search for: 1981

I wonder if this is an intentional feature or an oversight. in some column summaries or in ifelse operations, apparently I am losing the date property of my vector. > a <- c(198012, 198101, 198102) > b <- a*100+31 > c <- as.Date( as.character(b), "%Y%m%d" ) > summary(c) Min. 1st Qu. Median Mean 3rd Qu. Max. "1980-12-31" "1981-01-07" "1981-01-15" "1981-01-15" "1981-01-23&qu...

...54 foo <- sin((2 * pi * 1/24) * 1:nPts) foo <- foo + rnorm(nPts, 0, 0.05) bar <- ts(foo, start = c(1980,3), frequency = 24) plot(bar) start(bar) end(bar) # I want to find the peak value from each year, and then get the mean of the values on either side. # So, if the peak value in the year 1981 is max.in.1981 <- max(window(bar, start = c(1981,1), end = c(1981,24))) # e.g, cycle 7 or 8 window(bar, start = c(1981,1), end = c(1981,24)) == max.in.1981 # E.g. if the highest value in 1981 is in cycle 8 I want mean.in.1981 <- mean(window(bar, start = c(1981,5), end = c(1981,11))) plot(bar)...

...hivo madre lo relleno con el valor del mismo caso que lo tengo en el archivo hijos. El comando merge no me permite hacer lo anterior. ¿Hay alguno más avanzado? El archivo madre es mas corto que cualquiera de los archivos hijos. Un extracto del archivo madre: Dia Mes Año Nombre Apellido Clase 1 1981 Juan Perez A 2 2 1981 Maria Paz B 2 Pedro García B 3 3 1981 José Lugano C 1 1 1982 José Lugano C Un extracto de un archivo hijo: Dia Mes Año Nombre Apellido Clase 1 1 1981 Juan Perez A 3 2 1981 Maria Paz B 1 2 1982 Pedro García B 1 1 1983 José Lugano C 1 2 1984 Juan Paz B 2 2 1985 Maria García...

...annot open the connection In addition: Warning message: In file(file, ifelse(append, "a", "w")) : cannot open file 'c:/data1.csv': Permission denied where dataa is a zoo object > head(dataa) data11 data22 Nov 1980 988.25 194841 Dec 1980 942.38 205732 Jan 1981 935.90 226501 Feb 1981 968.79 227402 Mar 1981 932.77 233490 Apr 1981 906.18 233447 Can please tell me why this error is coming? I am using Windows vista [[alternative HTML version deleted]]

...ctly create a lagged value of the time-series variable? As an example, suppose I create: A <- data.frame(year=rep(c(1980:1984),3), person= factor(sort(rep(1:3,5))), wage=c(rnorm(15))) > A year person wage 1 1980 1 0.17923212 2 1981 1 0.25610292 3 1982 1 0.50833655 4 1983 1 -0.42448395 5 1984 1 0.49233532 6 1980 2 -0.49928025 7 1981 2 0.06842660 8 1982 2 0.65677575 9 1983 2 0.15947390 10 1984 2 -0.46585116 11 1980 3 -0.29052635 12 1981 3 -0...

...p' to centos-announce-request at centos.org You can reach the person managing the list at centos-announce-owner at centos.org When replying, please edit your Subject line so it is more specific than "Re: Contents of CentOS-announce digest..." Today's Topics: 1. CESA-2015:1981 Critical CentOS 7 nspr Security Update (Johnny Hughes) 2. CESA-2015:1981 Critical CentOS 7 nss-util Security Update (Johnny Hughes) 3. CESA-2015:1981 Critical CentOS 7 nss Security Update (Johnny Hughes) 4. CESA-2015:1982 Critical CentOS 7 firefox Security Update (J...

Hi there, I´m a newbie in R and I´m looking for some advice how to teste Piecewise (Broken Stick) models. I´have another simple question: how can I compute descriptive statistics for data grouped for two or more variables? See below, please. Year Site Repetition rainfall 1980 1 1 ... 1980 1 2 ... 1980 1 3 ... 1980 2

I have trouble with this: as.Date("Sep-1981", format="%b-%Y") Returns "NA" >From documentation for strftime '%b' Abbreviated month name in the current locale. (Also matches full name on input.) '%Y' Year with century. What am I doing wrong? cheers Worik [[alternative HTML vers...

https://bugzilla.mindrot.org/show_bug.cgi?id=1981 Bug #: 1981 Summary: Trying to use ssh with a missing identity file gives no warnings Classification: Unclassified Product: Portable OpenSSH Version: 5.2p1 Platform: All OS/Version: All Status: NEW...

https://bugzilla.mindrot.org/show_bug.cgi?id=1981 Damien Miller <djm at mindrot.org> changed: What |Removed |Added ---------------------------------------------------------------------------- Attachment #2136| |ok+ Flags| | --- Comment...

...a tabular form? The second question is that if I have another data sequence, how can I combine the two and see both data in a tabular form? > a2<-101:116> a2ts<-ts(a2, frequency=4, start=c(1979,1))> a2ts Qtr1 Qtr2 Qtr3 Qtr4 1979 101 102 103 104 1980 105 106 107 108 1981 109 110 111 112 1982 113 114 115 116 > Thank you, Miao [[alternative HTML version deleted]]

Greetings all, I have two questions. I have a data set that is arranged in the example below. I wish to obtain a plot of the performance of each ID over Year on v1. It's not clear how I set this up? ID Year V1 1 1980 1 1 1981 2 1 1982 6 1 1983 4 2 1980 5 2 1981 5 2 1982 5 2 1983 6 Also,I would like to transpose the data to have the variable across the columns such as ID v1980 v1981 v1982 v1983 1 1 2 6 4 2 5 5 5 6 Is there a straightforward...

Hello, I have a data set with 10 countries, 10 sectors of public policy and 15 years like country sector year a aa 1980 a aa 1981 ... a bb 1980 a bb 1981 ... b aa 1980 b aa 1981 ... b bb 1980 b bb 1981 .... with 1500 observations. My cases are the couple country/sector. So, I want to have 100 cases over 15 years. (both country and sector are factors) I want to assign to each case a label (e.i. country 'a' + sector...

Hi people, I need reorganization several databases. I would like to know if that is possible in R. My problem is like that: original data base: Age x1980 x1981 1 5 8 3 7 9 5 9 15 7 11 20 future data base year age x 1980 1 5 1980 3 7 1980 5 9 1980 7 11 1981 1 8 1981 3 9 1981 5 15 1981 7 20 Thanks in advance Bernardo Rangel Tur...

...hape/reshape2 to get from: 1957 0.862500000 1958 0.750000000 1959 0.300000000 1960 0.287500000 1963 0.675000000 1964 0.937500000 1965 0.025000000 1966 0.387500000 1969 0.087500000 1970 0.275000000 1973 0.500000000 1974 0.362500000 1976 0.925000000 1978 0.712500000 1979 0.337500000 1980 0.700000000 1981 0.425000000 1982 0.212500000 1983 0.312500000 1986 0.237500000 1958 0.643564356 1963 0.250000000 1968 0.211538462 1976 0.317307692 1981 0.673076923 1985 0.730769231 1986 0.057692308 1957 0.073394495 1966 0.742574257 1961 0.082568807 1964 0.165137615 1965 0.137614679 1959 0.128712871 1968 0.58715596...

...1976 6 7 a 1977 7 8 a 1978 8 9 a 1979 9 10 a 1980 10 11 b 1971 11 12 b 1972 12 13 b 1973 13 14 b 1974 14 15 b 1975 15 16 b 1976 16 17 b 1977 17 18 b 1978 18 19 b 1979 19 20 b 1980 20 21 b 1981 21 22 b 1982 22 23 b 1983 23 24 b 1984 24 25 b 1985 25 and I'd like to reshape it so it is like this: X.1971 X.1972 X.1973 X.1974 X.1975 X.1976 X.1977 X.1978 X.1979 X.1980 X.1981 a 1 2 3 4 5 6 7 8 9 10 NA b...

CentOS Errata and Security Advisory 2015:1981 Critical Upstream details at : https://rhn.redhat.com/errata/RHSA-2015-1981.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) x86_64: ddc6b8eb467af6527ab38d900b3a42d2818e89c7fb1e12e963d1650fc52931a8 nspr-4.10.8-2.el7_1.i686.rp...

CentOS Errata and Security Advisory 2015:1981 Critical Upstream details at : https://rhn.redhat.com/errata/RHSA-2015-1981.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) x86_64: b0fcaaf2573261e960592ca2d2283e944200e9c1c3995340a3794760d53318f5 nss-util-3.19.1-4.el7_1.i68...

CentOS Errata and Security Advisory 2015:1981 Critical Upstream details at : https://rhn.redhat.com/errata/RHSA-2015-1981.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) x86_64: c4090c4b3292ac5abf553f3ce549681f0149d3b710bc003c2c8a2cc6b6610b16 nss-3.19.1-7.el7_1.2.i686.r...

CentOS Errata and Security Advisory 2015:1981 Critical Upstream details at : https://rhn.redhat.com/errata/RHSA-2015-1981.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 2244ada80af9a50e7159f2b15d583c95d52a8fcf64bf24741a9ef43cae60ba7c nss-util-3.19.1-2.el6_7.i686....