search for: 0.80

Dear list I'm testing a predictor and I produced nice performance plots with ROCR package utilizing the 3 standard command pred <- prediction(predictions, labels) perf <- performance(pred, measure = "tpr", x.measure = "fpr") plot(perf, col=rainbow(10)) The pred object and the perfo object are S4 with the following slots An object of class "performance"

Hi, I have a Dataframe. A B C D 0.1 0.7 0.9 0.8 0.20 0.60 0.80 0.70 0.40 0.80 0.70 0.76 I need a resultant dataframe (A-B) (C-D) -0.6 0.1 -0.40 0.1 -0.40 -0.06 Any suggestion would be of a great help Thanks Ramya -- View this message in context: http://r.789695.n4.nabble.com/Finding-a-Diff-within-a-Dataframe-columns-tp3247943p3247943.html Sent from

Hello everyone,           I have a basic question regarding logical operators. > x<-seq(-1,1,by=0.02) > x   [1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78  [13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54  [25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30  [37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16

Hi, > a <- 4 > a*0.2 [1] 0.8 ok!! Is there a method to obtain this: > a*0.2 [1] 0.80 I need to round the number also with the zero. Thanks in advance, Alfredo

Since snapshot rsync-HEAD-20090220-0710GMT.tar.gz make check is successful but sudo make check fails ------------------------------------------------------------ ----- overall results: 29 passed 3 failed 6 skipped ------------------------------------------------------------ failed FAIL batch-mode FAIL chmod-option FAIL daemon-gzip-upload

Hi Group, I posted this question on the ggplot list and was advised to try here also. The code below produces a plot as a png and pdf. The pdf looks great, and I cannot make the png look this way. I've tried various combinations of height, width, and dpi, but it has not worked out so far. Any suggestions to make the png look like the pdf? I received a response that the problem does not occur

Hello everyone, I have two data.frames that look like calib: place zoom scale left 0.65 8 left 0.80 5.6 left 1.20 3 right 0.65 8.4 right 0.80 6 right 1.20 2.9 X: ... place zoom .... ... left 0.80 .... ... left 1.20 .... ... right 0.65 .... ... NA NA .... ... right 0.8 .... ... left 1.20 .... and I want to get the corresponding values of 'scale' in a new column

Hi R-users, I have a list mylist <- list(c(0.79, 0.92, 0.91, 0.86, 0.96, 0.96, 0.95, 0.94, 0.99), c(0.28, 0.45, 0.59, 0.69, 0.80, 0.87, 0.95, 0.94, 0.98), c(0.29, 0.39, 0.59, 0.69, 0.68, 0.80, 0.93, 0.95, 0.98)) Is there a way to find the index of the list element that contains the lowest value among all the other elements? As the lowest value in each element is the first, the

Hello there, I don't know if I'm addressing my question to the right e-mail address, I hope I do. Actually I have a little problem concerning writing a code in R. I try to briefly sum up my problem. As you can see below, I created the functions "Equation1" and "Equation2" with some conditions. Equation1 <-function(x){ if

I'm getting constantly high numbers of page reclaims & involuntary context switches for dovecot/auth. page reclaims = minor faults = cpu switching back to system-mode, But why is the auth process doing that so excessively? Same for the large number of involuntary context switches... Attached is my "dovecot -n" output. Date: Sun, 07 Nov 2010 20:40:34 +0100 type real

Hi I have just posted a new release of my Prototype Window Class (http://blogus.xilinus.com/pages/javawin) Seb

# I have a dataframe in the following form: track <- c(rep('A', 3), rep('B', 4), rep('C', 4)) value <- c(0.15, 0.25, 0.35, 0.05, 0.99, 0.32, 0.13, 0.80, 0.75, 0.60, 0.44) df <- data.frame(track=factor(track), value=value) #> print(df) #track value #1 A 0.15 #2 A 0.25 #3 A 0.35 #4 B 0.05 #5 B 0.99 #6 B 0.32 #7 B 0.13

Hello, While exploring if rgl is along the lines of what I need, I checked out demo("rgl") and didn't find quite what I'm looking for, and am therefore seeking additional help/suggestions. The application is geared towards displaying a 3D rendering of a contaminant plume in the subsurface with the following highlights: Once the plume was rendered as a 3D object, a

Thanks for both the mapply and array approaches! However, although intended to generate the same result, they don't: # mapply approach n = 3 sa <- rnorm(n,0.8,0.1) so <- rnorm(n,0.5,0.1) m <- rnorm(n,1.2,0.1) mats = mapply(function(sa1, so1, m1) matrix(c(0,sa1*m1,so1,sa1),2,2,byrow=T), sa, so, m, SIMPLIFY = FALSE) print(mats) [[1]] ????????? [,1]????? [,2] [1,] 0.0000000

Short: get rid of the loops I use and optimize runtime Dear all, I want to calculate for each row the amount of the month ago. I use a matrix with 2100 rows and 22 colums (which is still a very small matrix. nrows of other matrixes can easily be more then 100000) Table before Year month quarter yearmonth Service ... Amount 2009 9 Q3 092009 A ...

Hello, I am trying to port one of my plotting S+ functions to R and I am having difficulties!!! I am including here only the troublesome code! I first produce a barplot, saving the positions of the bar's centers. par(mar = c(6.1, 5.1, 4.1, 4.1), mgp = c(3, 3.0, 0)) ticks.loc <- barplot(sum.of.weights, col = 5, xlab = "", ylab = "", axes =

If I use latex(summary(X)) where X is a data frame with four variables I get something like Rainfall Education Popden Nonwhite Min. :10.00 Min. : 9.00 Min. :1441 Min. : 0.80 1st Qu.:32.75 1st Qu.:10.40 1st Qu.:3104 1st Qu.: 4.95 Median :38.00 Median :11.05 Median :3567 Median :10.40 Mean :37.37 Mean :10.97 Mean :3866

I tried building with linux-2.6.0-test7 build dies with: make[1]: Entering directory `/home/rogelio/src/klibc-0.80/klibc' gcc -Wp,-MD,./.fork.d -march=i386 -Os -fomit-frame-pointer -malign-functions=0 -malign-jumps=0 -malign-loops=0 -nostdinc -iwithprefix include -I../klibc -I../klibc/arch/i386/include -I../klibc/include/bits32 -D__KLIBC__ -DBITSIZE=32 -I../klibc/include

Hi. I'm trying to plot two ecdf's on the same graph using two different colors. I can plot using the same color, but it doesn't work when I change colors? Any suggestions? Thanks in advance for your help. x <- c(0.80, 0.83, 1.89, 1.04, 1.45, 1.38, 1.91, 1.64, 0.73, 1.46) y <- c(1.15, 0.88, 0.90, 0.74, 1.21) plot(ecdf(x)) # it works without col='blue', but doesn't

Hello All, I am having a problem creating text for my forest plot using the "forestplot" function in the rmeta package. I think my problem is that I have too many columns of text, so I was wondering if there is a way to shrink my text or to change the default setting. Here is an example: #### forest_mean<- as.numeric(c(NA, 1.00, 2.00, NA, 0.75, 1.10)) forest_lower<-