search for: 0.53

Displaying 20 results from an estimated 215 matches for "0.53".

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2012 Jul 30
2
distance matrix and hclustering
Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,
2013 Feb 23
2
assign index to colnames(matrix)
Hello, I’m trying to follow the syntax of a script from a journal website. In order to create a regression formula used later in the script, the regression matrix must have column names “X1”, “X2”, etc. I have tried to assign these column names to my matrix ScoutRSM.mat using a for loop, but I don’t know how to interpret the error message. Suggestions? Thanks, Paul
2017 Sep 02
6
Strange lazy evaluation of default arguments
Dear R developers, sessionInfo() below Please have a look at the following two versions of the same function: 1. Intended behavior: > Su1 = function(u=100, l=u, mu=0.53, sigma2=4.3^2) + { + print(c(u, l, mu)) # here, l is set to u?s value + u = u/sqrt(sigma2) + l = l/sqrt(sigma2) + mu = mu/sqrt(sigma2) + print(c(u, l, mu)) + } > > Su1() [1] 100.00 100.00 0.53 [1]
2017 Sep 02
2
Strange lazy evaluation of default arguments
Another way to avoid the problem is to not redefine variables that are arguments. E.g., > Su3 <- function(u=100, l=u, mu=0.53, sigma2=4.3^2, verbose) { if (verbose) { print(c(u, l, mu)) } uNormalized <- u/sqrt(sigma2) lNormalized <- l/sqrt(sigma2) muNormalized <- mu/sqrt(sigma2) c(uNormalized, lNormalized, muNormalized) } > Su3(verbose=TRUE)
2013 May 15
1
x and y lengths differ
I have a problem with R. I try to compute the confidence interval for my df. When I want to create the plot I have this problem: Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ. I try this code: library(dplR) df.rwi <- detrend(rwl = df, method = "Spline",nyrs=NULL) write.table(df.rwi,file="rwi.txt",quote=FALSE,row.names=TRUE)
2017 Sep 02
0
Strange lazy evaluation of default arguments
Dear Bill, All makes perfect sense (including the late evaluation). I actually discovered the problem by looking at old code which used your proposed solution. Still I find it strange (and, hnestly, I don?t like R?s behavior in this respect), and I am wondering why u is not being copied to L just before u is assigned a new value. Of course, this would require the R interpreter to track all these
2017 Sep 02
0
Strange lazy evaluation of default arguments
Hello, One way of preventing that is to use ?force. Just put force(l) right after the commented out print and before you change 'u'. Hope this helps, Rui Barradas Citando Matthias Gondan <matthias-gondan at gmx.de>: > Dear R developers, > > sessionInfo() below > > Please have a look at the following two versions of the same function: > > 1. Intended
2012 Apr 21
0
help with rmeta package
Dear R users, I'm trying figuring out with forest plot and rmeta. Here's my code... library(rmeta) tabletext <- structure(c("", NA, "Sex", "[F]", "[M]", NA, "Age class", "(0,60]", "(60,80]", NA, "Karnofsky class", "[70;90]",
2006 Dec 03
4
prop.trend.test issue
I have the clinical study data. Year 0 Year 3 Retinol (nmol/L) N Mean +-sd Mean +-sd Vitamin A group 73 1.89+-0.36 2.06+-0.53 Trace group 57 1.83+-0.31 1.78+-0.30 where N is the number of male for the clinical study. I want to test if the mean serum retinol has increased over 3 years among subjects in the vitamin A group. > 1.89+0.36
2006 Mar 26
4
edge and 1.8.2/1.8.4 issues
I recently upgraded to 1.8.4 to try out mongrel, and so far have been in a kind of hell where I can''t get my app working! Currently running (or trying to run): Ruby version 1.8.4 (i386-mswin32) RubyGems version 0.8.11 Rails version 1.0.0 Active Record version 1.13.2 Action Pack version 1.11.2 Action Web Service version 1.0.0 Action Mailer version 1.1.5 Active Support version
2017 Jun 12
0
plotting gamm results in lattice
Hi Maria If you have problems just start with a small model with predictions and then plot with xyplot the same applies to xyplot Try library(gamm4) spring <- dget(file = "G:/1/example.txt") str(spring) 'data.frame': 11744 obs. of 11 variables: $ WATERBODY_ID : Factor w/ 1994 levels "GB102021072830",..: 1 1 2 2 2 3 3 3 4 4 ... $ SITE_ID
2017 Sep 05
0
Strange lazy evaluation of default arguments
Mathias, If it's any comfort, I appreciated the example; 'expected' behaviour maybe, but a very nice example for staff/student training! S Ellison > -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Matthias > Gondan > Sent: 02 September 2017 18:22 > To: r-help at r-project.org > Subject: [R] Strange lazy evaluation of
2017 Jun 12
2
plotting gamm results in lattice
Dear all,? I hope that you can help me on this. I have been struggling to figure this out but I haven't found any solution. I am running a generalised mixed effect model, gamm4, for an ecology project. Below is the code for the model: model<-gamm4(LIFE.OE_spring~s(Q95, by=super.end.group)+Year+Hms_Rsctned+Hms_Poaching+X.broadleaved_woodland? ? ? ? ? ? ?+X.urban.suburban+X.CapWks,
2007 Jul 19
3
help with heatmap - how to remove annoying "X" before numeric values?
Hello All, I have a simple question based on how things are labeled on my heat map; particularly, there is this annoying "X" that appears before the numeric value of all the labels of my columns. Let's say I have the following silly data, stored in "temp.txt" 1905 1910 1950 1992 2011 2020 Gnat 0.08 0.29 0.29 0.37 0.39 0.43 Snake
2024 Nov 09
1
NUT stopped working after an upgrade
Running NUT version 2.8.2 on Fedora 40. NUT installed from the Fedora package. CyberPower CP1000AVRLCD connected by USB. I updated the system yesterday with all the latest Fedora packages. Now NUT will not run. Chasing the issue through the layers, I come to this: ===================== [root at mythtv rules.d]# upsc cyberpower Error: Driver not connected [root at mythtv rules.d]#
2010 May 30
4
Data Frame as Hash Table
I'm interested in using a data frame as if it were a hash table. For instance if I had the following, > (d <- data.frame(key=seq(0.5, 3, 0.5), value=rnorm(6))) key value 1 0.5 -1.118665122 2 1.0 0.465122921 3 1.5 -0.529239211 4 2.0 -0.147324638 5 2.5 -1.531503795 6 3.0 -0.002720434 Then I'd like to be able to quickly retrieve the "value" of "key" 1.5
2024 Nov 09
1
NUT stopped working after an upgrade
Did the upgrade by chance install/alter any udev rules causing the UPS devices to now have incorrect permissions? And what user is nut running as? On November 9, 2024 9:58:57 AM EST, Bill Gee <bgee at campercaver.net> wrote: >Running NUT version 2.8.2 on Fedora 40. NUT installed from the Fedora package. CyberPower CP1000AVRLCD connected by USB. > >I updated the system yesterday
2024 Nov 09
1
NUT stopped working after an upgrade
Nut should be running as user nut. As far as I can tell, the udev rules have not changed. And the system IS seeing the UPS at a low level. I looked through /dev/ but did not see a device that jumps out as the UPS. ===================== [root at mythtv rules.d]# dmesg | grep -i 0764 [ 2.021485] usb 1-1.8: New USB device found, idVendor=0764, idProduct=0501, bcdDevice= 0.01 [ 2.049515]
2003 Mar 03
1
using data() in an example
Hi all, I'm trying to put together examples in an R package, and am having trouble reading data from the package's data directory. The data are in comma-separated variable files, so to read a file like gw.csv, I include in the data directory both bailey.csv and a file bailey.R which contains: bailey <- read.csv("bailey.csv",na.strings="."); so that typing
2008 Jun 01
2
optim error
I saw a similar question but I still don't fully understand how to implement optim. Can someone help me out with this? Thanks. Keun-Hyung > vol<-rep(c(0.03, 0.5, 2, 4, 8, 16, 32), 3) > time<-rep(c(2,4,8),each=7) > p.mated<-c(0.47, 0.48, 0.43, 0.43, 0.26, 0.23, "null", 0.68, 0.62, 0.64, 0.58, 0.53, 0.47, + 0.24, 0.8, 0.79, 0.71, 0.56, 0.74, 0.8, 0.47) >