Displaying 20 results from an estimated 208 matches for "95110".
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5110
2010 Oct 07
3
reshape from wide to long, ordering of "varying"
...57.86592 9.755003
4.343534 4.280714
93610 93 1 53.36475 39.47247 4.381618
1.622119 1.159044
94110 94 0 23.47514 58.23936 10.789339
3.690415 3.805741
94610 94 1 53.34524 39.32675 4.602774
1.520247 1.204988
95110 95 0 23.76256 58.18757 9.583178
4.186825 4.279866
95610 95 1 53.14037 39.55376 4.313944
1.632805 1.359124
and want to get it in the form:
age sex cat Int.Prev.Est
93 0 1 23.75482
93 0 2 57.86592
93 0 3 9.755003
93 0...
2005 Aug 12
3
General expression of a unitary matrix
Hi, all,
Does anybody got the most general expression of a unitary matrix?
I found one in the book, four entries of the matrix are:
(cos\theta) exp(j\alpha); -(sin\theta)exp(j(\alpha-\Omega));
(sin\theta)exp(j(\beta+\Omega)); (cos\theta) exp(j\beta);
where "j" is for complex.
However, since for any two unitary matrices, their product should also
be a unitary matrix. When I
2005 Aug 17
2
power of a matrix
Dear all,
I have a population with three age-classes, at time t=0 the population
is:
n.zero <- c(1,0,0)
I have a transition matrix A which denotes "fertility" and "survival":
A <- matrix(c(0,1,5, 0.3,0,0, 0,0.5,0), ncol=3, byrow=TRUE)
To obtain the population at t=1, I calculate:
A %*% n.zero
To obtain the population t=2, I calculate:
A %*% (A %*% n.zero)
... and so
2009 May 05
1
cannot delete non-empty directory
...I searched the bugs and new and didn't see anything regarding this. It
appears to me to be a bug, can anyone confirm?
--
-------------------------------------
Scott Machtmes, Sr. Systems Administrator
Engineering Lab Services Infrastructure Lead
Brocade
1745 Technology Drive
San Jose, Ca. 95110
408-333-7203
scottm@brocade.com
2005 Jun 28
2
the function of mle
Hi,
I am a user of R computer language.Several days ago,I download R-2.1.0.From
the help manual,I saw there is a function "mle" to find the maximum
likelihood estimators.But when I try to use this function,there is no this
function.Could you help me to solve this problem?
I am looking forward to your answer.
Thank you.
Jun Liu
2005 Oct 07
3
panel data unit root tests
Hi,
The question is as follows: has anyone coded panel data unit root tests
with R? Even the "first generation" tests (see e.g. Levin & Lin 1993;
Pesaran, & Smith & Im 1996; Maddala & Wu 1999) would be sufficient for my
needs. To my understanding, these are rather easy to code, but as I have
taken just my first steps in coding with R, existing code would save me
2005 Dec 16
3
partially linear models
Hey,
I am estiamting a partially linear model y=X\beta+f(\theta) where the f(\theta) is estiamted using wavelets.
Has anyone heard of methods to test if the betas are significant or to address model fit?
Thanks for any thoughts or comments.
Elizabeth Lawson
__________________________________________________
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2005 Sep 26
2
quasi-random vector according to an independent graph
Dear R-users,
Is anyone aware of any function/package for generating a random vector from
a joint distribution defined by an independent graph? Or I have to work it
out myself?
Thanks.
Jinfang
------------------------------
Jinfang Wang, Associate Professor
Chiba University, Japan
2005 Jul 14
2
Variance components from lm?
I often use simple nested random-effect models for interlaboratory data.
The variance components are important things to know.
Is there an R function or package that gets variance components from lm
objects? Or can someone point me to a method of doing so?
2005 Nov 23
1
qbinom returns NaN
...the .Internal qbinom code. However, that's beyond my current R
skill level.
Thanks for all your efforts to make R what it is today.
Best Wishes,
spencer graves
--
Spencer Graves, PhD
Senior Development Engineer
PDF Solutions, Inc.
333 West San Carlos Street Suite 700
San Jose, CA 95110, USA
spencer.graves at pdf.com
www.pdf.com <http://www.pdf.com>
Tel: 408-938-4420
Fax: 408-280-7915
2005 Jul 06
2
Plotting confidence intervals for lme
Hello and sorry to disturb.
I'm trying to plot the confidence intervals for the fixed effects of a lme.
I want to obtain graphically, if it is possible, a bar with Estimate, upper
and lower CI for each level of the factors.
I know how to do for a lm model but for a lme one, I tried with
plot(intervals(...)) and plot(ci(...)) from the gmodels package but it
doesn't work well.
Thanks
2005 Nov 11
3
no package 'Matrix' at the repositories
...ckage 'Matrix' required by 'lme4' could not be found
What do you suggest?
Spencer Graves
p.s. I get the same result using several different (US) mirrors.
--
Spencer Graves, PhD
Senior Development Engineer
PDF Solutions, Inc.
333 West San Carlos Street Suite 700
San Jose, CA 95110, USA
spencer.graves at pdf.com
www.pdf.com <http://www.pdf.com>
Tel: 408-938-4420
Fax: 408-280-7915
2005 Aug 04
1
Counterintuitive Simulation Results
...)
}
Qp.mean
}
set.seed(1)
plot(simCus5(Qp0=4.5))
#################################################
Thanks for your time in reading this.
Best Wishes,
Spencer Graves
Spencer Graves, PhD
Senior Development Engineer
PDF Solutions, Inc.
333 West San Carlos Street Suite 700
San Jose, CA 95110, USA
spencer.graves at pdf.com
www.pdf.com <http://www.pdf.com>
Tel: 408-938-4420
Fax: 408-280-7915
2005 Nov 03
4
nlme questions
Dear R users;
Ive got two questions concerning nlme library 3.1-65 (running on R 2.2.0 /
Win XP Pro). The first one is related to augPred function. Ive been working
with a nonlinear mixed model with no problems so far. However, when the
parameters of the model are specified in terms of some other covariates,
say treatment (i.e. phi1~trt1+trt2, etc) the augPred function give me the
following
2005 Dec 27
3
parameterization of factor in R
Hi all,
I encountered this problem with parameterization in R:
I have two factors in a regression. how about if I want to
set constraint so that for each factor, the sum of their
coefficients equals to zero(instead of choosing a reference
category)? for example, I have factor(variable) A(with three
categories) and factor(variable) B(with 4 categories), and I want
to parameterize so that the sum
2005 Jun 26
1
better code?
...___________________
> On the road to retirement? Check out MSN Life Events for advice on how
> to get there! http://lifeevents.msn.com/category.aspx?cid=Retirement
>
--
Spencer Graves, PhD
Senior Development Engineer
PDF Solutions, Inc.
333 West San Carlos Street Suite 700
San Jose, CA 95110, USA
spencer.graves at pdf.com
www.pdf.com <http://www.pdf.com>
Tel: 408-938-4420
Fax: 408-280-7915
2005 Oct 31
2
nlme error message
Dear Friends,
I am seeking for any help on an error message in lme
functions. I use mixed model to analyze a data with
compound symmetric correlation structure. But I get an
error message: "Error in corMatrix.corCompSymm(object) :
NA/NaN/Inf in foreign function call (arg 1)". If I change
the correlation structure to corAR1, then no error. I have
no clue how to solve this problem.
2005 Oct 03
2
"symbol print-name too long"
All,
I've coded a function and it works manually if I copy it line by line into R.
However, when I try to "load" (copy and paste) the entire function into
R, I get the following error after the listed line of code:
+ N.j.list = lapply(rej.hyp, length)
Error: symbol print-name too long
Does anyone you know what this error means? Strangely, when I copy the
same line verbatim
2005 Nov 03
1
ML optimization question--unidimensional unfolding scalin g
...ps://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide!
> http://www.R-project.org/posting-guide.html
>
> --
> Spencer
> Graves, PhD
> Senior Development Engineer
> PDF Solutions, Inc.
> 333 West San Carlos Street Suite 700
> San Jose, CA 95110, USA
>
> spencer.graves at pdf.com
> www.pdf.com <http://www.pdf.com>
> Tel: 408-938-4420
> Fax: 408-280-7915
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE...
2005 Jun 23
2
solving equation system
Hello,
I want to solve some two dimensional equation system with R. Some systems
are not solvable analytically.
Here is an example:
(I) 1/n*sum{from_i=1_to_n}(Xi) = ln lambda + digamma(c)
(II) mean(X) = x / lambda
I want to find lambda and c,
which R-function could do that task?
Carsten
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