search for: 0.71

I've run into persistent problems with OpenBUGS crashing when using BRugs .53 and .71, and am hoping someone has suggestions. There is obviously something unusual going on in my environment, but I'm at a loss as to where to begin to try to solve it. In a nutshell, what happens is that, as soon as I call "modelCheck()" in BRugs, it gets an error or crashes ... but only some of

Hola a todos, quería preguntaros un medio para obtener los valores p usando lmer. He tratado con pvals.fnc, que es lo que me habían recomendado, pero por algún motivo no está ya disponible etc. Ésta es la función que tengo, pero da las "t", sin los valores p. Aunque Baayen indica que valores por encima de 2 son significativos necesito saber las p. resultado = lmer(rt_ln ~ (fre_ln *

Dear R-users, i encountered some problems when trying to adjust the line width of the axes and stripes in a plot created with ggplot2. I use the "barley" dataset of the lattice package to illustrate my problem: library(ggplot2) library(lattice) barley[["SD"]] <- 5 limits <- aes(ymax=barley$yield + barley$SD,ymin=barley$yield - barley$SD) p1 <-

I have a problem with R. I try to compute the confidence interval for my df. When I want to create the plot I have this problem: Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ. I try this code: library(dplR) df.rwi <- detrend(rwl = df, method = "Spline",nyrs=NULL) write.table(df.rwi,file="rwi.txt",quote=FALSE,row.names=TRUE)

Hola Manuel lo he tratado de hacer pero me sale Error: unexpected string constante in: "anova(a,as,test=Chisq") no tengo ni idea de por qué... Me resulta alucinante no poder contar ya con pvals.fnc. ¿Será imposible hacerse con ello? Saludos, Miguel -------------------------------------------- El vie, 13/6/14, Manuel Azcárate <mazcarategarcia en gmail.com> escribió:

--------------------------------------------------------------------- Red Hat, Inc. Red Hat Security Advisory Synopsis: Updated webalizer packages available Advisory ID: RHSA-2001:141-05 Issue date: 2001-10-24 Updated on: 2001-10-30 Product: Red Hat Powertools Keywords: webalizer cross-site scripting malicious html security update

Hi all, I've got a matrix of fractional data that is all positive and greater than zero that I would like to "loosely" classify, for lack of a better word. It looks something like this : 1.07 1.11 1.27 1.59 0.97 0.76 2.23 0.98 0.71 0.88 1.19 1.02 What I'm looking for is a way to round these numbers to the nearest 0.25, i.e. the above matrix would be

Existe discusión sobre el uso de los p-valores en modelos mixtos. Como se ha dicho antes, para mi lo más adecuado es comparar modelos mediante la función anova. Por Internet se puede encontrar un buen libro de Douglas Bates y en español, busca modelos mixtos con R de Luis Cayuela, enfocado hacia ecología, pero está muy bien El 13/06/2014 14:00, "Jorge I Velez"

Dear help-list, I would like to perform a linear regression on the log10 of the two vectors ov.mag.min and res.600nm. The slope and intercept of the regression I use to plot a wider range of ov.mag.min in a double log plot. For a linear regression on only tow points, wouldn't I expect the results for two.points.min to match pretty exactly res.600nm? It does not seem to be the case here.

Hi, i have a problem in assigning 2 conditions to grep() , my data look like this: DA 24 N7 Rad= 3.4 20 Sac= 0.93 Acc= 4.76 DA 24 N7 Rad= 3.4 14 Sac= 0.65 Acc= 3.33 DA 24 N7 Rad= 3.4 3 Sac= 0.14 Acc= 0.71 DA 24 N7 Rad= 3.4 11 Sac= 0.51 Acc= 2.62 DG 23 N7 Rad= 3.4 8 Sac= 0.37 Acc= 1.91 DG 23 N7 Rad= 3.4 5 Sac= 0.23 Acc= 1.19 DG 23 N7 Rad= 3.4 0 Sac= 0.00 Acc= 0.00 DG 23 N7 Rad= 3.4 3 Sac=

hello, i'm pete ,how can i order rows of matrix by max to min value? I have a matrix of membership degrees, with 82 (i) rows and K coloumns, K are clusters. I need first and second largest elements of the i-th row. for example 1 0.66 0.04 0.01 0.30 2 0.02 0.89 0.09 0.00 3 0.06 0.92 0.01 0.01 4 0.07 0.71 0.21 0.01 5 0.10 0.85 0.04 0.01 6 0.91 0.04 0.02 0.02 7 0.00 0.01 0.98 0.00 8 0.02

Hi All, I have a very simple question about a time series object: how to access values for a particular year and quarter (say)? Suppose, following http://www.stat.pitt.edu/stoffer/tsa2/R_time_series_quick_fix.htm I have read in data as a time series; here is how it looks. * Qtr1 Qtr2 Qtr3 Qtr4 1960 0.71 0.63 0.85 0.44 1961 0.61 0.69 0.92 0.55 . . . . .

i have combined all the variables in a matrix, and i wish to conduct a simulation row by row. But i found out the code only works for the every first row after a cycle of nine samples. But after check out the code, i don know where is my mistake... can anyone pls help .... #For gamma disribution with equal skewness 1.5 #to evaluate the same R function on many different sets of data

I am looking for simple introduction to cluster analysis using R, that would be understandable to a novice in statistics. Or, could someone perhaps help me understand how to proceed in my analysis? I am very new to both statistics and R, but am trying hard to avoid having to use SPSS as everyone around me... I have dataset on people presenting their opinions on different religious

Dear all, I would like to convert the first column of a dataframe to a date (original format: year (4 digits) and month (last 2 digits)) >str(dat_FF) 'data.frame': 1022 obs. of 4 variables: $ date : int 192607 192608 192609 192610 192611 192612 192701 192702 192703 192704 ... $ Rm.Rf: num 2.69 2.52 0 -3.06 2.42 2.66 0 4.29 0.51 0.57 ... $ SMB : num -2.49 -1.25 -1.38 -0.2 -0.34

I saw a similar question but I still don't fully understand how to implement optim. Can someone help me out with this? Thanks. Keun-Hyung > vol<-rep(c(0.03, 0.5, 2, 4, 8, 16, 32), 3) > time<-rep(c(2,4,8),each=7) > p.mated<-c(0.47, 0.48, 0.43, 0.43, 0.26, 0.23, "null", 0.68, 0.62, 0.64, 0.58, 0.53, 0.47, + 0.24, 0.8, 0.79, 0.71, 0.56, 0.74, 0.8, 0.47) >

I have 2 zoo objects - 1) Interest rate spread between 10-YR-US-Treasury and 2-YR-US-Treasury (object name = sprd) 2) S&P 500 index (object name = spy) > str(spy) ?zoo? series from 1976-06-01 to 2011-03-31 Data: num [1:8791] 99.8 100.2 100.1 99.2 98.6 ... Index: Class 'Date' num [1:8791] 2343 2344 2345 2346 2349 ... > str(sprd) ?zoo? series from 1976-06-01 to 2011-03-31

Hello, I have vector called test. And now I wish to measure the mean of the first 10 number, the second 10 numbers etc How does it work? Thanks Wim > dput (test) c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.71, 0.21875, 0,

Dear anonymous, The big mistake in the output might be obvious to you but not to others. Please make clear what the correct output should be or at least what is wrong with the current output. And please DO read the posting guide which asks you not to post in HTML. ir. Thierry Onkelinx Instituut voor natuur- en bosonderzoek / Research Institute for Nature and Forest team Biometrie &

Hi, I have the following table of odds ratios (or), lower limits(ll) and upper limits(ul), which I would like to plot as horizontal lines beginning at the lower limit, ending at the upper limits and with a dot at the odds ratio on an x-axis on a log10 scale. The y axis would be the study sites. >From what I can figure out, it looks like the plotCI function will do everything except give me an