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...-- Felix Andrews / ??? PhD candidate, The Fenner School of Environment and Society The Australian National University (Building 48A), ACT 0200 Beijing Bag, Locked Bag 40, Kingston ACT 2604 http://www.neurofractal.org/felix/ voice:+86_1051404394 (in China) mobile:+86_13522529265 (in China) mobile:+61_410400963 (in Australia) xmpp:foolish.android at gmail.com 3358 543D AAC6 22C2 D336 80D9 360B 72DD 3E4C F5D8

Hi! R is an amazing piece of software and with so many libraries it can do almost anything... but I was very surprised that a standard "binary search" function seems not to exist. I can find other much more highly-complex search routines (optimize, uniroot, nlm) in the standard no-extra-packages-loaded version of R, but not this simple alternative. I searched and found an

...-- Felix Andrews / ??? PhD candidate, The Fenner School of Environment and Society The Australian National University (Building 48A), ACT 0200 Beijing Bag, Locked Bag 40, Kingston ACT 2604 http://www.neurofractal.org/felix/ voice:+86_1051404394 (in China) mobile:+86_13522529265 (in China) mobile:+61_410400963 (in Australia) xmpp:foolish.android at gmail.com 3358 543D AAC6 22C2 D336 80D9 360B 72DD 3E4C F5D8

Hi, I read the posts for 2 hours and ?list and tried many comninations but I haven't found the answer to this basic question. So I decided to post my question even if it is a silly one ... What is the instruction to retrieve, for example, the "D" of the first list ? Thanks in advance, Ptit Bleu. > x<-list(LETTERS[1:5], LETTERS[10:20]) > x [[1]] [1] "A"

Hello, What is the best way of solving this problem? answer <- ifelse(tf=TRUE, i * 5, previous answer) where as an initial condition tf[1] <- TRUE For example if, tf <- c(T,F,F,F,T,T,F) over i = 1 to 7 then the output of the function will be answer = 5 5 5 5 25 30 30 Thank you. Phil,

Hi. I am trying to do histograms in lattice, and I want to get both counts and percents in the same plot. To try to be clearer --- there are 3 levels to my factor; I'd like to get a 2 x 3 array of plots where the top row consist of histograms by counts and the bottom consists of (the corresponding) histograms by percent. I tried the following: # Demo. library(lattice) set.seed(42) XX <-

Hi, I was *very* surprised by this little trick for new players: mean() only considers its first argument! > mean(1,1,2) [1] 1 > mean(2,1,1) [1] 2 I found this very different behaviour to max(): > max(1,1,2) [1] 2 > max(2,1,1) [1] 2 Perhaps this is the wrong list to ask, but does anyone else think this a little on the interesting side? Is it not possible to detect a

...-- Felix Andrews / ??? PhD candidate, The Fenner School of Environment and Society The Australian National University (Building 48A), ACT 0200 Beijing Bag, Locked Bag 40, Kingston ACT 2604 http://www.neurofractal.org/felix/ voice:+86_1051404394 (in China) mobile:+86_13522529265 (in China) mobile:+61_410400963 (in Australia) xmpp:foolish.android at gmail.com 3358 543D AAC6 22C2 D336 80D9 360B 72DD 3E4C F5D8

Hi I think I have been struggling to use replace correctly, I usually work my way around this using a loop, but I think this is in fact inefficient. I have a dataset with runoff from three plots and associated rainfall. However either the datarecording was sloppy, or the rainfall very patchy. So I am trying to remove data from my dataset for which the runoff is larger than the rainfall on the

Hi- I am trying to find a way to diffuse GIS data on a European map. I have a dataset consisting of particular locations scattered across Europe, along with magnitude and value information. I can plot these as discrete points with something like the following: "geocode" is a dataframe with four columns: LAT; LONG; MAGNITUDE;VALUE. library(maps) library(mapdata)

...8) -- Felix Andrews / $B0BJ!N)(B Beijing Bag, Locked Bag 40, Kingston ACT 2604 Building 48A, Linnaeus Way, The Australian National University ACT 0200 Australia http://www.neurofractal.org/felix/ mailto:felix at nfrac.org voice:+86_1051404394 (in China) mobile:+86_13522529265 (in China) mobile:+61_410400963 (in Australia) xmpp:foolish.android at gmail.com 3358 543D AAC6 22C2 D336 80D9 360B 72DD 3E4C F5D8 [[alternative HTML version deleted]]

Dear R users, I have the following two problems, related to the function sub, grep, regexpr and similia. The header of the file(s) I have to import is like this. c("y (m)", "BD (g/cm3)", "PR (Mpa)", "Ks (m/s)", "SP g./g.", "P (m3/m3)", "theta1 (g/g)", "theta2 (g/g)", "AWC (g/g)") To get rid of spaces and

...chment Assessment and Management Centre The Fenner School of Environment and Society The Australian National University (Building 48A), ACT 0200 Beijing Bag, Locked Bag 40, Kingston ACT 2604 http://www.neurofractal.org/felix/ voice:+86_1051404394 (in China) mobile:+86_13522529265 (in China) mobile:+61_410400963 (in Australia) xmpp:foolish.android at gmail.com 3358 543D AAC6 22C2 D336 80D9 360B 72DD 3E4C F5D8 ------------------------------ Message: 31 Date: Sun, 19 Aug 2007 23:26:20 -0400 From: Fran?ois Pinard <pinard at iro.umontreal.ca> Subject: Re: [R] how to collapse a list of 1 column matri...