Displaying 20 results from an estimated 110 matches for "0.999".
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0.99
2011 Jan 27
1
Errors in Integrate
Hello,
I have written the function I would like to integrate in two ways:
denfxn <- function(yy,vv,a2,b2,mu2) {
pp <- 1-pnorm(yy/sqrt(vv))
part1 <- pp^(a2-1)
part2 <- (1-pp)^(b2-1)
part3 <- dnorm(yy,mu2,sqrt(vv))
return(part1*part2*part3) }
denfxnorg <- function(yy,vv,a2,b2,mu2) {
pp <- 1-pnorm(yy/sqrt(vv))
pp <- if (pp < .001) .001
else
2006 Oct 13
4
nontabular logistic regression
Hi. I'm attempting to fit a logistic/binomial model so I can determine
the influence of landscape on the probability that a box gets used by a
bird. I've looked at a few sources (MASS text, Dalgaard, Fox and
google) and the examples are almost always based on tabular predictor
variables. My data, however are not. I'm not sure if that is the
source of the problems or not because the
2012 Mar 01
1
Need help using Melt and cast to compute correlation for a cross tabulation
I have a data frame with a number of observed and predicted values by
classification as shown below:
Count Volume FCLASS
1 55000 60000 Grade Separated
2 43000 39000 Grade Separated
3 26000 26500 Major Arterial
4 19500 20000 Major Arterial
...
There are four classes here: Grade Separated, Major Arterial, Minor
Arterial, and Collector
I am looking
2009 Jun 16
2
Trouble with optim on a specific problem
Hello!
I am getting the following errors when running optim() [I tried optim() with
3 different methods as you can see]:
Error in optim(c(0.66, 0.999, 0.064), pe, NULL, method = "L-BFGS-B") :
objective function in optim evaluates to length 6 not 1
> out <- optim( c(0.66, 0.999, 0.064), pe, NULL, method = "Nelder-Mead")
Error in optim(c(0.66, 0.999, 0.064),
2011 May 30
1
Error in minimizing an integrand using optim
Hi,
Am not sure if my code itself is correct. Here's what am trying to do:
Minimize integration of a function of gaussian distributed variable 'x' over
the interval qnorm(0.999) to Inf by changing value of parameter 'mu'. mu is
the shift in mean of 'x'.
Code:
# x follows gaussian distribution
# fx2 to be minimized by changing values of mu
# integration to be done over
2015 Mar 13
6
[LLVMdev] On LLD performance
> I will do a run with --merge-strings. This should probably the the
> default to match other ELF linkers.
Trying --merge-strings with today's trunk I got
* comment got 77 797 bytes smaller.
* rodata got 9 394 257 bytes smaller.
Comparing with gold, comment now has the same size and rodata is 55
021 bytes bigger.
Amusingly, merging strings seems to make lld a bit faster. With
2011 Nov 04
2
Reading parameters from dataframe and loading as objects
Hi List,
I want to read several parameters from data frame and load them as object
into R session, Is there any package or function in R for this??
Here is example
param <-c("clust_num", "minsamp_size", "maxsamp_size", "min_pct", "max_pct")
value <-c(15, 20000, 200000, 0.001, .999)
data <- data.frame ( cbind(param , value))
data
2006 Feb 16
0
(m)simtest ?
Hi,.
We have 2 values (first formant F1, second formant F2) for a given
phoneme for six languages. We want to see whether the languages are
significantly different one from another for this given phoneme.
We have done a manova on our data and it works well, but we doesn't
allow us to see which pair of languages are different.
If we have only one formant for the phoneme, we would use
2010 Dec 05
1
HOW to use the survivalROC to get optimal cut-off values?
I have the same problem of a prevous request
HOW to use the survivalROC (or another library in R) to get optimal
cut-off values?
I want to use the time-dependent survivalROC package.according to
the,reference material,it only gives a set of ordered cut-off values
.eg.
--------------------------------------------------------------------------------
data(mayo)
str(mayo)
attach(mayo)
2010 Dec 05
1
HOW to use str() after the survivalROC (or another library in R) to get optimal cut-off values
I have the same problem of a previous request
HOW to use the survivalROC (or another library in R) to get optimal
cut-off values?
I want to use the time-dependent survivalROC package.according to
the,reference
material,it only gives a partial set of ordered cut-off values .eg.
--------------------------------------------------------------------------------
data(mayo)
str(mayo)
attach(mayo)
2020 Jun 16
1
Simple scan in CentOS 7
On 06/15/2020 08:58 PM, Fred Smith wrote:
> On Mon, Jun 15, 2020 at 04:28:17PM -0400, H wrote:
>> I just installed C7 on a new computer and despite Simple Scan being installed as part of C7, I have not been able to get it to recognize my Canon scanner connected to a USB port. I did have it running on another computer with C7 so there should not be any inherent issues.
>>
>> On
2011 Apr 12
1
2-parameter MLE problems
Hi all,
Sorry for the re-post, I sent my previous e-mail before it was complete. I
am trying to model seroprevalence using the differential equation: dP/dt =
beta*seronegative*.001*(seropositive)-0.35*(0.999)*(seropositive)-r*seropositive.
I would like to estimate my two parameters, beta and r, using maximum
likelihood methods. I have included my code below:
2008 Oct 23
1
distribution fitting
Dear R-help readers,
I am writing to you in order to ask you a few questions about distribution
fitting in R.
I am trying to find out whether the set of event interarrival times that I
am currently analyzing is distributed with a Gamma or General Pareto
distribution. The event arrival granularity is in minutes and interarrival
times are in seconds, so the values I have are 0, 60, 120, 180, and
2012 Mar 08
1
Doing Mathematica Quantile[] function in R
Hi all,
I am an R newbie trying to do some calculations I do in Mathematica in
R on a GNU/Linux system.
The main thing I am interested in doing is taking a 0.999 quantile on
a data set in a file who's data is normally distributed, say foo.csv.
e.g in Mathematica if I have something like this :
a=Import["foo.csv"]
b=Transpose[a][[1]]
Quantile[b,0.999]
In R I can load all the data
2020 Jun 15
4
Simple scan in CentOS 7
I just installed C7 on a new computer and despite Simple Scan being installed as part of C7, I have not been able to get it to recognize my Canon scanner connected to a USB port. I did have it running on another computer with C7 so there should not be any inherent issues.
On a lark I installed gscan2pdf and sane-backends-drivers-scanners and sane-find-scanner found it:
found USB scanner
2012 Nov 27
1
glm convergence warning
Hello,
When I run the following glm model:
modelresult=glm(CID~WS+SS+DV+DS, data=kimu, family=binomial)
I get the following warning messages:
1: glm.fit: algorithm did not converge
2: glm.fit: fitted probabilities numerically 0 or 1 occurred
What I am trying to do is model my response variable (CID: correct bird
identification) as a function of the predictor variables weather state
(WS), sea
2005 Aug 14
1
make check-all fails (PR#8063)
Full_Name: Jed Kaplan
Version: 2.1.1 Patched
OS: Fedora Core 4
Submission from: (NULL) (66.31.221.212)
Installation through "make check" succeeds. "Make check-all" fails with the
following tail message:
"
make[3]: Entering directory `/mnt/linuxApp/usr/local/R/R-patched/tests'
running code in 'p-r-random-tests.R' ...make[3]: *** [p-r-random-tests.Rout]
Error 1
2010 Mar 03
3
Notch Filter in AEC
Hi,
The notch filter in AEC is only used to remove DC signal, and the time of convergence is not important, right?
If so, I think preset value of notch_radius is too small, and it causes noticeable distortion(freq < 200hz cut).
There is a picture in attachment to show signals under different radius in time-domain.
By setting notch_radius to 0.999 for all sampling rates, I found better
2020 Jun 16
0
Simple scan in CentOS 7
On Mon, Jun 15, 2020 at 04:28:17PM -0400, H wrote:
> I just installed C7 on a new computer and despite Simple Scan being installed as part of C7, I have not been able to get it to recognize my Canon scanner connected to a USB port. I did have it running on another computer with C7 so there should not be any inherent issues.
>
> On a lark I installed gscan2pdf and
2005 Aug 17
2
Classifying values in vector
I have a vector of size 217 called "A".
the values of A are not sorted and range from 0 to 1 (normalized)
I am having difficulty writing a program to create a new vector "B" where
if A's value is 0< A <=0.333 then B is 0
if A's value is 0.333< A <=0.666 then B is 1
if A's value is 0.666< A <=1 then B is 2
so if A is
0.22
0.999
0.444
0
B would