search for: 90th

Hi: Summary: I am trying to determine the 90th percentile of ambulance response times for groups of data. Background: A fire chief would like to look at emergency response times at the 90th percentile for 1 kilometer grids in Cape Coral, Florida. I have mapped out ambulance response times on a GIS map. Then I superimpose a regularly-spaced gri...

I am looking to create what I would call a "simple variation" on the boxplot. What I would like to do is to be able to plot the upper and lower confidence limits as the "box" and the 10th and 90th percentile as the whiskers. What I have done is write the code to create a dataframe, the columns of which are the mean, sd, 10th percentile, 90th percentile, lower confidence limit of the mean, and upper confidence limit of the mean, the rows are the groups. I have exported this to excel and get t...

...r wider audience] The plan is two axe two old networking protocols from FreeBSD head/, meaning that FreeBSD 11.0-RELEASE, available in couple of years would be shipped without them. 1) AppleTalk Last time claimed to be supported by vendor in 2007[1]. In practice had very little use since 90th. Discontinued by major routing equipment vendors since 2009[2]. 2) IPX Last time claimed to be supported by vendor in 2007[3]. In practice had very little use since 90th. Discontinued by major routing equipment vendors since 2011[4]. Current status of these protocols in FreeBSD is &q...

...current approach of doing a binary search when the previous binary search returned 0, and times for the new approach, which directly picks the first item/child node in the leaf/node. Current approach: Count: 5013 Range: 25.000 - 497.000; Mean: 82.767; Median: 64.000; Stddev: 49.972 Percentiles: 90th: 141.000; 95th: 182.000; 99th: 287.000 25.000 - 33.930: 211 ###### 33.930 - 45.927: 277 ######## 45.927 - 62.045: 1834 ##################################################### 62.045 - 83.699: 1203 ################################### 83.699 - 112.789: 609 ##################...

Dear All, I have to get the value of say 90th percentile of precipitation time series.. The series is of daily precipitation value of 96 years, I have to to get 90the percentile value of daily precipitation each year. If you know the R code or command for this please let me know. I would appreciate your early response. Thanking you, Sincerely,...

...files each have the same title, and they are each located in a directory path that includes, as one of the folder names, the "ID". These DBF files have 2 columns of interest. One is the "run number" the other is the "statistic." I'm interested in the median and 90th percentile of the "statistic" as well as their corresponding run numbers. Ultimately, I want a table that consists of ID Run_50th Stat_50 Run_90 Stat_90 1AB 5 102010 3 144376 1AC 3 999999 6 999999999 etc. Where I currently have a dataset that ha...

...on(cond) and the interaction at each subset from 90 datasets So I perform anova 90 times using a command like below; for(i in 1:90) {results_ezANOVA = ezANOVA(data=subset(ast.ast_coef, ast.ast_coef$coef_thr==i), dv=.(ast.values), between=.(gender), wid=.(subj), within=.(cond))} But I got the last(90th) result, not all. Here are my questions. 1) Is my command correct? 2) If correct, please let me know if I can get all 90 results. 3) What kind of postHoc would be appropriate? Thank you, Jeong [[alternative HTML version deleted]]

Hi R users, I have a question about plotting. There is the dataframe below, while each row represents a record. If I want to plot on a A-B plot, i.e., x-axis represents A, while y-axis represents B values. However, I want to plot the mean value from records 1-10 as one point, while the 10th and 90th percentiles represent the error bars, such as one point in the attached example. I don't know how to do this, and then add a legend. After the above step, if I have a dataframe DF2 with the same structure but different values than DF1, how to show the point on the same figure, but use different...

Hi all, I am working with a spatial data set for which I am only interested in high concentration values ("leaks"). The low values (< 90th percentile) have already been turned into NA's, leaving me with a matrix like this: < CH4_leak lon lat CH4 1 -71.11954 42.35068 2.595834 2 -71.11954 42.35068 2.595688 3 NA NA NA 4 NA NA NA 5 NA NA...

...ration for every account (including root) for every 90 days. I understand that cronjob for root will fail when the password expires. The question is, if I setup a cronjob every 90 days to renew the root password like: echo diFficulT123 | passwd --stdin root will it work? I mean at second 1 on the 90th day, which will run first? - The cronjob to renew the password - Or the password expiration, thus preventing the cronjob from running. Pardon me if it's silly. I know it's bad to change password from script, but the root acc is not used at all and has been disabled from logon remotely. I j...

Hello, I know this has been covered on here before, but as a complete novice, I need a little more guidance. I would like to produce boxplots with the whiskers extending to the 10 and 90th percentiles. I found this code: myboxplot.stats <- function (x, coef = NULL, do.conf = TRUE, do.out = TRUE) { nna <- !is.na(x) n <- sum(nna) stats <- quantile(x, c(.1,.25,.5,.75,.9), na.rm = TRUE) iqr <- diff(stats[c(2, 4)]) out <- x < stats[1] | x > stats[5]...

...names values for the result in a separate place if that makes explaining how to get the numeric values into a dist any easier. Google, searching r-project.org, and the R Nutshell book all lead me back to dist() or daisy(). thanks -- Steven Lembark 85-09 90th St. Workhorse Computing Woodhaven, NY, 11421 lembark at wrkhors.com +1 888 359 3508

Dear helpers. I often need to make dichotomous variables out of continuous ones (yes, I realize the problems with throwing away much of the information), but I then like to check the min and max of each category. I have the following simple code to do this that cuts each variable (x1,x2,x3) at the 90th percentile, and then prints the min and max of each category: d=data.frame(x1=rnorm(100),x2=runif(100)); d=transform(d,x3=x1-x2) d[,4:6]=data.frame(sapply(d,function(v)as.numeric(v>=quantile(v,0.9)))); names(d)[4:6]=c('x1high','x2high','x3high') head(d) for (i in 1:3){pr...

...s at and around that share definition but cannot find any. Forcing the share to be browseable with "browseable = yes" does not make any difference. smbclient -L server does show all defined shares. net view \\server on a win9X box does not show all defined shares - only up until the 90th share or so. Any ideas what I might look for that could cause this behaviour ? Surely there's no limit to the number of shares in a browselist (or at least not a silly limit of 90 =) ?) version used is 1.9.18-HEAD. (Not wanting to spam the list, I did not include the used conf file(s) yet in...

...I have a question about plotting. There is the dataframe below, while each > row represents a record. If I want to plot on a A-B plot, i.e., x-axis > represents A, while y-axis represents B values. However, I want to plot the > mean value from records 1-10 as one point, while the 10th and 90th > percentiles represent the error bars, such as one point in the attached > example. I don't know how to do this, and then add a legend. > After the above step, if I have a dataframe DF2 with the same structure but > different values than DF1, how to show the point on the same figur...

...plotting. There is the dataframe below, while > each > > row represents a record. If I want to plot on a A-B plot, i.e., x-axis > > represents A, while y-axis represents B values. However, I want to plot > the > > mean value from records 1-10 as one point, while the 10th and 90th > > percentiles represent the error bars, such as one point in the attached > > example. I don't know how to do this, and then add a legend. > > After the above step, if I have a dataframe DF2 with the same structure > but > > different values than DF1, how to show th...

...4, 288, 273, 278), final.weight= c(2609.328, 2955.701, 4159.837, 4591.258, 5144.559, 2877.159, 4384.498, 3348.454, 3323.391, 2918.055)) ; "birth.vec" is in days and "final.weight" is in grams. Now, what I'm trying to do is to output smoothed curves for the 10th, 50th and 90th percentiles over completed weeks. In other words, I transform "birth.vec" into a factor vector of completed weeks with completed.weeks = as.factor(floor(my.data$birth.vec/7)) ; I use these factors to get weight quantiles by completed weeks with quan.list = tapply(my.data$final.weight...

...hod = '2-opt', rep=56 ) Error in solve_TSP(tsp, method = "2-opt", rep = 56) : unused argument(s) (rep = 56) this isn't an artifact of the debugger since I get the same result without debug() setups. -- Steven Lembark 85-09 90th St. Workhorse Computing Woodhaven, NY, 11421 lembark at wrkhors.com +1 888 359 3508

Good afternoon! I need to evaluate the goodness-of-fit (aka calibration) for survival probability estimates from a Cox model. I tried to use 'calibrate' in the Design package but I'm not sure if it should/would produce what I need (ie a chi-sq type statistic with a table of expected vs observed probabilities). Any other functions I should be aware of? Also, has anybody come across

Hi Timo, >> * LIST (\HasNoChildren) "/" "folder1" >> * LIST (\HasNoChildren) "/" "folder2" >> * LIST (\HasNoChildren) "/" {9} >> six"wafer >> . OK List completed. >> >> Note the {9} length of the following real folder name. Is this normal >> handling of special folder names ? >Yes. Well,