Displaying 4 results from an estimated 4 matches for "0.6923".
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0.692
2007 Apr 06
0
translating sas proc mixed to lme()
Hi All
I am trying to translate a proc mixed into a lme() syntax. It seems that I was
able to do it for part of the model, but a few things are still different.
It is a 2-level bivariate model (some call it a pseudo-3-level model).
PROC MIXED DATA=psdata.bivar COVTEST METHOD = ml;
CLASS cluster_ID individual_id variable_id ;
MODEL y = Dp Dq / SOLUTION NOINT;
RANDOM Dp Dq / SUBJECT = cluster_ID
2009 Jul 24
1
metafor
I had found the author's (Wolfgang Viechtbauer) earlier meta-analytic code in R, MiMa, useful. so I have been exploring metafor using an example dataset from MiMa. metafor provides a lot more. However, MiMa provided parameter estimates, standard errors, z values, etc. for individual moderators in the meta-analysis, but I don't see how to obtain these from metafor. Have you any help
2013 Mar 28
0
using cvlm to do cross-validation
Hello,
I did a cross-validation using cvlm from DAAG package but wasn't sure how to assess the result. Does this result means my model is a good model?
I understand that the overall ms is the mean of sum of squares. But is 0.0987 a good number? The response (i.e. gailRel5yr) has min,1st Quantile, median, mean and 3rd Quantile, and max as follows: (0.462, 0.628, 0.806, 0.896, 1.000, 2.400) ?
2005 May 30
3
sapply following using by with a list of factors
Background:
OS: Linux Mandrake 10.1
release: R 2.0.0
editor: GNU Emacs 21.3.2
front-end: ESS 5.2.3
---------------------------------
Colleagues
I am having some trouble extracting results from the function by, used to
average variables in a data.frame first by one factor (depth) and then by a
second factor (station). The real data.frame is quite large
> dim(data.2001)
[1] 32049 11
Here is a