search for: 0.9

Hello List, I have a data frame like: V130 V131 V132 V133 V134 V135 V136 1 0 0 0.9 0 0.9 0 0 2 0 0 0 0 0 0.8 3 0 0 0 0 0.9 0 0 4 0.9 0 0 0 0 0 0.9 5 0 0 0 6 0 0 0 0.9 0 0 0.9 7 0 0 0.8 0 0 0 0 8 0.9 0 0 0.9 0.8 0 9 0 0 0 0.9 0.9 0 0 10 0 0 0 0 0 0 0.9

Hello, Searching this forum has enabled me to get pretty far in what I'm trying to do. However, there is one more manipulation I would like to make and I haven't found a solution. Using the data and code below, I generate the plot produced by the last command. If possible I would like to reverse the order of the y-axis (bearing in mind horizontal=T) so that 0 is plotted at the upper

CentOS Errata and Security Advisory 2009:0104 https://rhn.redhat.com/errata/RHSA-2008-0104.html The following updated files have been uploaded and are currently syncing to the mirrors: s390: updates/s390/RPMS/seamonkey-1.0.9-0.9.el3.centos3.s390.rpm updates/s390/RPMS/seamonkey-chat-1.0.9-0.9.el3.centos3.s390.rpm updates/s390/RPMS/seamonkey-devel-1.0.9-0.9.el3.centos3.s390.rpm

Le 04/12/2018 ? 11:27, I?aki Ucar a ?crit?: > On Tue, 4 Dec 2018 at 11:12, <qweytr1 at mail.ustc.edu.cn> wrote: >> function ppois is a function calculate the CDF of Poisson distribution, it should generate a non-decreasing result, but what I got is: >> >>> any(diff(ppois(0:19,lambda=0.9))<0) >> [1] TRUE >> >> Actually, >> >>>

Folks, The contour() function wants x and y to be in increasing order. I have a situation where I have a grid in x and y, and associated z values, which looks like this: x y z [1,] 0.00 20 1.000 [2,] 0.00 30 1.000 [3,] 0.00 40 1.000 [4,] 0.00 50 1.000 [5,] 0.00 60 1.000 [6,] 0.00 70 1.000 [7,] 0.00 80 0.000 [8,] 0.00 90

Ok... here's my big problem with the nVidia drivers. Ever since I upgraded to 0.9-6 DGA mode with Starcraft has been broken!, and now with the 0.9-767 drivers Starcraft has refused to work AT ALL. If I replace the drivers back to the 0.9-5 (which are dreadfully unstable with SMP) Starcraft works fine. Any resolution, any color depth. With 0.9-6 I have to run Starcraft at 8-bit depth, else

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Dear all, I have a dataset as below: id code1 code2 p 1 4 8 0.1 1 5 7 0.9 2 1 8 0.4 2 6 2 0.2 2 4 3 0.6 3 5 6 0.7 3 7 5 0.9 I just want to rewrite it as this (vertical to horizontal): id var1 var2 var3

Is the following developed in my console output a recognized bug or am I using the cat function incorrectly? Thanks, Stan > ifelse(class(data[[n]])!="factor",{print("yes")},{print("no")}) [1] "yes" [1] "yes" > ifelse(class(data[[n]])!="factor",{cat("yes")},{cat("no")}) yesError in ans[test & !nas] <-

Dear R programmers, is there a sensible explanation for the following behaviour? The second command seems not to be interpreted correctly. > seq(0.6, 0.9, by=0.1) == 0.8 [1] FALSE FALSE TRUE FALSE > seq(0.7, 0.9, by=0.1) == 0.8 [1] FALSE FALSE FALSE > c(0.7, 0.8, 0.9) == 0.8 [1] FALSE TRUE FALSE > seq(0.9, 0.7, by=-0.1) == 0.8 [1] FALSE TRUE FALSE I am running R version 1.7.1 on

We''d like to get some feedback on RSpec 0.9 before we start pushing out releases via Rubyforge''s gem server and update the website. We have therefore made the first beta of 0.9 available - both prepackaged and tagged in subversion (see below). RSpec 0.9 introduces a new API for expectations, which essentially means that your underscores go away (there has been other discussions

function ppois is a function calculate the CDF of Poisson distribution, it should generate a non-decreasing result, but what I got is: > any(diff(ppois(0:19,lambda=0.9))<0) [1] TRUE Actually, > ppois(19,lambda=0.9)<ppois(18,lambda=0.9) [1] TRUE Which could not be TRUE. Code is tested in both R 3.5.1 and Microsoft R Open 3.5.1. _

Hi everyone, I have a question on selecting and grouping elements of a data frame. For example: A.df<- [ a c 0.9 b x 0.8 b z 0.5 c y 0.9 c x 0.7 c z 0.6] I want to create a list of a data frame that gives me the unique values of column 1 of A.df so that i can create intersects. That is: B[a]<- [ c 0.9] B[b]<- [ x 0.8

Hello all. I have two data frames. Group Start End G1 200 700 G2 500 1000 G3 2000 3000 G4 4000 6000 G5 7000 8000 and Pos C0 C1 200 0.9 0.6 500 0.8 0.8 800 0.9 0.7 1000 0.7 0.6 2000 0.6 0.4 2500 1.2 0.8

Hi, I want to perform t-test in R for each individual car. Here is what i have. Is there a way i can test each car? The original table (test.csv) Car Tester2 Tester2 Controller1 Controller2 Audi 0.56 0.9 0.5 0.9 Toyota 0.2 0.9 0.9 0.2 Honda 0.5 0.9 0.1 0.5 BMW 0.2 0.3 0.5 0.7 > cars<-read.table("c://test.csv",header=T,sep=",", + skip=2,comment.char="")

CentOS Errata and Security Advisory CESA-2008:0104 seamonkey security update for CentOS 3 x86_64: https://rhn.redhat.com/errata/RHSA-2008-0104.html The following updated file has been uploaded and is currently syncing to the mirrors: x86_64: updates/x86_64/RPMS/seamonkey-1.0.9-0.9.el3.centos3.i386.rpm updates/x86_64/RPMS/seamonkey-1.0.9-0.9.el3.centos3.x86_64.rpm

Dear R Users, Could you please help me on the following issue? I have a real large yearly data set. For each year I have 365 flow values. Some of the flow values are not known and that’s why you will see NA written in those slots. I wanted to know, is there a way that I can estimate those values? I tried approx command but it seems least helpful for the kind of issue I am up against.

Hi, all, I'd like to find one or more changepoints in a dataset eg for data like 0.9 1 0.8 0.8 0.85 0.3 0.9 0.9 0.9 1.1 0.3 is unlikely a changepoint but for data like 0.9 1 0.8 0.8 0.85 0.3 0.2 0.2 0.1 0.2 0.3 0.3 is a change point I am wondering is there any function can do changepoint analysis? Ying Fan

Hello, I need to build certain interpolation logic using R. Unfortunately, I just started using R, and I'm not familiar with lots of advanced or just convenient features of the language to make this simpler. So I struggled for few days and pretty much reduced the whole exercise to the following problem, which I cannot resolve: Assume we have a vector of some values with NA: a <- c(1,

>>>>> Serguei Sokol >>>>> on Tue, 4 Dec 2018 11:46:32 +0100 writes: > Le 04/12/2018 ? 11:27, I?aki Ucar a ?crit?: >> On Tue, 4 Dec 2018 at 11:12, <qweytr1 at mail.ustc.edu.cn> wrote: >>> function ppois is a function calculate the CDF of Poisson distribution, it should generate a non-decreasing result, but what I got is: