search for: 0.79

When I add the --with-pam option in my configure command I get the following error: checking for pam_start in -lpam... no configure: error: Can't build with PAM support: libpam not found PAM is most certainly installed on the machine: ii libpam-modules 0.79-5 Pluggable Authentication Modules for PAM ii libpam-runtime 0.79-5 Runtime support

Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,

Hi list, I'd like to make a factor with seven 1s and three 2s using the factor() function. That is, 1 1 1 1 1 1 1 2 2 2 I will then bind this factor to the matrix below using cbind.data.frame(). 0.56 0.48 0.22 0.59 0.32 0.64 0.26 0.60 0.25 0.38 0.24 0.45 0.56 0.67 0.78 0.97 0.87 0.79 0.82 0.85 I am new to R and have been using various manuals and have made many attempts without

On Sat, 2004-09-11 at 12:49, Jeff Cohen wrote: > For the heck of it I tried upgrading to gcc 3.4.2 (from 3.3.3). It > didn't make a difference. So here are the failures for llvm-test. All > diffs are against the "native" output. > > ===================== MultiSource/Applications/sgefa > > cbe failed differently from jit/llc. First cbe: > > 84c84

On Sat, 11 Sep 2004 13:53:11 -0700 Reid Spencer <reid at x10sys.com> wrote: > On Sat, 2004-09-11 at 12:49, Jeff Cohen wrote: > > > > ===================== MultiSource/Applications/sgefa > > > sgefa is a known XFAIL. See the nightly test results over the last > several months. Actually, you should compare your test results with the > 1.3 release test results

I have 2 zoo objects - 1) Interest rate spread between 10-YR-US-Treasury and 2-YR-US-Treasury (object name = sprd) 2) S&P 500 index (object name = spy) > str(spy) ?zoo? series from 1976-06-01 to 2011-03-31 Data: num [1:8791] 99.8 100.2 100.1 99.2 98.6 ... Index: Class 'Date' num [1:8791] 2343 2344 2345 2346 2349 ... > str(sprd) ?zoo? series from 1976-06-01 to 2011-03-31

For the heck of it I tried upgrading to gcc 3.4.2 (from 3.3.3). It didn't make a difference. So here are the failures for llvm-test. All diffs are against the "native" output. ===================== MultiSource/Applications/sgefa cbe failed differently from jit/llc. First cbe: 84c84 < One-Norm(A) ---------- 8.879153e+02. --- > One-Norm(A) ---------- 8.879156e+02.

I've spent some time looking at klibc today, and find myself in a state of some puzzlement. The 0.79 snapshot does not build against 2.5.68; it fails almost immediately, apparently due to problems with include files. I'm hesitant to try patching anything to get it building, because I can find no sign of a CVS or BK repo that I can check against, and I don't want to replicate

Dear all Is there an easy way to display only one half (top-right or bottom-left) of a correlation matrix? > require(Hmisc) > rcorr(as.matrix(mtcars[ , 1:4])) mpg cyl disp hp mpg 1.00 -0.85 -0.85 -0.78 cyl -0.85 1.00 0.90 0.83 disp -0.85 0.90 1.00 0.79 hp -0.78 0.83 0.79 1.00 n= 32 P mpg cyl disp hp mpg 0 0 0 cyl 0 0 0 disp 0 0

On Thu, 9 Sep 2004 20:16:37 -0700 Jeff Cohen <jeffc at jolt-lang.org> wrote: > On Thu, 9 Sep 2004 08:52:10 -0700 > Jeff Cohen <jeffc at jolt-lang.org> wrote: > > > > I haven't got around to this yet but I will. The odds are good the > > > problem is in a BSD system header file so I need to capture the > > > preprocessed source. > > >

Dear R Users, Could you please help me on the following issue? I have a real large yearly data set. For each year I have 365 flow values. Some of the flow values are not known and that’s why you will see NA written in those slots. I wanted to know, is there a way that I can estimate those values? I tried approx command but it seems least helpful for the kind of issue I am up against.

Dear list, First my information: platform i386-pc-linux-gnu arch i386 os linux-gnu system i386, linux-gnu status major 2 minor 3.1 year 2006 month 06 day 01 svn rev 38247 language R version.string Version 2.3.1 (2006-06-01) Now my question: How is it possible that a command in an R script is not

I have a problem with R. I try to compute the confidence interval for my df. When I want to create the plot I have this problem: Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ. I try this code: library(dplR) df.rwi <- detrend(rwl = df, method = "Spline",nyrs=NULL) write.table(df.rwi,file="rwi.txt",quote=FALSE,row.names=TRUE)

Dear r-helpers, why do I get an output in the first iteration of the for-loop which contains the string values of the input vector, and how can I avoid that? Here's the output (only line 1 is wrong) latentVariable Indiv Group 1 rPlanning rIterat rTDD 2 rPlanning 0.79 0.84 3 rIterat 0.79 0.83 4 rTDD 0.9 0.96 5 rStandup 0.83 0.82 6

I am looking for simple introduction to cluster analysis using R, that would be understandable to a novice in statistics. Or, could someone perhaps help me understand how to proceed in my analysis? I am very new to both statistics and R, but am trying hard to avoid having to use SPSS as everyone around me... I have dataset on people presenting their opinions on different religious

Hi guys, one of the questions where you need a real human instead of a search engine, so it would be great if you could help. I have a matrix of z-scores which I would like to filter, sometimes columnwise, sometimes rowwise. Data looks like this: Allstar hsa.let.7a hsa.let.7a.1 hsa.let.7a.2 2 0.87 0.79 -0.57 1.07 3 0.67 -1.14 -0.78 -0.95 4

Here is the script I used to plot the graph indicating the text I wanted to insert. The line in the script that I have issues with is: text(-8,-8, "R^2= 0.62", r = 0.79, N = 161", cex = 2 R^2= 0.62 is not producing R squared = 0.62. Thanks. Sys.setenv( TZ="GMT" ) dt <- read.table("CLMXAPTY_sim", col.names = c("FDcli", "FDapt"))

Hi >i have this data > X [1] 5.79 1579.52 2323.70 68.85 426.07 110.29 108.29 1067.60 17.05 22.66 [11] 21.02 175.88 139.07 144.12 20.46 43.40 194.90 47.30 7.74 0.40 [21] 82.85 9.88 89.29 215.10 1.75 0.79 15.93 3.91 0.27 0.69 [31] 100.58 27.80 13.95 53.24 0.96 4.15 0.19 0.78 8.01 31.75 [41] 7.35 6.50

Hi, the command line with 'text' should be: text(-8,-8, expression(R^2 * " = 0.62, r = 0.79, N = 161"), cex = 2 ) Best, Kimmo su, 2024-02-04 kello 17:16 +0100, Jibrin Alhassan kirjoitti: > Here is the script I used to plot the graph indicating the text I > wanted to > insert. The line in the script that I have issues with is: text(-8,- > 8, > "R^2=?

Hello, I?m wondering if anyone can offer advice on the out-of-memory error I?m getting. I?m using R2.12.2 on Windows XP, Platform: i386-pc-mingw32/i386 (32-bit). I am using the quantreg package, trying to perform a quantile regression on a dataframe that has 11,254 rows and 5 columns. > object.size(subsetAudit.dat) 450832 bytes > str(subsetAudit.dat) 'data.frame': 11253 obs.