search for: annuals

I could use some advice regarding xyplot. I've got 2 time series. Both cover approximately the same period of time (ie, 1940 to 2009). But one series has annual data and the other has monthly data. One refers to university enrollment; the other to unemployment rates. Both are currently in the same data frame. I'd like to use the monthly times series as a light grayscale background for a

I could use some advice. I've got 2 time series. Both cover approximately the same period of time (ie, 1940 to 2009). But one series has annual data and the other has monthly data. One refers to university enrollment; the other to unemployment rates. Both are currently in the same data frame. I'd like to use the monthly times series as a light grayscale background for a plot of the

Dear Sir/Madam, How to use getSymbols() to get annual data? For example, I need the annual stock price of APPLE from the year 2000 to 2016. How to write the command? I only know how to get the daily data. It is: getSymbols("AAPL",from="2000-01-01",to="2016-12-31") Thank you very much. Have a good week! Best regards, Yingrui Liu [[alternative HTML

Hi, I'd like to make a time series at an annual frequency. > a<-xts(x=c(2,4,5), order.by=c("1991","1992","1993")) Error in xts(x = c(2, 4, 5), order.by = c("1991", "1992", "1993")) : order.by requires an appropriate time-based object > a<-xts(x=c(2,4,5), order.by=1991:1993) Error in xts(x = c(2, 4, 5), order.by =

Hello, I'm very new to R, and so my question is simple. I have data record with 80 years of daily temperatures in one long string. The dates are also recorded, in YYMMDD format. I'd like to learn an elegant simple way to pull out the annual averages. (Obviously, every 4th year has 366 days.) I know I can set up a formal loop to create annual records and then average. But R

I have a monthly price index series x, the related return series y = diff(log(x)) and a POSIXlt date-time variable dp. I would like to apply annual blocks to compute for example annual block maxima and mean of y. When studying the POSIX classes, in the first stage of the learning curve, I computed the maximum drawdown of x: > mdd <- maxdrawdown(x) > max.dd <- mdd$maxdrawdown > from

Hello world, I am actually transferring a course in data management for students in biology, geography and agriculture from statistica to R - it works surprisingly well. If anyone is interested in my scratch/notepad (in German language), please see www.hydrology.uni-kiel.de/~schorsch/statistik/statistik_datenauswertung.pdf (pages 40-52) The dataset is:

Greetings, I am attempting to build a R package, however the build fails and the following message is ouput: C:\ConstellaGroup\EPA\RAGG\package>R CMD BUILD --binary --force RAGG * checking for file 'RAGG/DESCRIPTION' ... OK * preparing 'RAGG': * checking DESCRIPTION meta-information ... ERROR Error in if (regexpr(dep_regexp, dep) == -1) { : missing value where

hi everyone! hope you can help me here. i am a new R user. what i am trying to do is to find the maximum annual discharge from a daily record. i have a data.frame which includes date and the discharge. somewhat like this.. 10/1/1989 2410 10/2/1989 2460 10/3/1989 2890 ... ... ... 12/31/2005 5730 i have been browsing through the archives and fount out about the aggregate

Folks, This question is somewhat related to a previous posting of mine. I just can't seem to create a generic solution. Here is a function that I found searching around the internet: splitIt <- function(x, n) {split(x, sort(rank(x) %% n))} I use it like so: > splitIt(1:12, 2) $`0` [1] 1 2 3 4 5 6 $`1` [1] 7 8 9 10 11 12 Or > splitIt(1:12, 4) $`0` [1] 1 2 3 $`1` [1] 4 5 6

Hi, I was wondering if there is a package I can use to convert my 22 annual observations to quarterly time series so that I will have 88 observations. Also, will there be any harm in doing so? will I loose any important data specific info? I want to run VARs in levels using TY method. Due to small sample, i will probably use a bootstrap method. Thanks! [[alternative HTML version deleted]]

Hello, I'm trying currently using barplot to summarize precipitation data. So far I've compiled total annual snow and rain accumulation in a table (attached). I've been successful at plotting it using the following code: fig=barplot(t(Annual_Precip_table), horiz=TRUE, space=0, col=c("grey70", "white"), axes=FALSE) . . The result is a stacked barplot with total

...quot;, "sum.vs.win") ) plot(df) Luego he arreglado el gráfico usando: df <- ggpredict(m.glob.pre.anu , terms = c("pre", "area_m2", "sum.vs.win") ) plot(df)+ labs(title = "Predicted number of annuals" # falla al posar 4 terms en el df ,x = "MAP" ,y = "Proportion of annuals" ) + scale_x_continuous(breaks = c(-2,0,2) , labels= etiquetas ) + labs(color="Area") Pero me inter...

dear kind helper, i would like to know how to find the annual maximun for a table that basicly looks like this: date time measurement1 measurement2 measurement3 mm/dd/yyyy hh:mm:ss m1 m2 m3 there are about 9000 measurements for each year, which makes it quite large... i already tried to subset all rows for a year, to find the maximum within these choosen rows, y <-

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I have a button option in my form with 2 options. User may only select one of the options. Based on the option they choose I want an associated select list to appear. I''m guessing this can only be done with javascript or can it be done with just Ruby ? TIA Stuart --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google

I have been using browsercam.com for CSS testing, but it is rather expensive. Recently, I discovered others using funadable.org to purchase a yearly membership as a group. A year long membership at browsercam.com costs $480.00. This gives us 25 user accounts. I am proposing that 25 people throw in $19.20 for their 1/25th share of the membership cost. Once I have raised $479.40 I will

Hi all, Could anybody please help me understand AIC and BIC and especially why do they make sense? Furthermore, I am trying to devise a new metric related to the model selection in the financial asset management industry. As you know the industry uses Sharpe Ratio as the main performance benchmark, which is the annualized mean of returns divided by the annualized standard deviation of returns.

dear r-helpers i've got a table that in extracts looks like this: V1 V2 V3 V4 V5 1 01/01/1975 00:00:00 125.837 3.691 296.618 2 01/01/1975 01:00:00 124.799 3.679 281.307 3 01/01/1975 02:00:00 111.607 3.536 281.307 4 02/24/1976 11:00:00 21.602 2.555 93.893 5 02/24/1976 12:00:00 27.804 2.623 93.893 6 02/24/1976 13:00:00 26.105 2.604 114.716 7 10/18/1977

Second Annual LLVM Developers' Meeting August 1, 2008 - Apple Inc. Campus, Cupertino, California, U.S.A. The second annual LLVM Developers' Meeting will be held this year at Apple Inc.'s main campus in Cupertino, California: http://llvm.org/devmtg Like last year's inaugural meeting, the meeting serves as a forum for both LLVM developers and users to get acquainted, to