Displaying 20 results from an estimated 1296 matches for "1992".
2009 Sep 11
4
Sorting
I have following object :
> date2
[,1] [,2]
[1,] "apr" "1992"
[2,] "aug" "1992"
[3,] "dec" "1992"
[4,] "feb" "1992"
[5,] "jan" "1992"
[6,] "jul" "1992"
[7,] "jun" "1992"
[8,] "mar" "1992"
[9,] "...
2009 Mar 19
1
problem with Dates
Hi all,
I am strugling with date formates and caliculating diferent operations like
different between 2 dates and
getting minimum in vector of dates
that is i m working with dates in formate "6/22/1992 12:00:00 AM"
and the vector is
[1] 6/4/1992 12:00:00 AM 2/13/1992 12:00:00 AM 6/19/1992 12:00:00 AM
[4] 2/11/1992 12:00:00 AM 6/22/1992 12:00:00 AM 10/3/1991 12:00:00 AM
[7] 5/12/1992 12:00:00 AM 7/11/1991 12:00:00 AM 2/6/1992 12:00:00 AM
[10] 10/4/1991 12:00:00 AM 1/31/199...
2006 Nov 23
1
how to loop this?
...uot;1991-11-04", "1991-11-11", "1991-11-22",
"1991-11-24", "1991-11-28", "1991-12-02", "1991-12-08", "1991-12-11",
"1991-12-17", "1991-12-21", "1991-12-26", "1991-12-30", "1992-01-05",
"1992-01-07", "1992-01-09", "1992-01-12", "1992-01-15", "1992-01-20",
"1992-01-25", "1992-02-02", "1992-02-12", "1992-02-16", "1992-02-24",
"1992-02-28", "1992...
2011 Apr 06
1
Problem to convert date to number
Hi R users,
I have a maybe small problem which I cannot solve by myself.
I want to convert
"chron" "dates" "times"
(04/30/06 11:35:00)
to a number with as.POSIXct.
The Problem is that I can't choose different timezones. I always get "CEST"
and not "UTC" what I need.
date = as.POSIXct(y,tz="UTC")
"2006-04-30 11:35:00
2012 Apr 22
10
Assignment problems
...rk I have to do, which is due in 2 days
and I am strung up with a lot of other stuff, so I was hoping someone would
take 5 mins and help me ??
Here is a part of my data.frame:
year country1 country2 contig comlang pop1 gdp1
pop2 gdp2 rta dist avgflow
1 1992 AUS AUT 0 0 17.4950008 321708.281
7.7825189 194684.078 0 15608.4 1.075999e+02
2 1992 AUS BEL 0 0 17.4950008 321708.281
10.0450001 231762.094 0 16319.2 4.767162e+02
3 1992 AUS CAN 0 1 17.4950008 321708.281
28.5195...
2006 May 03
4
Aggregate?
...n the other variables as they are in
the data set with the new summed TRIPID.
So what I have is something like this:
YEAR MONTH DAY CONTINUE SPL AREA COUNTY DEPTH
DEPUNIT GEAR GEAR2 TRAPS SOAKTIME UNITS FACTOR DISPOSIT
NUMSETS TRIPST TRIPID
1992 1 26 1 SP0073928 8
25 4 NA 1000000 NA NA
NA 161 1 NA NA
NA 0216 3399054 1992 1 26
1 SP0073928 8 25 4...
2006 May 03
4
Aggregate?
...n the other variables as they are in
the data set with the new summed TRIPID.
So what I have is something like this:
YEAR MONTH DAY CONTINUE SPL AREA COUNTY DEPTH
DEPUNIT GEAR GEAR2 TRAPS SOAKTIME UNITS FACTOR DISPOSIT
NUMSETS TRIPST TRIPID
1992 1 26 1 SP0073928 8
25 4 NA 1000000 NA NA
NA 161 1 NA NA
NA 0216 3399054 1992 1 26
1 SP0073928 8 25 4...
2006 Dec 27
5
plotting time series with zoo pckg
Hi all,
I am using the zoo package to plot time series. I have a problem with formatting the axes.
my zoo object (z) looks like the following.
c1
1992-01-10 21
1992-01-17 34
1992-01-24 33
1992-01-31 41
1992-02-07 39
1992-02-14 38
1992-02-21 37
1992-02-28 28
1992-03-06 33
1992-03-13 40
plot.zoo(z) produces a plot with the labels on the x-axis that I cannot control....
2006 Nov 22
3
dataframe manipulation
...uot;, "1991-11-04", "1991-11-11",
"1991-11-22", "1991-11-24", "1991-11-28", "1991-12-02", "1991-12-08",
"1991-12-11", "1991-12-17", "1991-12-21", "1991-12-26", "1991-12-30",
"1992-01-05", "1992-01-07", "1992-01-09", "1992-01-12", "1992-01-15",
"1992-01-20", "1992-01-25", "1992-02-02", "1992-02-12", "1992-02-16",
"1992-02-24", "1992-02-28", "1992-03-01"...
2011 Jun 22
2
strange date problem - May 3, 1992 is NA
> is.na(strptime("5/2/1992", format="%m/%d/%Y"))
[1] FALSE
> is.na(strptime("5/3/1992", format="%m/%d/%Y"))
[1] TRUE
Any idea what's going on with this? Running strptime against all dates
from around 1946, only 5/3/1992 was converted as "NA". Even stranger,
it still seem...
2017 Jun 07
4
Determining which.max() within groups
...stions appreciated:
Daily <- read.table(textConnection(" Date wyr Q
1911-04-01 1990 4.530695
1911-04-02 1990 4.700596
1911-04-03 1990 4.898814
1911-04-04 1990 5.097032
1911-04-05 1991 5.295250
1911-04-06 1991 6.569508
1911-04-07 1991 5.861587
1911-04-08 1991 5.153666
1911-04-09 1992 4.445745
1911-04-10 1992 3.737824
1911-04-11 1992 3.001586
1911-04-12 1992 3.001586
1911-04-13 1993 2.350298
1911-04-14 1993 2.661784
1911-04-16 1993 3.001586
1911-04-17 1993 2.661784
1911-04-19 1994 2.661784
1911-04-28 1994 3.369705
1911-04-29 1994 3.001586
1911-05-20 1994 2.661784"),header=T...
2008 Oct 29
1
Subsetting data in a loop
... 0 0
1991 8 6 6 0 0 0 0 0
1991 9 4 7 2 0 0 0 0
1991 9 9 8 4 0 0 0 0
1991 12 16 9 0 0 0 0 0
1992 3 18 10 1 0 0 0 0
1992 5 13 11 0 0 0 0 0
1992 7 31 12 1 0 0 0 0
1992 8 19 13 0 0 0 0 0
1992 10 14 ...
2006 May 10
3
Unique?
Hello,
I have sample data set that looks like:
YEAR MONTH DAY CONTINUE SPL TIMEFISH
TIMEUNIT AREA COUNTY DEPTH DEPUNIT GEAR TRIPID
CONVUNIT
1992 1 26 1 SP0073928 8
H 7 25 4 NA 1000000
02163399054 161
1992 1 26 1 SP0073928 8
H 7 25 4 NA 1000000
02163399054 8
1992 1 26 2 SP0004228 8
H 7 25 4 NA 1000000
02163399054 161
1992 1 26 2 SP0004228 8
H 7 25 4 NA 1000000
02163399054 8
1992 1 25 NA SP0052652 8
H 7 25 4 NA 1000000
021...
2010 Mar 19
2
Sequence of ordered variable to add as column
...w I would like to add a column containing a sequence (disregarding
ties) that represents the order of the variable
"dates" in each case of the variable "id", resulting in this dataframe:
> seq.id<-c(1,2,3,1,2)
> df$seq.id<-seq.id
id ord dates seq.id
3 a 1 1992-01-14 1
5 a 2 1992-02-01 2
4 a 3 1992-02-28 3
1 b 2 1992-02-27 1
2 b 1 1992-02-27 2
Thanks in advance,
Duarte Viana
2004 May 06
3
strptime
...quot;01/14/92", "02/28/92", "02/01/92")
> times <- c("23:03:20", "22:29:56", "01:03:30", "18:21:03", "16:56:26")
> x <- paste(dates, times)
> z <- strptime(x, "%m/%d/%y %H:%M:%S")
> z
[1] "1992-02-27 23:03:20" "1992-02-27 22:29:56" "1992-01-14 01:03:30"
[4] "1992-02-28 18:21:03" "1992-02-01 16:56:26"
which I understand. But then
> length(dates)
[1] 5
> length(times)
[1] 5
> length(z)
[1] 9
>
which I don't.
It seems that le...
2009 Mar 23
1
Graphic with several curves
Hi R users,
Imagine the folowing data frame
1990 1991 1992
1 5 20 6
2 15 1 11
3 3 14 22
4 20 8 55
5 10 3 14
Is there a way to build a graphic in which:
- 1 curve represents the observation 1 during 1990 & 1992
- 1 curve represents th...
2009 Oct 23
2
extract day or month as in Splus
Dear all,
I am writing to ask for help to find R code to do the same thing as the
following Splus code:
dates <- c("02/27/1992", "02/27/1992", "01/14/1992", "02/28/1992",
"02/01/1992")
timeDate(as.character(dates),in.format="%m/%d/%Y","%a")
[1] Thu Thu Tue Fri Sat
Could anyone give me some R codes to get the same results as above(extract
days from dates...
2006 Nov 26
1
adding elemens to a list
..."1990-05", "1990-06",
"1990-07", "1990-08", "1990-10", "1990-11", "1991-01", "1991-03",
"1991-04", "1991-05", "1991-06", "1991-09", "1991-11", "1991-12",
"1992-01", "1992-03", "1992-04", "1992-05", "1992-06", "1992-07",
"1992-08", "1992-09", "1992-10", "1992-11", "1992-12", "1993-01",
"1993-02", "1993-03", "1993-04&qu...
2005 Oct 13
1
subsetting data frame using by() or tapply() or other
...a.frame.list()
in front of tapply() and still have the same problem. I know this can't
be that unusual of a data manipulation and that someone has to have done
similar things before.
I want to go from something like this:
LOCID POPULATION YEAR DBC
1 algb-1 A 1992 0.70451575
2 algb-1 A 1993 0.59506851
3 algb-1 A 1997 0.84837544
4 algb-1 A 1998 0.50283182
5 algb-1 A 2000 0.91242707
6 algb-2 A 1992 0.09747155
7 algb-2 A 1993 0.84772253
8 algb-2 A 1997 0.439...
2017 Jun 07
0
Determining which.max() within groups
cumsum() seems to be what you need.
This can probably be done more elegantly, but ...
out <- aggregate(Q ~ wyr, data = Daily, which.max)
tbl <- table(Daily$wyr)
out$Q <- out$Q + cumsum(c(0,tbl[-length(tbl)]))
out
## yields
wyr Q
1 1990 4
2 1991 6
3 1992 9
4 1993 15
5 1994 18
I leave the matter of Julian dates to you or others.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
O...