search for: asgn

...he ANOVA code (anova.lm) is doing? I am having a hard time reconciling what the text books have as a brute force regression and the formula algorithm in 'R'. Specifically I see: p <- object$rank if (p > 0L) { p1 <- 1L:p comp <- object$effects[p1] asgn <- object$assign[object$qr$pivot][p1] nmeffects <- c("(Intercept)", attr(object$terms, "term.labels")) tlabels <- nmeffects[1 + unique(asgn)] ss <- c(unlist(lapply(split(comp^2, asgn), sum)), ssr) df <- c(unlist(lapply(split(asgn, a...

...000 0.2476221 0.4952442 [8] 0.7428664 0.9904885 Here is what one should get: > abs((df$x-mean(df$x)))*summary(df.lm)$coef[2,2] [1] 0.5769836 0.4327377 0.2884918 0.1442459 0.0000000 0.1442459 0.2884918 [8] 0.4327377 0.5769836 Here is the corrected code: if (type=="terms"){ asgn <- attrassign(object) beta<-coef(object) hasintercept<-attr(tt,"intercept")>0 if (hasintercept) asgn$"(Intercept)"<-NULL nterms<-length(asgn) predictor<-matrix(ncol=nterms,nrow=NROW(X)) dimnames(predictor)<-list...

...442 [8] 0.7428664 0.9904885 Here is what one should get: > abs((df$x-mean(df$x)))*summary(df.lm)$coef[2,2] [1] 0.5769836 0.4327377 0.2884918 0.1442459 0.0000000 0.1442459 0.2884918 [8] 0.4327377 0.5769836 Here is the relevant section of corrected code: if (type=="terms"){ asgn <- attrassign(object) beta<-coef(object) hasintercept<-attr(tt,"intercept")>0 if (hasintercept) asgn$"(Intercept)"<-NULL nterms<-length(asgn) predictor<-matrix(ncol=nterms,nrow=NROW(X)) dimnames(predictor)<-list...

...strata (only) nmstrata <- sub("^`(.*)`$", "\\1", nmstrata) if(intercept) nmstrata <- c("(Intercept)", nmstrata) qr.e <- er.fit$qr rank.e <- er.fit$rank qty <- er.fit$resid maov <- is.matrix(qty) asgn.e <- er.fit$assign[qr.e$piv[1:rank.e]] ## we want this to label the rows of qtx, not cols of x. nobs <- NROW(qty) if(nobs > rank.e) { ## APPARENT BUG 1: # result <- vector("list", max(asgn.e) + 2) # asgn.e[(rank.e+1):nobs] <- max(...

...a <- sub("^`(.*)`$", "\\1", nmstrata) > if(intercept) nmstrata <- c("(Intercept)", nmstrata) > qr.e <- er.fit$qr > rank.e <- er.fit$rank > qty <- er.fit$resid > maov <- is.matrix(qty) > asgn.e <- er.fit$assign[qr.e$piv[1:rank.e]] > ## we want this to label the rows of qtx, not cols of x. > nobs <- NROW(qty) > if(nobs > rank.e) { > ## APPARENT BUG 1: > # result <- vector("list", max(asgn.e) + 2) > # asgn...

...arguments I think the problem lies in the computation of the 'ss' terms (line 237 in the file mlm.R in the source code). Changing this (and the following line) by something similar to what is done in summary.manova seems to resolve the problem: comp <- as.matrix(fit$effects)[seq(along=asgn), ,drop=FALSE] uasgn <- unique(asgn) nterms <- length(uasgn) ss <- list(nterms) df <- numeric(nterms) for(i in seq(nterms)) { ai <- (asgn == uasgn[i]) ss[[i]] <- crossprod(comp[ai, ,drop=FALSE]) df[i] <- sum(ai) }

...lmfit<-lm(dat~1) > anova(mlmfit, X=~1) > Error: ceiling(length.out) : Non-numeric argument to mathematical function > > this error occurs in anova.mlm > > if (rk > 0) { > p1 <- 1:rk > comp <- object$effects[p1, ] > asgn <- object$assign[object$qr$pivot][p1] > nmeffects <- c("(Intercept)", attr(object$terms, > "term.labels")) > tlabels <- nmeffects[1 + unique(asgn)] > ix <- split(seq(length = nrow(comp)), asgn) #HERE &...

Hi, In R I get the following: > x <- 1:9 > f <- as.factor(1:9) > i <- model.matrix(~x+f) > > attr(i, "assign") [1] 0 1 2 2 2 2 2 2 2 2 whereas in S I get the following: > attr(i, "assign") $"(Intercept)": [1] 1 $x: [1] 2 $f: [1] 3 4 5 6 7 8 9 10 Has anybody written a model.matrix function to get the same result as S?

...rs for certain contrasts and following the help page for se.contrast() I tried the following but I get an error: >se.contrast(test.aov,list(Material=="A",Material=="B",Material=="C",Material=="D"),coef=c(1,1,-1,-1),data=testdata) Error in matrix(0, length(asgn), ncol(effects), dimnames = list(nm[1 + : length of dimnames [1] not equal to array extent I have tested this on R 2.0.1 on Windows XP and Solaris and get the same error on both systems. I am unsure as to what I am doing wrong here. Thanks for any help. Jamie Jarabek

I'm using plot to make a simple plot but I want to control where the tick marks go on bot axes. The graphical parameters xaxp and yaxp seem to be ignored by the plot function so I tried setting them using op <- par(no.readonly=T) par(xaxp=c(-2.4,-2.2,5), yaxp=c(-2500,10000,6)) plot(...) par(op) but they are still ignored. Next I tried to use the axis function as follows op <-

>>>>> SOEIRO Thomas via R-devel >>>>> on Fri, 17 Jan 2025 14:19:31 +0000 writes: > Following Duncan Murdoch's off-list comments (thanks again!), here is a more complete/flexible version: > > as.data.frame.lm <- function(x, ..., level = 0.95, exp = FALSE) { > cf <- x |> summary() |> stats::coef() > ci <- stats::confint(x,