Displaying 20 results from an estimated 34647 matches for "2012".
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2017 Oct 26
2
Help needed with aggregate or other solution
...ue.
My data:
structure(list(date = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L,
8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L,
5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L,
19L, 20L, 21L, 22L, 23L, 24L, 7L, 8L, 9L, 10L, 11L, 12L, 13L,
14L, 15L, 16L), .Label = c("2012-01-25 18:00:00", "2012-01-26 00:00:00",
"2012-01-26 06:00:00", "2012-01-26 12:00:00", "2012-01-26 18:00:00",
"2012-01-27 00:00:00", "2012-01-27 06:00:00", "2012-01-27 12:00:00",
"2012-01-27 18:00:00", "2012-01...
2017 Oct 26
3
Help needed with aggregate or other solution
...e now 3 date columns (it looks like 2 cols are merged into 1
col)
(2) the output rows should not have any of the basistime dates repeated
(maybe I misstated the problem); I need the max fcst value by basistime,
but also list the date value for that row; for example:
basistime fcst
1 2012-01-25 15:02:00 47.9
2 2012-01-26 15:11:00 50.4
3 2012-01-27 01:41:00 46.0
4 2012-01-27 10:15:00 47.3
5 2012-01-27 15:15:00 47.3
6 2012-01-28 14:22:00 46.2
7 2012-01-29 13:33:00 45.8
8 2012-01-30 14:11:00 44.8
9 2012-01-31 14:24:00 43.9
10 2012-02-01 14:55:00 41.1
11 2012-02-02 14:...
2017 Oct 26
0
Help needed with aggregate or other solution
...###
dta <- structure(list(date = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L,
8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L,
5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L,
19L, 20L, 21L, 22L, 23L, 24L, 7L, 8L, 9L, 10L, 11L, 12L, 13L,
14L, 15L, 16L), .Label = c("2012-01-25 18:00:00", "2012-01-26 00:00:00",
"2012-01-26 06:00:00", "2012-01-26 12:00:00", "2012-01-26 18:00:00",
"2012-01-27 00:00:00", "2012-01-27 06:00:00", "2012-01-27 12:00:00",
"2012-01-27 18:00:00", "2012-01...
2017 Oct 26
0
Help needed with aggregate or other solution
...tanding dplyr.
[1] H. Wickham, The Split-Apply-Combine Strategy for Data Analysis,
Journal of Statistical Software, vol. 40, no. 1, Apr. 2011.
[2] H. Wickham and G. Grolemund, R for Data Science. OReilly UK Ltd, 2017.
URL: https://r4ds.had.co.nz.
>
> ???????????? basistime fcst
> 1?? 2012-01-25 15:02:00 47.9
> 2?? 2012-01-26 15:11:00 50.4
> 3?? 2012-01-27 01:41:00 46.0
> 4?? 2012-01-27 10:15:00 47.3
> 5?? 2012-01-27 15:15:00 47.3
> 6?? 2012-01-28 14:22:00 46.2
> 7?? 2012-01-29 13:33:00 45.8
> 8?? 2012-01-30 14:11:00 44.8
> 9?? 2012-01-31 14:24:00 43.9
> 10...
2013 Dec 01
2
Adjunto fichero de datos (en .txt)
...Un saludo,
Carolina
------------ próxima parte ------------
Se ha borrado un adjunto en formato HTML...
URL: <https://stat.ethz.ch/pipermail/r-help-es/attachments/20131201/a60a00e3/attachment-0001.html>
------------ próxima parte ------------
fecha temp vel.vientokmh dir.viento presion
01/06/2012 0:00 16,648983 5,219999741 107,7431259 927,5014648
01/06/2012 0:10 16,09646225 6,120000601 135,4023895 927,4806519
01/06/2012 0:20 16,36221504 7,020000601 159,3079987 927,4867554
01/06/2012 0:30 16,66913986 6,120000601 128,4988861 927,4844971
01/06/2012 0:40 16,18397141 6,120000173 144,4150085 927,...
2012 Sep 05
4
Summarizing data containing data/time information (as factor)
Dear R user
I want to create a table (as below) to summarize the attached data
(Test.csv, which can be read into R by using 'read.csv(Test.csv, header=F)'
), to indicate the day that there are any data available, e.g.value=1 if
there are any data available for that day, otherwise value=0.
28/04 29/04 30/04 01/05 02/05
532703 0 1 1
2012 Sep 03
1
Time Series filter help?
...tion will return 1's until I have three 0's in a row and
it would keep producing zeros until I have three 1's in a row again.
I have tried many ways to do this but I have not found a way that seems
simple. I know I just making this more complex then needed so any help
would be great.
2012-05-07 0
2012-05-08 0
2012-05-09 0
2012-05-10 0
2012-05-11 0
2012-05-14 0
2012-05-15 0
2012-05-16 0
2012-05-17 0
2012-05-18 0
2012-05-21 0
2012-05-22 0
2012-05-23 0
2012-05-24 0
2012-05-25 0
2012-05-29 0
2012-05-30 0
2012-05-31...
2024 Jun 15
2
code for year month day hr format
Thank you Rui. I ran the following script
df1 <- read.table("solar_hour", header = TRUE)
df1$date <- as.Date(paste(df1$year, df1$hour),
format = "%Y %j",
origin = "2012-08-01-0")
df2 <- df1[c("date", "IMF", "SWS", "SSN", "Dst", "f10")]
head(df1)
#To display all the rows
print(df2).
It gave me this error message
> source ("script.R")
Error in `$<-.data.frame`(`*tmp*`, date, value =...
2024 Jun 15
1
code for year month day hr format
?s 20:00 de 15/06/2024, Jibrin Alhassan escreveu:
> I have solar-geophysical data e.g as blow:
> YEAR DOY HR IMF SW SSN Dst f10.7
> 2012 214 0 3.4 403. 132 -9 154.6
> 2012 214 1 3.7 388. 132 -10 154.6
> 2012 214 2 3.7 383. 132 -10 154.6
> 2012 214 3 3.7 391. 132 -9 154.6
> 2012 214 4 4.2 399. 132 -7 154.6
> 2012 214 5 4.1 411. 132 -6 154.6
> 2012 214 6 4.0 407. 132 -6...
2012 Dec 13
3
subsetting time series
Hello,
my series of dates look like
[1] "2012-05-30 18:30:00 UTC" "2012-05-30 19:30:00 UTC"
[3] "2012-05-30 20:30:00 UTC" "2012-05-30 21:30:00 UTC"
[5] "2012-05-30 22:30:00 UTC" "2012-05-30 23:30:00 UTC"
[7] "2012-05-31 00:30:00 UTC" "2012-05-31 01:30:00 UTC"
[9...
2024 Jun 15
2
code for year month day hr format
I have solar-geophysical data e.g as blow:
YEAR DOY HR IMF SW SSN Dst f10.7
2012 214 0 3.4 403. 132 -9 154.6
2012 214 1 3.7 388. 132 -10 154.6
2012 214 2 3.7 383. 132 -10 154.6
2012 214 3 3.7 391. 132 -9 154.6
2012 214 4 4.2 399. 132 -7 154.6
2012 214 5 4.1 411. 132 -6 154.6
2012 214 6 4.0 407. 132 -6 154.6
2012 214 7 4.2 404....
2013 Mar 29
1
Create values based on a table of conditions
...18:33:03 6
54 52 28/10/2011 15:19:47 1
55 41 28/10/2011 19:00:24 8
56 17 03/12/2011 17:38:08 2
57 17 03/12/2011 17:38:49 20
58 17 20/05/2012 19:45:17 17
59 17 20/05/2012 19:45:58 47
60 17 22/05/2012 23:12:54 1
61 17 22/05/2012 23:15:15 3
62 17 22/05/2012 23:15:40 7
63 17 22/05...
2013 Mar 17
1
How make a boxplot with Y axis in percentage
I have to make a boxplot with Years 2011 and 2012 on the x axis, and
percentage of full time students (=1) and part time students (=2) on the y
axis.
I would really appreciate if someone can help me to build a proper code.
Thanks
Larissa
Data as follow:
Year
Q1
2011
1
2011
1
2011
1
2011
1
2011
1
2011
1
2011
1
2011
1
2011
1
2...
2013 Aug 25
3
POSIXct bug for conversion of specific combinations of date and time
.... As I convert them to POSIXct format,
1300 cases (of about half a million locations) simply return NA values.
I picked up a small sample of failed cases and normal cases to demonstrate
the problem (see below). Can anyone understand what's happening
Thanks
## Data input
>date<-rep("2012/10/21", 14)
>hour<- c("00:02:38","00:11:05","00:19:33","00:28:00","00:36:27","00:44:57",
+"00:53:27","01:03:28","01:10:15","01:16:34","01:24:00","01:30:13","01:47:...
2012 Mar 30
1
Multiple line Graphs
...it has been blocked so below
is some sample data, if you would like me to e-mail it over to you then just
let me know! Many Thanks for your help in advance
PolyNam Date
Total
1 Australia_North_East_250km 2012-03-09 707304183
2 Australia_North_East_250km 2012-03-16 364042592
3 Australia_North_East_250km 2012-03-23 353652092
4 Australia_North_West_250km 2012-03-09 1332721712
5 Australia_North_West_250km 2012-03-16 103...
2012 Jul 04
1
BDC Clients Unable to update DNS (PTR/A)
Hi;
Through samba4 BDC server not update DNS record in PDC DNS server. please
see logs
04-Jul-2012 10:22:19.800 client 192.253.8.25#1081: send
04-Jul-2012 10:22:19.800 client 192.253.8.25#1081: sendto
04-Jul-2012 10:22:19.800 client 192.253.8.25#1081: senddone
04-Jul-2012 10:22:19.800 client 192.253.8.25#1081: next
04-Jul-2012 10:22:19.800 client 192.253.8.25#1081: endrequest
04-Jul-2012 10:22:1...
2012 Jul 24
3
Collapsing a vector/data-frame based on the previous values
Hello
I have a data frame like this:
dput(states)
structure(list(Date = c("24/07/2012", "25/07/2012", "26/07/2012",
"27/07/2012", "28/07/2012", "24/07/2012", "25/07/2012", "26/07/2012",
"27/07/2012", "28/07/2012"), State = c(1L, 1L, 1L, 1L, 1L, -1L,
-1L, -1L, 1L, -1L)), .Names = c("Da...
2012 Aug 08
4
Saving Splitted Series to Excel via XLConnect
Dear R Discussion List,
I would like to save my data as a xlsx file. But at first
I need to split it and then save each series into a Excel
column. Please take a look at the following code:
dados <- data.frame(matrix(c("2012-01-01","2012-02-01",
"2012-03-01","2012-04-01","2012-05-01","2012-06-01",
"2012-01-01","2012-02-01","2012-03-01","2012-04-01",
"2012-05-01","2012-06-01","2012-01-01",&q...
2012 Jul 18
2
How to have original (name) order after melt and cast command
...2817, 0.099487289, 5.550737022, 4.877620777, 5.462477493, 4.972518082, 5.01495407, 5.820459609, 5.403881954, 5.009506516,
4.807763909, 10.11885434,10.1856975,10.04976806,10.15428632, 10.20399335, 10.22966704,10.20967742,10.22927793,10.02439192)))
> dat1
date name rate
1 2012-03-30 xyz 0.065550707
2 2012-03-29 xyz 0.001825007
3 2012-03-28 xyz 0.054441969
4 2012-03-27 xyz 0.020810572
5 2012-03-26 xyz 0.073430586
6 2012-03-23 xyz 0.037299722
7 2012-03-22 xyz 0.099807733
8 2012-03-21 xyz 0.042072817
9 2012-03-20 xyz 0.099487289
10 2012-03-30 abc ...
2013 Apr 17
2
Problem with DateVisit-gives wrong year?
Hi I have the following factor of dates that I want to converted to Date class so I can extract the month
> test.date
[1] 14/05/2012 14/05/2012 14/05/2012 14/05/2012 14/05/2012 14/05/2012
[7] 14/05/2012 14/05/2012 14/05/2012 14/05/2012
201 Levels: 01/10/2012 01/11/2012 01/12/2012 02/07/2012 ... 28/09/2012
I use code below
ntest.date<-as.Date(test.date,'%d/%m/%y')
but the output has the wrong year, and the reverse or...