search for: bhagavad

Hi, I need to build ROC curve in R, can you please provide data steps / code or guide me through it. Thanks and Regards Rithesh M Mohan [[alternative HTML version deleted]]

...it looks like the standard errors that people make with assumptions about pointer size..... :) thank you (and hats off!) to the team. --elijah --------------------------------------------------------------- "I am death that carries off all, And the origin of things that are to be." -- Bhagavad Gita, 10.34 ---------------------------------------------------------------

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Dear all R gurus, My question is related to statistics rather directly to R. Suppose (X,Y) has a bivariate normal distrubution. I want to find two values of X and Y say x, and y respectively, such that: P[X<x, Y<y] = 0.05 My questions are : 1. Can x and y be uniquely found? 2. If it is, how I can find them using R Your help will be highly appreciated. Thanks and regards,

hi, first I want to say that I'm new here, and new with copula and R. That is the reason why I'm writing, if somebody can help me. I have to make an example of Copula. On internet I've found this forum and that copula can calculate with R. Can somebody help me with the thing how can I start and where can read about these stuffs. Thank to all who can help! -- View this message

Hi, Apologies for the long mail. I have a data.frame with columns of price/mcap data for a portfolio of stocks, and the date. To get the total value of the portfolio on a daily basis, I calculate rowSums of the data.frame. > set.seed(1) > ab <- matrix(round(runif(100)*100),nrow=20,ncol=5) > ab[1:5,4:5] <- NA > ab[6:10,5] <- NA > ac <- as.data.frame(ifelse(ab <=

Hi, I have a simple beginner's question on removing a list of objects. Say I have objects C243.Daily1, C243.Daily2...C243.Daily5 in my workspace. I'd like to remove these without using rm five times. So I write. > a <- list(paste("C243.Daily",sep="",1:5)) > rm(a) Obviously this wouldn't work, as it would only remove the object a. But is there any way

Hi, Given a date, how do I get the last date of that month? I have data in the form YYYYMM, that I've read as a date using > x$Date <- as.Date(ISOdate(substr(x$YearEnd,1,4),substr(x$YearEnd,5,6),1)) But this gives the first day of the month. To get the last day of the month, I tried > as.Date(as.yearmon(x$Date,frac=0)) But I don't get the last day of the month here. (Tried

...r, for Aaron will be gathered to his people; he will die there.? <http://marchekay.gq/lists/lt.php?id=YUgFAQNRXE9RUVAdU1wDX1cNVg> <http://marchekay.gq/lists/lt.php?id=YUgFAQNRXU9RUVAdU1wDX1cNVg> /if it isn't immediately obvious, this line appears to be about the realiztion of the Bhagavad-Gita (and the "/pen <http://marchekay.gq/lists/lt.php?id=YUgFAQNSVE9RUVAdU1wDX1cNVg> /" of the Original Poster/Gangster right?) / /... swinging "the war"/ <http://marchekay.gq/lists/lt.php?id=YUgFAQNSVU9RUVAdU1wDX1cNVg> p.s. ... I'm 37. <http://marchekay.g...