search for: 0.14

CentOS Errata and Enhancement Advisory 2012:0530 Upstream details at : https://rhn.redhat.com/errata/RHEA-2012-0530.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 53da93638561a35a13a8f47db761d728b2b850b11eccd729c8d071289883d244 python-qpid-0.14-7.el6_2.noarch.rpm

CentOS Errata and Security Advisory 2012:1269 Moderate Upstream details at : https://rhn.redhat.com/errata/RHSA-2012-1269.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 293df4e212d169d2c52478b2370a4836f6e9583c04397bf087edb7a2c306946c python-qpid-0.14-11.el6_3.noarch.rpm

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Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,

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This release adds support for 32-bit PCI domain IDs, which are apparently common in virtualized environments. This support has been tested on Linux, and probably also "just works" on FreeBSD and Solaris, to the extent that the underlying OS supports it. If you were allocating a struct pci_device yourself, or embedding it in another structure, this release would be an ABI break. That

CentOS Errata and Bugfix Advisory 2013:1159 Upstream details at : https://rhn.redhat.com/errata/RHBA-2013-1159.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 8d1079bab56eeedfe19cf4d835012f38a22f7069537facc0eb30054c4ec9c118 spice-glib-0.14-7.el6_4.1.i686.rpm

CentOS Errata and Security Advisory 2013:1273 Important Upstream details at : https://rhn.redhat.com/errata/RHSA-2013-1273.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: c7bc8814163e0390fbba942451f909fd2219a985e6d7d80e20406337df9f53d7 spice-glib-0.14-7.el6_4.3.i686.rpm

Hi, I am trying to do a lasso regression using the lars package with the following data (see attached): FastestTime WinPercentage PlacePercentage ShowPercentage BreakAverage FinishAverage Time7Average Time3Average Finish 116.90 0.14 0.14 0.29 4.43 3.29 117.56 117.77 5.00 116.23 0.29 0.43 0.14 6.14 2.14 116.84 116.80 2.00 116.41 0.00 0.14 0.29 5.71 3.71 117.24

Hi all, I have 2 questions: 1)How do I calculate the mean on an imported txt file? I've imported the file below and that's what it looks like imported. How do I then calcuate the mean, median, or mode on the column LeafArea using the desktop R package? Any help would be greatly appreciated!! Thanks, Nat LeafType Leaflets LeafArea ShapeRatio LeafWeight LeafThickness 1 1

Hello everyone,           I have a basic question regarding logical operators. > x<-seq(-1,1,by=0.02) > x   [1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78  [13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54  [25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30  [37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16

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Hi all, I can't figure out how to compute Wilks Lambda in a one way repeated measure design. My matrix looks like: > t2.m Blank ECR ENC UEA UED 1 -0.15 0.14 0.16 0.09 0.14 2 0.30 0.08 0.14 0.14 0.14 [...] where each row is a case and the columns are levels of one factor (named trial): > t2.fit <- manova(t2.m ~ 1) > summary(t2.fit, intercept=T,

The following errata for CentOS-2 have been built and uploaded to the centos mirror: RHSA-2008:0208-01 Critical: seamonkey security update Files available: seamonkey-1.0.9-0.14.el2.c2.1.i386.rpm seamonkey-chat-1.0.9-0.14.el2.c2.1.i386.rpm seamonkey-devel-1.0.9-0.14.el2.c2.1.i386.rpm seamonkey-dom-inspector-1.0.9-0.14.el2.c2.1.i386.rpm seamonkey-js-debugger-1.0.9-0.14.el2.c2.1.i386.rpm

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Hello there, I am not quite sure how to interpret the output of Rprof (in the following the output I was staring at). I was poking around the web a little bit for documentation but without much success. I guess if I want to figure out what takes so long in my code the 2nd table $by.total and the total.pct column (pct = percent) is the most helpful. What does it mean that [ or [.data.frame is

Having problems with Tripwire on C6, I installed AIDE from the base repository. x86_64 0.14-3.el6_2.2 base 123 k typing: aide result: "Couldn't open file /var/lib/aide/aide.db.gz for reading" (directory is empty and aide.db.gz does not exist.) typing: aide -i (for initialise the Aide database) result: "AIDE, version 0.14 ### AIDE database at

Hello, I’m trying to follow the syntax of a script from a journal website. In order to create a regression formula used later in the script, the regression matrix must have column names “X1”, “X2”, etc. I have tried to assign these column names to my matrix ScoutRSM.mat using a for loop, but I don’t know how to interpret the error message. Suggestions? Thanks, Paul

Hi R user,I am struggling to figure out on how I can calculate the average from the two tables in R. Any one can help me? really your help would be grateful- I am spending so much time to figure it out. It should not be so hard, I think. I have very big data but I have created a hypothetical data for simplification. for example I have : table 1 table 1: species occurance data

Hello I am a new user of R . and I ve problem with R and netcdf . I succed installation , I could use all examples . But when I take my netcf it is different . I want to do statistic on this kind of file . 1) first calculate mean . my data is like that through ncdump -h test.nc netcdf test { dimensions: lat = 301 ; lon = 401 ; time = UNLIMITED ; // (80 currently)