Displaying 20 results from an estimated 86 matches for "breslow".
2007 Jul 08
2
Making Gehan-Breslow test for Survival data
Hi all,
The survivals functions can be tested by the Log-rank test and others, for
example the Gehan-Breslow. The graham breslow work with the alpha values.
But I don't know how is the Gehan-Breslow test with R. Somebody know a
type function?.. or other suggestions? Any help will be really
appreciated
Jos? Bustos
Marine Biologist
Master Apllied Stat Program
University of Concepci?n
2005 Jan 11
2
Breslow Day Test
Breslow-Day test
A statistical test for the homogeneity of odds ratios.
Homogeneity
In <javascript:void(0);> systematic reviews homogeneity refers to the
degree to which the results of studies included in a review are similar.
"Clinical homogeneity" means that, in studies included in...
2005 Oct 18
4
Efficient ways of finding functions and Breslow-Day test for homogeneity of the odds ratio
Dear all,
I have been trying to find a function to calculate the Breslow-Day test for
homogeneity of the odds ratio in R. I know the test can be preformed in SAS
but i was wondering if anyone could help me to perform this in r.
In addition i have the fullrefman file to search for functions in the basic
R packages, does anyone have any suggestions of an efficient way...
2012 Aug 31
2
test Breslow-Day for svytable??
Hi all,
I want to know how to perform the test Breslow-Day test for homogeneity of
odds ratios (OR) stratified for svytable. This test is obtained with the following code:
epi.2by2 (dat = daty, method = "case.control" conf.level = 0.95,
units = 100, homogeneity = "breslow.day", verbose = TRUE)
where "daty" is the...
2006 Mar 07
1
breslow estimator for cumulative hazard function
...stratum
versus time should be approximately parallel.
i.e
fit<-coxph(Surv(start,end,status)~sx+rated+AGLEVEL+strata(Z1),data=ALLDPinfectionandbronchitis)
ss<-survfit(fit)
plot(ss,fun="cumhaz")
My question is on whether the cumulative hazard given by the above command
is actually a breslow estimator for baseline cumulative hazard ,i.e,
estimator=sum( number of death/ (sum(risk score in risk set)) or a
nelson-Aalen estimator. if the above command does not give me breslow
estimator, please advise on how I can get it.
Thanks for any help given.
kind regards,
sing yee
[[alternati...
2002 Dec 17
1
Breslow Day Test
Hello everyone,
Does anyone know if I can do Breslow Day Test for the homogeneity of odds
ratio in R?
Thanks!
- Jacqueline
2010 Nov 16
1
Breslow-Day test
Dear R Users,
I'm looking for a package that allows to test hypothesis about a
homogeneity of odds ratio in k 2x2 tables. I know that Breslow-Day is
suitable but does anybody could me point out a package? I found diffR,
but as far as I see this package is for IRT theory.
Best,
Robert
2009 Mar 10
2
simple question beginner
Hi there,
I am beginner in R and I have some basic question. Suppose I run a common procedure such as a t test or cox model like below:
out<-coxph( Surv(tstart,tstop, death1) ~ x1+x1:log(tstop+1) , test1,method=c("breslow"))
Which yields the following result:
Call:
coxph(formula = Surv(tstart, tstop, death1) ~ x1 + x1:log(tstop +
1), data = test1, method = c("breslow"))
coef exp(coef) se(coef) z p
x1 -9.58 6.89e-05 6.83 -1.40 0.16
x1:log(tstop +...
2011 Jul 22
3
Cox model approximaions (was "comparing SAS and R survival....)
...ession has for anything
branded with the word "exact", I currently see no reason to ever use
that particular computation in a Cox model. I'm not quite ready to
remove the option from coxph, but certainly am not going to devote any
effort toward improving that part of the code.
The Breslow approximation is less accurate, but is the easiest to
program and therefore was the only method in early Cox model programs;
it persists as the default in many software packages because of history.
Truth be told, unless the number of tied deaths is quite large the
difference in results between it a...
2009 Jun 15
2
Schoenfeld Residuals with tied data
Dear all,
I am struggling with calculation of Schoenfeld residuals of my Cox Ph
models.
Based on the formula as attached, I calculated the Schoenfeld residuals for
both non tied and tied data, respectively.
And then I validated my results with R using the same data sets. However, I
found that my results for non-tied data was ok but the results for tied data
were different from R's.
How
2009 Aug 19
2
Problem with predict.coxph
We occasionally utilize the coxph function in the survival library to fit multinomial logit models. (The breslow method produces the same likelihood function as the multinomial logit). We then utilize the predict function to create summary results for various combinations of covariates. For example:
mod1<-coxph(Depvar~Price:Product+strata(ID),data=MyDCMData2,na.action=na.omit,method="breslow")...
2009 Feb 25
3
survival::survfit,plot.survfit
...ean?
is it the survival curve with different covariates at different points?
or just the baseline survival curve?
for example, I run the following code and get the survival curve
####
library(survival)
fit<-coxph(Surv(futime,fustat)~resid.ds+rx+ecog.ps,data=ovarian)
plot(survfit(fit,type="breslow"))
summary(survfit(fit,type="breslow"))
####
for the first two failure points, we have s(59|x1)=0.971, s(115|x2)=0.942
how can we guarantee that s(59|x1) is always greater than s(115|x2)?
since s(59|x1)=s_0(59)^exp(\beta'x1) and s(115|x2)=s_0(115)^exp(\beta'x2),
we can manip...
2010 Sep 08
4
coxph and ordinal variables?
...ittle puzzled
as STATA and R seem to be yielding different survival estimates for the same
dataset when treating a variable as ordinal. Ordered() is used to represent
an ordinal variable) I understand that R's coxph (by default) uses the Efron
approximation, whereas STATA uses (by default) the Breslow. but we did
compare using the same approximations. I am wondering if this is a result of
how coxph manages an ordered factor?
Essentially, this is a survival dataset using tumor grade (1, 2, 3 and 4) as
the risk factor. This is more of an 'ordinal' variable, rather than a
continuous variab...
2009 Jul 13
0
adjusting survival using coxph
...a bit
less obvious how to properly combine multiple variables (like stage
and grade) - examples I've found aren't very helpful. For instance,
can someone explain what these two function calls are doing differently?
cox.model1 <- coxph(Surv(time,outcome)~stage+grade,method="breslow")
cox.model2 <- coxph(Surv(time,outcome)~stage+grade
+stage:grade,method="breslow")
Also, am I right to think that this is how I would plot the survival
curves for stage in a 50 year old patient?
cox.model3 <- coxph(Surv(time,outcome)~stage+I
(age-50),method="b...
2009 Nov 20
0
How do I specify a partially completed survival analysis model
...fter I simulate Time and Censor data vectors denoting the censoring
time
and status respectively, I can call the following function to fit the
data
into the Cox model (a is a data.frame containing 4 columns X1, X2, Time
and
Censor):
b = coxph (Surv (Time, Censor) ~ X1 + X2, data = a, method = "breslow");
Now the purpose of me doing simulation is that I have another mechanism
to
generate the number b2. From the given b2 (say it's 4.3), Cox model can
be
fit to generate b1 and check how feasible the new model is. Thus, my
question is, how do I specify such a model that is partially comple...
2008 Jan 16
1
exact method in coxph
...0 14.84
2 1 2 0 1 1 08.63
A complication here is that units can experience repeated events while
previous events are still ongoing.
I tried the following: cox1 <- coxph( Surv( dur0, dur1, event) ~
strata(eventn) + x)
This works fine under the breslow and efron method. However, since I have a
fair number of ties, especially of repeated events while previous events are
still ongoing, the exact method seems advisable.
The help says that the exact method is computationally demanding, but even
after days the computing it won't finish. Also, if...
2007 Aug 06
1
(Censboot, Z-score, Cox) How to use Z-score as the statistic within censboot?
Dear R Help list,
My question is regarding extracting the standard error or Z-score from a
cph or coxph call. My Cox model is: -
modz=cph(Surv(TSURV,STATUS)~RAGE+DAGE+REG_WTIME_M+CLD_ISCH+POLY_VS,
data=kidneyT,method="breslow", x=T, y=T)
I've used names(modz) but can't see anything that will let me extract
the Z scores for each coefficient or the standard errors in the same way
one can use coef (modz).
I need to get either the se or Zscore as I am hoping to be able to use
the Zscore within a statistic fun...
2009 Apr 25
3
Nomogram with stratified cph in Design package
...assumptions. This is where I go wrong, but I'm not sure where.
Non-Stratified Nomogram:
f<-cph(S~A+B+C+D+E+F+H,x=T,y=T,surv=T,time.inc=10*12,method="breslow")
srv=Survival(f)
srv120=function(lp) srv(10*12,lp)
quant=Quantile(f)
med=function(lp) quant(.5,lp)
at.surv=c(0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9)
at.med=c(120,80,60,40,30,20,15,10,8,6,4,2,0)
nomogram(f,lp=F, fun=list(srv120, med),funlabel=c("120-mo Survival","Median
Survival&qu...
2002 Apr 12
1
summary: Generalized linear mixed model software
...re I summarize the software, I note
that there are several ways of doing statistical inference for
generalized linear mixed models:
(1)Standard maximum likelihood estimation, computationally intensive
due to intractable likelihood function
(2) Penalized quasi likelihood or similar approximations (Breslow &
Clayton, 1993; Lee & Nelder, 1999, Schall 1991). This method is not
good for binomial outcomes in particular. Theoretically, it is
consistent when the cluster size increases. It is not consistent when
the number of clusters increases while the size of each cluster remain
constant. The sta...
2009 May 04
1
Nelson-Aalen estimator of cumulative hazard
Hi,
I am computing the Nelson-Aalen (NA) estimate of baseline cumulative hazard in two different ways using the "survival" package. I am expecting that they should be identical. However, they are not. Their difference is a monotonically increasing with time. This difference is probably not large to make any impact in the application, but is annoyingly non-trivial for me to just