit(bxp$stats[5], "native")),...

Was there ever a convenient method provided to add boxplots to the current plot at specified x values? There was a question by Martin Maechler some time ago here, but I could seem to find any satisfactory resolution of it. I see that there is an add=T option to boxplot and bxp, but I don't see how to set the x-values. url: http://www.econ.uiuc.edu Roger Koenker email roger at ysidro.econ.uiuc.edu Department of Economics vox: 217-333-4558 University of Illinois fax: 217-244-6678 Champaign, IL 61820 -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-....

dear all, could somebody tell me how I can plot mild outliers as a circle(?) and extreme outliers as an asterisk(*) in a box-whisker plot? Thanks very much in advance -- View this message in context: http://www.nabble.com/mild-and-extreme-outliers-in-boxplot-tp25040545p25040545.html Sent from the R help mailing list archive at Nabble.com.

Hi, Is this expected behavior (R-3.6.0)? dat <- cbind(x = 1:10, y = 10:1) ylab <- substitute(X[t], list(t = 2)) plot(dat, ylab = ylab) # works (correctly displays ylab) boxplot(dat, ylab = ylab) # fails boxplot(dat, ylab = as.expression(ylab)) # works Thanks & cheers, M

It's not new anyway. You see the same behaviour with boxplot(dat, ylab=quote(X[2])) and it boils down to the use of do.call("bxp", ...) in the internals. As a general matter, expression() exists to prevent this sort of confusion, e.g., in this construction, > X <- quote(Y+1); bquote(f(.(X))) f(Y + 1) is indistinguishable from just entering f(Y+1), so f has no way of detecting whether or not it is intended to e...

I'd like to iterate my earlier request (#7737) to change the documentation for bxp(). The argument outpch=" " needs to be replaced with outpch=NA in two places. I actually wrote this part of the documentation myself at one point, but have now realized that pch=NA and pch=" " are not the same: x <- split(rlnorm(26e4), letters) ## NA generates small...

...eds more careful thought than=20 I have time for right now, so I'll leave it for someone else (or for=20 myself in a less busy future, which may exist in some alternate universe). What I'd suggest you do in the short term is simply to set up the plot=20 axes the way you want before calling bxp, then call it with add=3DTRUE. Duncan Murdoch = *******************************************************************=0D=0A= This email and any attachments are confidential. Any use, co...{{dropped}}

Full_Name: Bob O'Hara Version: 2.6.0 OS: Windows XP Submission from: (NULL) (88.112.20.250) Using horizontal=TRUE with boxplot() confuses it as to what is an x- or y-axis. At least, xlim= and ylim= are the wrong way round, log="x" (or "y") and xaxt= work as expected, I haven't looked at anything else. Some code to see if you can reproduce the bug (or discover

Hi, Is it possible to produce box-and-whisker plots given that I have the median, interquartile and 5/95th centile values, but not the data from which they come? It seems that it ought to be possible to coerce bxp to do what I want, but I can't quite see how. Thanks, Matthew -- Matthew Vernon, Research Fellow Ecology and Epidemiology Group, University of Warwick http://blogs.warwick.ac.uk/mcvernon

Dear list, I am using a external program that outputs Q1, Q3, median, upper and lower whisker values for various datasets simultaneously in a tab delimited format. After importing this text file into R, I would like to plot a boxplot using these given values and not the original series of data points, i.e. not using something like boxplot(mydata). Is there an easy way for doing this? If I am not

Dear Users Is there any way to generate lines instead of points for outliers in the boxplot function? Thanks AA. [[alternative HTML version deleted]]

Hi, I would like to make a box and whisker plot but use a sample weight for each observation. I've searched around a bit and have not found a method of doing this. Anyone have any advice? Thanks much, Sean Parks -- View this message in context: http://www.nabble.com/sample-weight-for-box-plot--tp26104205p26104205.html Sent from the R help mailing list archive at Nabble.com.

Hi All, As a follow-on from the mail below, it is possible to have boxplots based on means and variance for more than one input, i.e., bxp(input1,input2,....) Thanks in Advance, Dermot ******** Previous Mail on this subject *********** >I have a couple more questions about boxplots. In the books I've read on >statistics (I'm not a statistics expert but just a poor engineer trying >to help his wife with the analysi...

I'm graphing a series of boxplots of grouped data inside a function that passes the data.frame, the names vector, and a title vector. Because both the data subset changes with each successive pass through the function, occasionally the names vector turns up with only one group to plot. This is an expected result. However, when the names argument in boxplot has only a single name, it

...y. My apologies if I am being redundant. (A scan of CRAN revealed that someone had experienced problems with the "horizontal" argument, but he was spelling it out in full, so that was a different issue.) If I execute > x <- rnorm(100) > tmp <- boxplot(x,plot=FALSE) > bxp(tmp,horiz=TRUE) I get the horizontal boxplot that I wanted. However if I go straight for it, as in > boxplot(x,horiz=TRUE) I get the warning message: parameter "horiz" couldn't be set in high-level plot() function and get a vertical boxplot. I traced the warning down to the...