search for: bmw

Displaying 20 results from an estimated 84 matches for "bmw".

Did you mean: bmt
2020 Jul 23
5
Issue with Keytab memory
...ing to samba shares from windows. In the corresponding samba logs I found entries: .... [2020/07/23 12:08:06.697678, 1] ../../source3/librpc/crypto/gse.c:660(gse_get_server_auth_token) gss_accept_sec_context failed with [ Miscellaneous failure (see text): Failed to find cifs/lpeda1.muc at EUROPE.BMW.CORP(kvno 26) in keytab MEMORY:cifs_srv_keytab (aes256-cts-hmac-sha1-96)] [2020/07/23 12:08:06.698028, 1] ../../auth/gensec/spnego.c:1218(gensec_spnego_server_negTokenInit_step) gensec_spnego_server_negTokenInit_step: gse_krb5: parsing NEG_TOKEN_INIT content failed (next[(null)]): NT_STATUS_LOGO...
2013 May 08
1
[LLVMdev] [lld] contentHash in the Reader ?
..., at 10:50 AM, Chandler Carruth <chandlerc at google.com> > wrote: > > >> >>> What are the SHA-3 variants that you think would suite these needs ? >> >> > I want to look at the implementation complexity. The winner (and the > official SHA3 algorithm), BMW and Skein are all worth looking at. > > > If your primary criterion is through-put on large, desktop-class CPUs, > Skein is likely to be the winner. Keccak (the official SHA3) is also > pretty fast on CPUs (and significantly better in hardware implementations, > not that it matte...
2008 Mar 09
1
Two sample t-test
Hi, I want to perform t-test in R for each individual car. Here is what i have. Is there a way i can test each car? The original table (test.csv) Car Tester2 Tester2 Controller1 Controller2 Audi 0.56 0.9 0.5 0.9 Toyota 0.2 0.9 0.9 0.2 Honda 0.5 0.9 0.1 0.5 BMW 0.2 0.3 0.5 0.7 > cars<-read.table("c://test.csv",header=T,sep=",", + skip=2,comment.char="") > cars Toyota X0.2 X0.9 X0.9.1 X0.2.1 1 Honda 0.5 0.9 0.1 0.5 2 BMW 0.2 0.3 0.5 0.7 > head(cars) Toyota X0.2 X0.9 X0.9.1 X0.2.1 1 Honda...
2011 Dec 01
1
transform data.frame holding answers --> data.frame holding logicals
Hello Hello I have a data frame, x, holding 5 persons answering the question which cars they have used: # the data frame x <- as.data.frame( matrix( c('BMW', '', '', 'Mercedes', 'VW', '', 'Skoda', 'VW', 'BMW', '', '', '', 'VW', 'Skoda', '' ), ncol=3, dimnames=list( NULL, paste( ...
2005 Jan 28
0
Read and get a BMW 735i
...Western Express Company launches a loss-free lottery for E-gold users. Take your chance to win a lot of prizes! The list of prizes includes: T-shirts, backpacks, sun-glasses are granted to ALL participants of the lottery. 1000 BOSCH washing machines. 1000 BOSCH refrigerators 10 world tours. and BMW 735i is a SUPERPRIZE!. Please find enclosed the detailed instructions on participation in the lottery. ATTENTION! Only E-gold uses are invited! Contact us: phone: +1-(212)-736-7465 fax: +1-(212)-564-1350 president@paycard2000.com Western Express 555 8-th Ave #1001 New York, NY 10018 USA -...
2002 Jun 16
3
lm() function to get coefficients doesn`t work
Hi, to get the residuals and coefficients I did the following: kurse <- read.table("kurse.txt" header=T) the data: index bmw mru rwe vow kar sie bas 1 159,70 74,18 338,21 89,03 110,30 141,23 178,53 67,97 2 160,76 73,46 343,66 89,38 110,30 142,66 180,45 68,30 3 162,45 74,18 349,12 91,54 108,54 146,22 183,12 68,85 4 162,18 72,74 349,12 92,20 106,43 144,80 181,75 68,52 5 161,64 72,98 340,93 91,43 101,87 144,...
2002 Jun 19
2
solve() doesn`t work
...t;- cbind(1,kurse[,-c(1)]) > y <- kurse$index > t(x) %*% x Error in t(x) %*% x : requires numeric matrix/vector arguments > x <- as.matrix(x) > xtxi <- solve(t(x) %*% x) Error in solve.default(t(x) %*% x) : singular matrix `a' in solve My data looks like this: index bmw mru rwe vow kar sie bas 1 159.70 74.18 338.21 89.03 110.30 141.23 178.53 67.97 2 160.76 73.46 343.66 89.38 110.30 142.66 180.45 68.30 3 162.45 74.18 349.12 91.54 108.54 146.22 183.12 68.85 4 162.18 72.74 349.12 92.20 106.43 144.80 181.75 68.52 5 161.64 72.98 340.93 91.43 101.87...
2020 Jul 23
0
Issue with Keytab memory
...rom windows. > In the corresponding samba logs I found entries: > .... > [2020/07/23 12:08:06.697678, 1] ../../source3/librpc/crypto/gse.c:660(gse_get_server_auth_token) > gss_accept_sec_context failed with [ Miscellaneous failure (see text): Failed to find cifs/lpeda1.muc at EUROPE.BMW.CORP(kvno 26) in keytab MEMORY:cifs_srv_keytab (aes256-cts-hmac-sha1-96)] > [2020/07/23 12:08:06.698028, 1] ../../auth/gensec/spnego.c:1218(gensec_spnego_server_negTokenInit_step) > gensec_spnego_server_negTokenInit_step: gse_krb5: parsing NEG_TOKEN_INIT content failed (next[(null)]): NT_...
2020 Jul 23
0
Issue with Keytab memory
...In the corresponding samba logs I found entries: > .... > [2020/07/23 12:08:06.697678, 1] > ../../source3/librpc/crypto/gse.c:660(gse_get_server_auth_token) > gss_accept_sec_context failed with [ Miscellaneous failure > (see text): Failed to find > cifs/lpeda1.muc at EUROPE.BMW.CORP(kvno 26) in keytab > MEMORY:cifs_srv_keytab (aes256-cts-hmac-sha1-96)] > [2020/07/23 12:08:06.698028, 1] > ../../auth/gensec/spnego.c:1218(gensec_spnego_server_negTokenI > nit_step) > gensec_spnego_server_negTokenInit_step: gse_krb5: parsing > NEG_TOKEN_INIT content fai...
2007 Jul 26
1
Download multiple stock quotes in a loop
...question, but I haven't been able to do it right. I am trying to download multiple stock quotes in a loop, so that every timeseries is safed with the symbol of the stock. Can anybody help me out? Here's the code: require(tseries) startd <- "2000-06-01" stocks <- c("bmw.de", "vow.de", "dte.de") for(stock in stocks) stock <- as.timeSeries(get.hist.quote(instrument=stock, start=startd, quote="Close", compress="d")) } Thanks in advance, Owe -- Owe Jessen Diplom-Volkswirt Hanssenstra?e 17 24106 Kiel jessen at econin...
2003 Dec 30
4
Assignments in loops
Greetings all. Any help with the following would be appreciated. I want to create a data frame for each file in a directory. The following code does not work but it may show what I am trying to do: carmakes <- c('BMW','Chrysler','Citroen','Fiat','Ford','Holden','Honda', 'Mercedes','MG','Mitsubishi','Nissan','Peugeot','Renault','Subaru','Toyota', 'VW') for (brand in carmakes) { fyle <...
2013 May 08
2
[LLVMdev] [lld] contentHash in the Reader ?
...you want to burn space in order to *not* compare them at all. I would suggest storing 256 bits at least. > > >> What are the SHA-3 variants that you think would suite these needs ? > > I want to look at the implementation complexity. The winner (and the official SHA3 algorithm), BMW and Skein are all worth looking at. > >> >> Thanks >> >> Shankar Easwaran >> >> -- >> Qualcomm Innovation Center, Inc. is a member of Code Aurora Forum, hosted >> by the Linux Foundation >> >> > -------------- next part -----------...
2020 Feb 28
4
Issue compiling Samba 4.11.6 with GNUTLS 3.6.12 (Not standard location)
...er und Partner Diplom-Informatiker Partnerschaftsgesellschaft Partner: Anne Feldmeier, Georg Biberger Sitz und Registergericht: M?nchen PR 480 Umsatzsteuer-ID: DE206858618 -------------------------------------------------------------------------------------------------------- Erreichbarkeit bei der BMW Group: Tel.: +49 89 382-49629 Mobil: +49 172 7719871 E-Mail: Georg.Biberger at partner.bmw.de<mailto:Georg.Biberger at partner.bmw.de>
2013 May 08
0
[LLVMdev] [lld] contentHash in the Reader ?
On May 8, 2013, at 10:50 AM, Chandler Carruth <chandlerc at google.com> wrote: > > What are the SHA-3 variants that you think would suite these needs ? > > I want to look at the implementation complexity. The winner (and the official SHA3 algorithm), BMW and Skein are all worth looking at. If your primary criterion is through-put on large, desktop-class CPUs, Skein is likely to be the winner. Keccak (the official SHA3) is also pretty fast on CPUs (and significantly better in hardware implementations, not that it matters here), and has the advanta...
2010 Aug 11
0
fExtremes
Hi. I need to convert data to time series. My problem is that when I converted my data to time series the data comes with time. I just want the date because doesn't work with "blockMaxima()". > data(bmwRet) > BMW=as.timeSeries(bmwRet) > head(BMW) GMT BMW.RET 1973-01-02 0.047704097 1973-01-03 0.007127223 1973-01-04 0.008883307 1973-01-05 -0.012440569 1973-01-08 -0.003569961 1973-01-09 0.000000000 > List=as.timeSeries(list) #my data > head(List) GMT Obs 1970-01-01 02:07:50 86342.98 1970...
2009 Sep 10
0
Multiple (multiplexed) simultaneous ssh connections - Cygwin bug?
...approx 100 to fix our specific problem. I've also tried mas_ssh_starts=100 but this prevent the ssh server to start up again. Did you have an Idea, or the right syntax for maxsessions mit freundlichen Gr??en / best regards Rainer Winhard ------------------------------------------------------- BMW Group Rainer Winhard IT Service Management Informationstechnologiezentrum - ITZ Bremer Str. 6 80807 M?nchen Tel: +49 89 382 58363 mobil : +49 176 601 58363 mailto: Rainer.Winhard at bmw.de<mailto:Rainer.Winhard at bmw.de> Url: http://www.bmwgroup.com/ ----------------------------------------...
2013 Nov 05
1
Opus Stereo for Speech
...the speech transmission at a certain bitrate be the same as Mono voice transmission? Is it at all possible to use Opus for stereo Speech( considering acceptable latency and package loss thresholds) ? Thanks and best regards Fereydoon Vahidi -------------------------------------------------------- BMW Group Fereydoon Vahidi Mobile-Apps, Online-Entertainment, CE-Connectivity 80788 M?nchen Tel: +4917660130570 Mail: fereydoon.vahidi-digehsaraei at bmw.de<mailto:juergen.hauser at bmw.de> Web: http://www.bmwgroup.com<http://www.bmwgroup.com/> ---------------------------------------------...
2020 Jun 30
2
Issues with FLOCK on NFS Share
...er und Partner Diplom-Informatiker Partnerschaftsgesellschaft Partner: Anne Feldmeier, Georg Biberger Sitz und Registergericht: M?nchen PR 480 Umsatzsteuer-ID: DE206858618 -------------------------------------------------------------------------------------------------------- Erreichbarkeit bei der BMW Group: Tel.: +49 89 382-49629 Mobil: +49 172 7719871 E-Mail: Georg.Biberger at partner.bmw.de<mailto:Georg.Biberger at partner.bmw.de>
2003 Jan 03
2
type of representation
Hi I have some data that i want to plot but i don't find how to do it. I have car types (bmw,renault,mercedes,seat ...), colors and a number for each car type-color relation.I want to come up with a matrix representation of cars vs colors where in each intersection i could set a dot proportional in size to my third variable. Can anybody give me a clue of hoe to come up with such represen...
2003 Jan 03
1
Take care with codes()! (was type of representation)
Ahh yes, sorry about that. Here's the corrected snippet: # Create an Example Data Frame Containing Car x Color data carnames <- c("bmw","renault","mercedes","seat") carcolors <- c("red","white","silver","green") datavals <- round(rnorm(16, mean=10, sd=4),1) data <- data.frame(Car=rep(carnames,4), Color=rep(carcolors, c(4,4,4,4) )...