search for: 1993

...uot;jul" "1992" [7,] "jun" "1992" [8,] "mar" "1992" [9,] "may" "1992" [10,] "nov" "1992" [11,] "oct" "1992" [12,] "sep" "1992" [13,] "apr" "1993" [14,] "aug" "1993" [15,] "dec" "1993" [16,] "feb" "1993" [17,] "jan" "1993" [18,] "jul" "1993" [19,] "jun" "1993" [20,] "mar" "1993" [21,] "...

...3 3 4 4 4 4 4 4 4 4 4 4 4 $day [1] 1 2 5 6 7 8 9 12 13 14 15 16 19 20 21 22 23 26 27 28 29 30 2 3 4 [26] 5 6 9 10 11 12 13 16 17 18 19 20 23 24 25 26 27 2 3 4 5 6 9 10 11 [51] 12 13 16 17 18 19 20 23 24 25 26 27 30 31 1 2 3 6 7 8 9 10 13 14 15 $year [1] 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 [16] 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 [31] 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 1993 So: The first day of my list of dates is Jan 2, 2003, but in the...

...uot;1992-10-27", "1992-11-01", "1992-11-15", "1992-11-18", "1992-11-20", "1992-12-04", "1992-12-07", "1992-12-13", "1992-12-18", "1992-12-22", "1992-12-26", "1992-12-28", "1993-01-02", "1993-01-05", "1993-01-11", "1993-01-19", "1993-01-21", "1993-01-30", "1993-02-02", "1993-02-09", "1993-02-13", "1993-02-19", "1993-03-02", "1993-03-06", "1993...

...uot;, "1992-10-27", "1992-11-01", "1992-11-15", "1992-11-18", "1992-11-20", "1992-12-04", "1992-12-07", "1992-12-13", "1992-12-18", "1992-12-22", "1992-12-26", "1992-12-28", "1993-01-02", "1993-01-05", "1993-01-11", "1993-01-19", "1993-01-21", "1993-01-30", "1993-02-02", "1993-02-09", "1993-02-13", "1993-02-19", "1993-03-02", "1993-03-06", "1993-03-10"...

Hi there, The following data is obtained from a long-term experiments. > mydata <- read.table(textConnection(" + y year Trt + 9.37 1993 A + 8.21 1995 A + 8.11 1999 A + 7.22 2007 A + 7.81 2010 A + 10.85 1993 B + 12.83 1995 B + 13.21 1999 B + 13.70 2007 B + 15.15 2010 B + 5.69 1993 C + 5.76 1995 C + 6.39 1999 C + 5.73 2007 C + 5.55 2010 C"), header...

...h(xValues)) # Plot the series as a line > plot(xValues,yValues,type="l"); # Sample forecast dates that start from xValue's data point > fcastDates=seq.Date(from=as.Date(xValues[length(xValues)]),length=12,by="month"); > fcastDates [1] "1992-12-31" "1993-01-31" "1993-03-03" "1993-03-31" "1993-05-01" "1993-05-31" [7] "1993-07-01" "1993-07-31" "1993-08-31" "1993-10-01" "1993-10-31" "1993-12-01" # Sample forecast (we only want the forecast point...

...h is every week. So now I have ordered observations of the daily 'risk-free rate' for one day every week. I want to expand this zoo object to give a value for every day, and to do so, copy the previous value to the next date (which is as yet not in the zoo object). For example: head(rf) 1993-01-01 1993-01-09 1993-01-16 1993-01-23 1993-01-30 1993-02-06 0.007306621 0.007659046 0.007681013 0.007817548 0.007847579 0.007867313 I want to insert values between each of the dates, and copy the previous value for those days. Any suggestions would be greatly appreciated. Thanks in anticipat...

...1990 4.530695 1911-04-02 1990 4.700596 1911-04-03 1990 4.898814 1911-04-04 1990 5.097032 1911-04-05 1991 5.295250 1911-04-06 1991 6.569508 1911-04-07 1991 5.861587 1911-04-08 1991 5.153666 1911-04-09 1992 4.445745 1911-04-10 1992 3.737824 1911-04-11 1992 3.001586 1911-04-12 1992 3.001586 1911-04-13 1993 2.350298 1911-04-14 1993 2.661784 1911-04-16 1993 3.001586 1911-04-17 1993 2.661784 1911-04-19 1994 2.661784 1911-04-28 1994 3.369705 1911-04-29 1994 3.001586 1911-05-20 1994 2.661784"),header=TRUE) aggregate(Q ~ wyr, data = Daily, which.max) # gives: # wyr Q # 1 1990 4 # 2 1991 2 # 3 199...

...till have the same problem. I know this can't be that unusual of a data manipulation and that someone has to have done similar things before. I want to go from something like this: LOCID POPULATION YEAR DBC 1 algb-1 A 1992 0.70451575 2 algb-1 A 1993 0.59506851 3 algb-1 A 1997 0.84837544 4 algb-1 A 1998 0.50283182 5 algb-1 A 2000 0.91242707 6 algb-2 A 1992 0.09747155 7 algb-2 A 1993 0.84772253 8 algb-2 A 1997 0.43974081 9 algb-2 A 1998 0.831...

cumsum() seems to be what you need. This can probably be done more elegantly, but ... out <- aggregate(Q ~ wyr, data = Daily, which.max) tbl <- table(Daily$wyr) out$Q <- out$Q + cumsum(c(0,tbl[-length(tbl)])) out ## yields wyr Q 1 1990 4 2 1991 6 3 1992 9 4 1993 15 5 1994 18 I leave the matter of Julian dates to you or others. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Tue, Jun...

...to know how to make aggregated data.frame with aggregate() tabulated. For example, I run the following command to aggregate re with respect to group1 and group2. > (aggr <- with(final, aggregate(re, group1, group2, mean))) Group.1 Group.2 x 1 1992 15 0.16392 2 1993 15 0.15467 3 1994 15 0.15456 4 1995 15 0.15391 5 1996 15 0.16511 6 1997 15 0.17368 7 1998 15 0.17955 8 1999 15 0.19805 9 2000 15 0.20546 10 1992 16 0.16237 11 1993 16 0.18359 12 1994 16 0.13811 13...

..."1991-09", "1991-11", "1991-12", "1992-01", "1992-03", "1992-04", "1992-05", "1992-06", "1992-07", "1992-08", "1992-09", "1992-10", "1992-11", "1992-12", "1993-01", "1993-02", "1993-03", "1993-04", "1993-05", "1993-07", "1993-08", "1993-09", "1993-10", "1993-12", "1994-02", "1994-03", "1994-04", "1994-05", "1994-07&qu...

Hi, I'd like to make a time series at an annual frequency. > a<-xts(x=c(2,4,5), order.by=c("1991","1992","1993")) Error in xts(x = c(2, 4, 5), order.by = c("1991", "1992", "1993")) : order.by requires an appropriate time-based object > a<-xts(x=c(2,4,5), order.by=1991:1993) Error in xts(x = c(2, 4, 5), order.by = 1991:1993) : order.by requires an appropriate time...

Full_Name: Christoph Schmutz, MeteoSchweiz, Switzerland Version: R1.7.1, R1.8.1 OS: windows2000, solaris sunOS 5.8 Submission from: (NULL) (141.249.133.6) I'm not sure if I don't get the clue, but please consider this: > strptime("19930870150","%Y%j%H%M") [1] "1993-03-28 01:50:00" > strptime("19930870250","%Y%j%H%M") [1] "1993-03-28 01:50:00" > strptime("19930870350","%Y%j%H%M") [1] "1993-03-28 03:50:00" The behaviour is the same with R1.7...

...s missing, the "%d" part of the "%m/%d/%yy" format is simply represented as "00". When I apply as.Date to the date information, the dates which don't contain exact day information are converted to "NA". Viz: > as.Date(interesting.data$date) [1] "1993-01-22" "1993-01-22" "1993-01-23" NA "1993-01-28" "1993-01-31" "1993-01-12" Is there a way of using the as.Date function when I only have partial dates (eg missing day information which is represented as "00", as above) such that th...

...h consist of 49 banks and I want the data for only 40 banks out of these 49 so can anyone help me on how to get this 40 banks data My data looks like Year Name totalliabilties assets 1990 a 90 10 1991 a 89 48 1992 a 87 34 1993 a 56 05 1990 b 90 11 1991 b 69 43 1992 b 37 34 1993 b 46 17 1990 c 55 10 1991 c 67 18 1992 c 34 24...

...s share doesn't behave like other ones here's a bit of a client log file (debug level 6) which shows that smbd/trans2.c:call_trans2qfsinfo(1356) takes just 60 seconds (and everytime it's called for that share) i really need help ! TIA, piece of log file [2003/03/06 20:07:49, 5, pid=1993, effective(10774, 10027), real(0, 0)] lib/util.c:show_msg(291) smb_bcc=5 [2003/03/06 20:07:49, 3, pid=1993, effective(10774, 10027), real(0, 0)] smbd/process.c:switch_message(685) switch message SMBtrans2 (pid 19...

I tried to compile Samba 2.0 beta with cc under SCO 3.2. I seem to be missing the inet.h and netdb.h include files. Does anyone know if they are publicly available? Steve Grose Sgrose@cmps.com Continental Managed Pharmacy Services - www.preferrx.com Voice - 216-459-2025 Ext. 208 Fax - 216-485-8615 Any opinions expressed are my own and not necessarily those of my employers.

Hi, I have got a lot of SPSS data for years 1993-2010. I load all data into lists so I can easily index the values over the years. Unfortunately loaded data occupy quite a lot of memory (10Gb) - so my question is, what's the best approach to work with big data files? Can R get a value from the file data without full loading into memory? How c...

Dear R helpers. I am new to plotting time data using R. wonder how to convert character time info into date in R. I searched over the web but did not find answer. the input character string is something like 03_1993 or 03-1993, so the precision is at month level. I tried the following but failed. #R code below. strptime(c("03_1993"),"%m_%Y") strptime(c("03-1993"),"%m-%Y") Can you someone kindly show me to do it? Many thanks in advance! -Sean [[alternative HTML ve...