Displaying 20 results from an estimated 346 matches for "0.40".
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0.0
2011 May 05
1
matrix not positive definite (while it should be)
I do have some trouble with matrices. I want to build up a covariance matrix
with a hierarchical structure). For instance, in dimension n=10, I have two
subgroups (called REGION).
NR=2; n=10
CORRELATION=matrix(c(0.4,-0.25,
-0.25,0.3),NR,NR)
REGION=sample(1:NR,size=n,replace=TRUE)
R1=REGION%*%t(rep(1,n))
R2=rep(1,n)%*%t(REGION)
SIGMA=matrix(NA,n,n)
for(i in 1:NR){
for(j in
2007 Aug 22
5
Slow concurrent actions on the same LVM logical volume
Hi 2 all !
I have problems with concurrent filesystem actions on a ocfs2
filesystem which is mounted by 2 nodes. OS=RH5ES and OCFS2=1.2.6
F.e.: If I have a LV called testlv which is mounted on /mnt on both
servers and I do a "dd if=/dev/zero of=/mnt/test.a bs=1024
count=1000000" on server 1 and do at the same time a du -hs
/mnt/test.a it takes about 5 seconds for du -hs to execute:
270M
2005 Jun 17
4
3D Scatter Plot
Hello:
I would like to be able to do a 3D scatter plot from 3 variables, 2
independent and 1 dependent. The closest R function I could find for
this is "cloud". However cloud uses, as input, a matrix where the value
of each matrix element is the dependent variable value at that matrix
coordinate. My problem is that the independent variable values are
floating point and can be of
2008 Oct 01
1
Please help me to produce smoothed contour plots
Please help me to produce smoothed contour plots.
I have dependent data generated at regular intervals of two independent
variables and would like to produce smoothed contour plots - I cannot get
interp (alima) to produce cubic interpolations of the data, only linear
ones. I'm interested in smoothing as the data generation process is
stochastic and produces small variations which I'd
2009 Jul 23
0
CentOS-announce Digest, Vol 53, Issue 6
Send CentOS-announce mailing list submissions to
centos-announce at centos.org
To subscribe or unsubscribe via the World Wide Web, visit
http://lists.centos.org/mailman/listinfo/centos-announce
or, via email, send a message with subject or body 'help' to
centos-announce-request at centos.org
You can reach the person managing the list at
centos-announce-owner at centos.org
When
2009 Jul 22
0
CESA-2009:1163 Critical CentOS 3 x86_64 seamonkey - security update
CentOS Errata and Security Advisory CESA-2009:1163
seamonkey security update for CentOS 3 x86_64:
https://rhn.redhat.com/errata/RHSA-2009-1163.html
The following updated file has been uploaded and is currently syncing to
the mirrors:
x86_64:
updates/x86_64/RPMS/seamonkey-1.0.9-0.40.el3.centos3.i386.rpm
updates/x86_64/RPMS/seamonkey-1.0.9-0.40.el3.centos3.x86_64.rpm
2005 May 30
0
compiling tftp-hpa-040 under Solaris 8
Dear List,
I'm trying to compile tftp-hpa-040 under Solris 8:
Step 1: "configre" works fine:
root at isu001[/usr/src/tftp-hpa-0.40] > ./configure
checking for gcc... gcc
checking for C compiler default output file name... a.out
checking whether the C compiler works... yes
checking whether we are cross compiling... no
checking for suffix of executables...
checking for
2020 Jun 30
7
[Bug 3189] New: channel mux_ctx memory leak
https://bugzilla.mindrot.org/show_bug.cgi?id=3189
Bug ID: 3189
Summary: channel mux_ctx memory leak
Product: Portable OpenSSH
Version: 8.3p1
Hardware: ix86
OS: Linux
Status: NEW
Severity: critical
Priority: P5
Component: ssh
Assignee: unassigned-bugs at mindrot.org
2011 Jan 31
5
Finding a Diff within a Dataframe columns
Hi,
I have a Dataframe.
A B C D
0.1 0.7 0.9 0.8
0.20 0.60 0.80 0.70
0.40 0.80 0.70 0.76
I need a resultant dataframe
(A-B) (C-D)
-0.6 0.1
-0.40 0.1
-0.40 -0.06
Any suggestion would be of a great help
Thanks
Ramya
--
View this message in context: http://r.789695.n4.nabble.com/Finding-a-Diff-within-a-Dataframe-columns-tp3247943p3247943.html
Sent from
2008 Oct 01
0
cubic bivariate interpolation on regular grid
Please help me to produce smoothed contour plots.
I have dependent data generated at regular intervals of two independent
variables and would like to produce smoothed contour plots - I cannot get
interp (alima) to produce cubic interpolations of the data, only linear
ones. I'm interested in smoothing as the data generation process is
stochastic and produces small variations which I'd
2009 Jul 22
0
CESA-2009:1163 Critical CentOS 3 i386 seamonkey - security update
CentOS Errata and Security Advisory CESA-2009:1163
seamonkey security update for CentOS 3 i386:
https://rhn.redhat.com/errata/RHSA-2009-1163.html
The following updated file has been uploaded and is currently syncing to
the mirrors:
i386:
updates/i386/RPMS/seamonkey-1.0.9-0.40.el3.centos3.i386.rpm
updates/i386/RPMS/seamonkey-chat-1.0.9-0.40.el3.centos3.i386.rpm
2013 Mar 06
3
About basic logical operators
Hello everyone,
I have a basic question regarding logical operators.
> x<-seq(-1,1,by=0.02)
> x
[1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78
[13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54
[25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30
[37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16
2009 Aug 10
3
Bug in "seq" (or a "feature") ?
(I use R 2.9.1 with win XP)
If I run this code:
seq(-0.1,.9, by = .05)[seq(-0.1,.9, by = .05) <= 0.5]
I get this output:
[1] -0.10 -0.05 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45
Why is 0.50 not in the results ?
(It seems that it gives a slightly bigger number then 0.5 but I don't
understand why it does that)
Where as if I try:
seq(-0.1,.9, by = .05)[seq(-0.1,.9, by = .05) <=
2016 Mar 22
0
CEBA-2016:0485 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2016:0485
Upstream details at : https://rhn.redhat.com/errata/RHBA-2016-0485.html
The following updated files have been uploaded and are currently
syncing to the mirrors: ( sha256sum Filename )
i386:
f43bc50d1af8b9f23f8eca5b92874105fc6ca169fd9d6887990e8a47bb5b1207 libcgroup-0.40.rc1-17.el6_7.i686.rpm
2016 Jul 12
0
CEBA-2016:1410 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2016:1410
Upstream details at : https://rhn.redhat.com/errata/RHBA-2016-1410.html
The following updated files have been uploaded and are currently
syncing to the mirrors: ( sha256sum Filename )
i386:
e529a006388dda6e4ce85e70623426707f033d27f868492f24cdc8a29ac47a4f libcgroup-0.40.rc1-18.el6_8.i686.rpm
2017 Oct 04
0
CEBA-2017:2854 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2017:2854
Upstream details at : https://access.redhat.com/errata/RHBA-2017:2854
The following updated files have been uploaded and are currently
syncing to the mirrors: ( sha256sum Filename )
i386:
9b58a5eb510e3c7664ccae92a1c12c1679593efe3041f5c5d0733bbad0884949 libcgroup-0.40.rc1-24.el6_9.i686.rpm
2018 Oct 09
0
CEBA-2018:2895 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2018:2895
Upstream details at : https://access.redhat.com/errata/RHBA-2018:2895
The following updated files have been uploaded and are currently
syncing to the mirrors: ( sha256sum Filename )
i386:
334ee6d935abe38fdd59e2d7d328190730db5c3ece3eb93c47af9665396809d5 libcgroup-0.40.rc1-27.el6_10.i686.rpm
2013 Dec 09
0
CEBA-2013:1797 CentOS 6 libcgroup Update
CentOS Errata and Bugfix Advisory 2013:1797
Upstream details at : https://rhn.redhat.com/errata/RHBA-2013-1797.html
The following updated files have been uploaded and are currently
syncing to the mirrors: ( sha256sum Filename )
i386:
9a39c9616d3f1fbe1676a4ca2c69bde4a350231f588524b963cea5d9675cbdf6 libcgroup-0.40.rc1-5.el6_5.1.i686.rpm
2014 Sep 30
0
CEBA-2014:1328 CentOS 6 libcgroup BugFix Update
CentOS Errata and Bugfix Advisory 2014:1328
Upstream details at : https://rhn.redhat.com/errata/RHBA-2014-1328.html
The following updated files have been uploaded and are currently
syncing to the mirrors: ( sha256sum Filename )
i386:
18d3cb7b351152d05f0fcb643606c89aa8afdadc2f37a2fb781bd16081e9180c libcgroup-0.40.rc1-6.el6_5.1.i686.rpm
2013 May 27
1
Question about subsetting S4 object in ROCR
Dear list
I'm testing a predictor and I produced nice performance plots with ROCR
package utilizing the 3 standard command
pred <- prediction(predictions, labels)
perf <- performance(pred, measure = "tpr", x.measure = "fpr")
plot(perf, col=rainbow(10))
The pred object and the perfo object are S4
with the following slots
An object of class "performance"