search for: 0.40

Displaying 20 results from an estimated 346 matches for "0.40".

Did you mean: 0.0
2011 May 05
1
matrix not positive definite (while it should be)
I do have some trouble with matrices. I want to build up a covariance matrix with a hierarchical structure). For instance, in dimension n=10, I have two subgroups (called REGION). NR=2; n=10 CORRELATION=matrix(c(0.4,-0.25, -0.25,0.3),NR,NR) REGION=sample(1:NR,size=n,replace=TRUE) R1=REGION%*%t(rep(1,n)) R2=rep(1,n)%*%t(REGION) SIGMA=matrix(NA,n,n) for(i in 1:NR){ for(j in
2007 Aug 22
5
Slow concurrent actions on the same LVM logical volume
Hi 2 all ! I have problems with concurrent filesystem actions on a ocfs2 filesystem which is mounted by 2 nodes. OS=RH5ES and OCFS2=1.2.6 F.e.: If I have a LV called testlv which is mounted on /mnt on both servers and I do a "dd if=/dev/zero of=/mnt/test.a bs=1024 count=1000000" on server 1 and do at the same time a du -hs /mnt/test.a it takes about 5 seconds for du -hs to execute: 270M
2005 Jun 17
4
3D Scatter Plot
Hello: I would like to be able to do a 3D scatter plot from 3 variables, 2 independent and 1 dependent. The closest R function I could find for this is "cloud". However cloud uses, as input, a matrix where the value of each matrix element is the dependent variable value at that matrix coordinate. My problem is that the independent variable values are floating point and can be of
2008 Oct 01
1
Please help me to produce smoothed contour plots
Please help me to produce smoothed contour plots. I have dependent data generated at regular intervals of two independent variables and would like to produce smoothed contour plots - I cannot get interp (alima) to produce cubic interpolations of the data, only linear ones. I'm interested in smoothing as the data generation process is stochastic and produces small variations which I'd
2009 Jul 23
0
CentOS-announce Digest, Vol 53, Issue 6
Send CentOS-announce mailing list submissions to centos-announce at centos.org To subscribe or unsubscribe via the World Wide Web, visit http://lists.centos.org/mailman/listinfo/centos-announce or, via email, send a message with subject or body 'help' to centos-announce-request at centos.org You can reach the person managing the list at centos-announce-owner at centos.org When
2009 Jul 22
0
CESA-2009:1163 Critical CentOS 3 x86_64 seamonkey - security update
CentOS Errata and Security Advisory CESA-2009:1163 seamonkey security update for CentOS 3 x86_64: https://rhn.redhat.com/errata/RHSA-2009-1163.html The following updated file has been uploaded and is currently syncing to the mirrors: x86_64: updates/x86_64/RPMS/seamonkey-1.0.9-0.40.el3.centos3.i386.rpm updates/x86_64/RPMS/seamonkey-1.0.9-0.40.el3.centos3.x86_64.rpm
2005 May 30
0
compiling tftp-hpa-040 under Solaris 8
Dear List, I'm trying to compile tftp-hpa-040 under Solris 8: Step 1: "configre" works fine: root at isu001[/usr/src/tftp-hpa-0.40] > ./configure checking for gcc... gcc checking for C compiler default output file name... a.out checking whether the C compiler works... yes checking whether we are cross compiling... no checking for suffix of executables... checking for
2020 Jun 30
7
[Bug 3189] New: channel mux_ctx memory leak
https://bugzilla.mindrot.org/show_bug.cgi?id=3189 Bug ID: 3189 Summary: channel mux_ctx memory leak Product: Portable OpenSSH Version: 8.3p1 Hardware: ix86 OS: Linux Status: NEW Severity: critical Priority: P5 Component: ssh Assignee: unassigned-bugs at mindrot.org
2011 Jan 31
5
Finding a Diff within a Dataframe columns
Hi, I have a Dataframe. A B C D 0.1 0.7 0.9 0.8 0.20 0.60 0.80 0.70 0.40 0.80 0.70 0.76 I need a resultant dataframe (A-B) (C-D) -0.6 0.1 -0.40 0.1 -0.40 -0.06 Any suggestion would be of a great help Thanks Ramya -- View this message in context: http://r.789695.n4.nabble.com/Finding-a-Diff-within-a-Dataframe-columns-tp3247943p3247943.html Sent from
2008 Oct 01
0
cubic bivariate interpolation on regular grid
Please help me to produce smoothed contour plots. I have dependent data generated at regular intervals of two independent variables and would like to produce smoothed contour plots - I cannot get interp (alima) to produce cubic interpolations of the data, only linear ones. I'm interested in smoothing as the data generation process is stochastic and produces small variations which I'd
2009 Jul 22
0
CESA-2009:1163 Critical CentOS 3 i386 seamonkey - security update
CentOS Errata and Security Advisory CESA-2009:1163 seamonkey security update for CentOS 3 i386: https://rhn.redhat.com/errata/RHSA-2009-1163.html The following updated file has been uploaded and is currently syncing to the mirrors: i386: updates/i386/RPMS/seamonkey-1.0.9-0.40.el3.centos3.i386.rpm updates/i386/RPMS/seamonkey-chat-1.0.9-0.40.el3.centos3.i386.rpm
2013 Mar 06
3
About basic logical operators
Hello everyone,           I have a basic question regarding logical operators. > x<-seq(-1,1,by=0.02) > x   [1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78  [13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54  [25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30  [37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16
2009 Aug 10
3
Bug in "seq" (or a "feature") ?
(I use R 2.9.1 with win XP) If I run this code: seq(-0.1,.9, by = .05)[seq(-0.1,.9, by = .05) <= 0.5] I get this output: [1] -0.10 -0.05 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 Why is 0.50 not in the results ? (It seems that it gives a slightly bigger number then 0.5 but I don't understand why it does that) Where as if I try: seq(-0.1,.9, by = .05)[seq(-0.1,.9, by = .05) <=
2016 Mar 22
0
CEBA-2016:0485 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2016:0485 Upstream details at : https://rhn.redhat.com/errata/RHBA-2016-0485.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: f43bc50d1af8b9f23f8eca5b92874105fc6ca169fd9d6887990e8a47bb5b1207 libcgroup-0.40.rc1-17.el6_7.i686.rpm
2016 Jul 12
0
CEBA-2016:1410 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2016:1410 Upstream details at : https://rhn.redhat.com/errata/RHBA-2016-1410.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: e529a006388dda6e4ce85e70623426707f033d27f868492f24cdc8a29ac47a4f libcgroup-0.40.rc1-18.el6_8.i686.rpm
2017 Oct 04
0
CEBA-2017:2854 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2017:2854 Upstream details at : https://access.redhat.com/errata/RHBA-2017:2854 The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 9b58a5eb510e3c7664ccae92a1c12c1679593efe3041f5c5d0733bbad0884949 libcgroup-0.40.rc1-24.el6_9.i686.rpm
2018 Oct 09
0
CEBA-2018:2895 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2018:2895 Upstream details at : https://access.redhat.com/errata/RHBA-2018:2895 The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 334ee6d935abe38fdd59e2d7d328190730db5c3ece3eb93c47af9665396809d5 libcgroup-0.40.rc1-27.el6_10.i686.rpm
2013 Dec 09
0
CEBA-2013:1797 CentOS 6 libcgroup Update
CentOS Errata and Bugfix Advisory 2013:1797 Upstream details at : https://rhn.redhat.com/errata/RHBA-2013-1797.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 9a39c9616d3f1fbe1676a4ca2c69bde4a350231f588524b963cea5d9675cbdf6 libcgroup-0.40.rc1-5.el6_5.1.i686.rpm
2014 Sep 30
0
CEBA-2014:1328 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2014:1328 Upstream details at : https://rhn.redhat.com/errata/RHBA-2014-1328.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 18d3cb7b351152d05f0fcb643606c89aa8afdadc2f37a2fb781bd16081e9180c libcgroup-0.40.rc1-6.el6_5.1.i686.rpm
2013 May 27
1
Question about subsetting S4 object in ROCR
Dear list I'm testing a predictor and I produced nice performance plots with ROCR package utilizing the 3 standard command pred <- prediction(predictions, labels) perf <- performance(pred, measure = "tpr", x.measure = "fpr") plot(perf, col=rainbow(10)) The pred object and the perfo object are S4 with the following slots An object of class "performance"