search for: 100

Dear list, I have the following dataset and want to know how many times each value occur in each column. >data [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,] -100 -100 -100 0 0 0 0 0 0 -100 [2,] -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 [3,] -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 [4,] -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 [5,] -100 -100 -100 -100 -100 -100 -100 -100 -100 -50 [6,] -100 -100 -100 -100...

On Thu, Apr 30, 2015 at 10:23 AM, Jack Howarth < howarth.mailing.lists at gmail.com> wrote: > The current test suite status on x86_64-apple-darwin14, with the > proposed patch from > http://lists.cs.uiuc.edu/pipermail/cfe-commits/Week-of-Mon-20150427/128219.html > applied to current cfe trunk, is quite respectable.... > > Summary: > S Number of tested Open MP

...87-- --Apple-Mail-27-953181986 Content-Disposition: attachment; filename=bug.txt Content-Transfer-Encoding: quoted-printable Content-Type: text/tab-separated-values; x-mac-creator=5843454C; x-unix-mode=0644; x-mac-type=54455854; name="bug.txt" fact1 fact2 covar time delta=0D57 1 71 100 = 0=0D24 27 73 100 0=0D54 42 74 46 1=0D24 = 27 77 100 0=0D60 42 78 100 0=0D33 1 = 78 100 0=0D60 42 79 100 0=0D54 42 79 = 100 0=0D24 1 79 100 0=0D48 27 80 78 = 1=0D54 1 80 100 0=0D54 42 81 34 1=0D24 = 27 81 48 1=0D24 1 81 100 0=0D48 40 = 81 100 0=0D58 1 82 13 1=0D60 27 82 = 100 0=0D24 27 82 100 0=0D...

Does anyone understand this? I have a long vector parlist containing values of 138 parameters in 100 simulations. The factor parno is defined by trys <- 100 sim <- gl(trys,138) parno <- gl(138,1,trys*138) I want to extract and compare results for related groups of parameters but I get inconsistent results: > length(parlist[parno==37:42]) [1] 600 > length(parlist[parno==c(37,38,39...

...mp;0.532&10.8&34.4&28&32.8 2&5&0.323&0.302&0.303&0.355&6.8&41.2&33.6&39.2 2&10&0.235&0.219&0.224&0.256&6.4&56.4&47.2&51.6 2&50&0.108&0.099&0.099&0.118&6.8&99.6&94.8&97.6 2&100&0.074&0.071&0.073&0.082&3.2&100&99.2&99.2 5&2&0.316&0.303&0.307&0.334&12&40.8&33.2&38 5&5&0.201&0.197&0.203&0.215&4.4&69.2&62.4&68.4 5&10&0.147&0.14&0.142&0.156&7.2&86...

HI, T5220, S10U4 + patches mdb -k > ::memstat While above is working (takes some time, ideally ::memstat -n 4 to use 4 threads could be useful) mpstat 1 shows: CPU minf mjf xcal intr ithr csw icsw migr smtx srw syscl usr sys wt idl 48 0 0 1922112 9 0 0 8 0 0 0 15254 6 94 0 0 So about 2mln xcalls per second. Let''s check with dtrace:

...seemed to be buggy, giving lots of "STORE failed" errors, even with just one connection. Zimbra uses 500MB of memory just to start up, so it's not exactly for hosting small installations. Login+Logout ------------ Dovecot: ./imaptest - select=0 secs=10 seed=0 clients=1 Logi Logo 100% 100% 3439 6878 ./imaptest - select=0 secs=10 seed=0 clients=10 Logi Logo 100% 100% 4415 8830 Zimbra: ./imaptest - select=0 secs=10 seed=0 clients=1 Logi Logo 100% 100% 18032 36064 ./imaptest - select=0 secs=10 seed=0 clients=10 Logi Logo 100% 100% 25519 51056 Looks like Dovecot's...

...ee how much slower a SQL backend could actually be. Skip to bottom for the conclusions. Originally I ran the tests with the databases being in XFS filesystem. MySQL's performance was horrible. It went 3-7x faster with ext3. MySQL 5.0.30 backend (innodb): ./imaptest clients=1 - append=100 seed=1 secs=30 msgs=1000000 logout=0 Logi Sele Appe 100% 100% 100% 5% 1 291 303 So that's 10 messages/sec saved. Now how about with 5 concurrent clients? Logi Sele Appe 100% 100% 100% 5% 5 1259 1332 Pretty well. Then something more generic: ./imaptest c...

...550848 > 3 204.11757 14.1157322 0.0004921955 > 4 53.34271 3.6889104 0.0611254598 > 5 14.46029 NA NA > > > > Presumably, you can take it from here. > > > > ------------------------------ > > Message: 2 > Date: Fri, 10 Aug 2007 11:09:32 +0100 > From: Daniel Brewer <daniel.brewer@icr.ac.uk> > Subject: [R] Plot legend in margin > To: r-help@stat.math.ethz.ch > Message-ID: <46BC395C.3080109@icr.ac.uk> > Content-Type: text/plain; charset=ISO-8859-1 > > Hi all, > Another plotting question I am afraid. Is...

...001","Var001","Var002","Var002","Var002","Var002","Var002","Var002","Var001","Var001","Var001","Var001","Var002","Var002","Var002") Dose <- c("100","100","80","80","50","100","100","100","80","50","25","100","100","80","50","100","80","50") Response <- c("90%&quo...

...best settings. I have been told that enabling zlib compression would be good to save iops on storage. But doing the test now, I get worse results. [@test2 ~]# pr -m -t mail04-mdbox-vdb-append-64kb-6.log mail04-mdbox-vdb-append-64kb-8.log |less Logi Sele Appe Logi Sele Appe 100% 100% 100% 100% 100% 100% 1 1 6 1/ 1 1 1 6 1/ 1 0 0 9 1/ 1 0 0 8 1/ 1 0 0 7 1/ 1 0 0 8 1/ 1 0 0 10 1/ 1 0 0 9 1/ 1 0 0 7...

...ity plot. I have found the library(hdrcde) can do this work, but I do not know how to handle functions of this library when I used ggplot2 to draw the graph. Thank you in advance. The data and codes followed: # dummy data factor<-rep(c("Alice","Jone","Mike"),each=100) factor<-factor(factor) traits1<-c(rnorm(100, mean=1, sd=1), rnorm(100, mean=3, sd=3), rnorm(100, mean=6, sd=6)) traits2<-c(rnorm(100, mean=1, sd=1), rnorm(100, mean=3, sd=3), rnorm(100, mean=6, sd=6)) traits3<-c(rnorm(100, mean=1, sd=1), rnorm(100, mean=3, sd=3), rnorm(100, mean=6, sd=...

I am running centos 4.x and 5 x86_64 and using the script below and the slider bar at the bottom I cannot get fonts bigger than 50. someone else posted a followup and said he has the same issue. What can be happening here??? xlsfonts shows that bigger fonts are available. How can I get bigger fonts??? Note - I had to do a "yum install tk" also... Thanks, Jerry

...at it's a lil hard the data frame that I'm working on is as follow > donCalcara2 Id_Cara Form_C 1 743 if C325=. then C743=(C152/C103)*100| else C743=(C152/C325)*100 2 627 if C137=. Then C627=.| else do| if C109=. Then C627=(C138/S138)*(100-C137)| else C627=(C138/S138)*C109| end 3 638 C638 = C103 / S103 4 740...

...'ve checked my logs and havent found anything relevant.. but yet again maybe you could as i'm a newbie.. Registered SIP '101' at 192.168.75.192 port 22162 -- Saved useragent "X-Lite release 1014k stamp 47051" for peer 101 -- Executing [101 at spa:1] Dial("SIP/100-0967ad88", "SIP/101|15") in new stack -- Called 101 -- SIP/101-09683690 is ringing -- SIP/101-09683690 answered SIP/100-0967ad88 -- Native bridging SIP/100-0967ad88 and SIP/101-09683690 == Spawn extension (spa, 101, 1) exited non-zero on 'SIP/100-0967ad88'...

I would like to use grep and gsub to manipulate a vector to make the names used consistent, i.e. reduce a level or two. However, here is what I found when I attempted to use grep and gsub: > tmp_test<-c("House 1 Plot Plus +100","House 2 Plot Plus +100","House 3 Plot Plus -100","House 4 Plot Plus -100","House 1 Plus +100","House 2 Plus +100","House 3 Plus -100","House 4 Plus -100") > gsub(tmp_test[2], tmp_test[1], tmp_test) [1] "House 1 Pl...

..."0", "07:00:00", "0", "0", "0", "14:30:00", "0", "0", "0", "07:00:00", "0", "0", "0", "14:30:00", "0", "0", "0"), WAIT = c(100, 60, 60, 100, 60, 100, 100, 60, 100, 60, 60, 100, 100, 60, 60, 100, 60, 100, 100, 60, 60, 100, 100, 60, 60, 60, 100, 100, 100, 60, 60, 100, 60, 60, 100, 100, 60, 100, 100, 60, 60, 100, 100, 60, 60, 100, 100, 60, 100, 100, 60, 60, 60, 60, 100, 100, 100, 100, 60, 60, 100, 60, 60,...

...ity plot. I have found the library(hdrcde) can do this work, but I do not know how to handle functions of this library when I used ggplot2 to draw the graph. Thank you in advance. The data and codes followed: # dummy data factor<-rep(c("Alice","Jone","Mike"),each=100) factor<-factor(factor) traits1<-c(rnorm(100, mean=1, sd=1), rnorm(100, mean=3, sd=3), rnorm(100, mean=6, sd=6)) traits2<-c(rnorm(100, mean=1, sd=1), rnorm(100, mean=3, sd=3), rnorm(100, mean=6, sd=6)) traits3<-c(rnorm(100, mean=1, sd=1), rnorm(100, mean=3, sd=3), rnorm(100, mean=6, sd=...

Hola a todos . ¿cómo puedo ordenar los niveles de un factor? Ejemplo > x<-c("0","0-9","10-49","50-99","100-199",">200") > dosis<-factor(rep(x,10)) > dosis [1] 0 0-9 10-49 50-99 100-199 >200 0 0-9 10-49 [10] 50-99 100-199 >200 0 0-9 10-49 50-99 100-199 >200 [19] 0 0-9 10-49 50-99 100-199 >200 0...

...6, solaris2.10 status major 2 minor 10.1 year 2009 month 12 day 14 svn rev 50720 language R version.string R version 2.10.1 (2009-12-14) > packageDescription("zoo") Package: zoo Version: 1.6-2 Date: 2009-11-23 >t1 = zoo(-100, as.POSIXct("2009-12-31")+(2:10)*60*60*24) >t2 = zoo(matrix(0), index(t1)[1]-1) >colnames(t1)="test" >colnames(t2) = colnames(t1) > t1 2010-01-02 2010-01-03 2010-01-04 2010-01-05 2010-01-06 2010-01-07 2010-01-08 -100 -100 -100 -100 -1...