Displaying 1 result from an estimated 1 matches for "200203".
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20203
2007 May 10
3
Getting the last day of the month.
...nth. To get the last day of the
month, I tried
> as.Date(as.yearmon(x$Date,frac=0))
But I don't get the last day of the month here. (Tried frac=1 too.)
I then add a month to the date, substract one day from the resultant
date. But this wouldn't work for December.
> x$YearEnd
[1] 200203 200303 200403 200503 200603 200603 200312 200503 200603
200203 200303
[12] 200403 200503 200512 200612 200203 200303 200403 200503 200603
>
> x$Date <- as.Date(ISOdate(substr(x$YearEnd,1,4),
+ as.integer(substr(x$YearEnd,5,6))+1,
+ 1))-1
> x$Date
[1] "2002-03-31" "2003-...