Displaying 20 results from an estimated 57 matches for "0.134".
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0.13
2008 Mar 27
2
options in 'rnorm' to set the lower bound of normal distribution to 0 ?
Dear list,
I have a dataset containing values obtained from two different instruments (x and y).
I want to generate 5 samples from normal distribution for each instrument based on
their means and standard deviations. The problem is values from both instruments are
non-negative, so if using rnorm I would get some negative values. Is there any options
to determine the lower bound of normal
2008 Apr 01
1
set the lower bound of normal distribution to 0 ?
Tom Cohen <tom.cohen78@yahoo.se> skrev: Thanks Prof Brian for your suggestion.
I should know that for right-skewed data,
one should generate the samples from a lognormal.
My problem is that x and y are two instruments that were thought to
be measured the same thing but somehow show a wide confidence interval
of the difference between the two intruments.This may be true that
these
2012 Aug 21
1
make check fails two tests on RHEL 6 build
I am installing R 2.15.1 onto RHEL 6, using gcc 4.7.0 with Intel MKL
10.3.7 and the following environment:
export BLAS_LIBS="-Wl,--start-group
/usr/caen/intel-12.1/mkl/lib/intel64/libmkl_gf_lp64.a
/usr/caen/intel-12.1/mkl/lib/intel64/libmkl_sequential.a
/usr/caen/intel-12.1/mkl/lib/intel64/libmkl_core.a -Wl,--end-group
-lpthread"
export LAPACK_LIBS="-Wl,--start-group
2010 Dec 21
2
please Help me on a repeated measures anova
I currently work on a draft of an aquatic bioassessment. The conditions
tested are the following: ER river water T dechlorinated water control 0.5 +
0.5mg / L of malate T + 1 dechlorinated water control + 1g / L of malate T
ED dechlorinated water control SED + ER + river water sediment SED ED +
sediment + water dechlorinated. It is the result of AChE in muscle (fillet
of fish). The production of
2009 Jul 24
1
metafor
I had found the author's (Wolfgang Viechtbauer) earlier meta-analytic code in R, MiMa, useful. so I have been exploring metafor using an example dataset from MiMa. metafor provides a lot more. However, MiMa provided parameter estimates, standard errors, z values, etc. for individual moderators in the meta-analysis, but I don't see how to obtain these from metafor. Have you any help
2013 Dec 02
1
Arithmetic Error while compiling R with the Intel compilers
Hi Team,
I downloaded the R 3.0.2 and, built and installed it
using Intel compilers (icc and ifort) from Intel parallel studio 2013,
sp1. After performing make tried to check it using 'make check'. Most of
the tests passed successfully but while checking a 'stats' package I saw
many lines were printed which did not match the desired output.
e.g.
There
2007 Jul 08
2
transform excel data into graph
Hello everyone,
I have a set of data in the following form, which are stored in an Excel
file:
nick john peter
lesson1 0.465 0.498 0.473
lesson2 0.422 0.44 0.134
lesson3 0.45 0.35 0.543
lesson4 0.590 0.64 0.11
lesson5 0.543
2010 Jan 04
3
how to draw abline correctly?
Hello, I am frastruated with this graph, just cannot get what I need. Thank
you for any suggestions or help. I really appreciate it. I wrote the
following code, but there are 3 problems
1, the red line is added on the graph but without any marker on the y-axis.
I want to display the number '.1361' on the y-axis. So people can easily
tell 'method 2' gets a constant estimate, which
2008 Mar 08
1
ask for help on nonlinear fitting
I have a table like the following. I want to fit Cm to Vm like this:
Cm ~ Cl+Q1*b1*38.67*exp(-b1*(Vm-Vp1)*0.03867)/(1+exp(-b1*(Vm-Vp1)*0.03867))^2+Q2*b2*38.67*exp(-b2*(Vm-Vp2)*0.03867)/(1+exp(-b2*(Vm-Vp2)*0.03867))^2
I use nls, with start=list(Q1=2e-3, b1=1, Vp1=-25, Q2=3e-3, b2=1,
Vp2=200). But I always get 'singlular gradient' error like this. But
in SigmaPlot I can get the result. How
2005 Apr 05
1
extracting Proportion Var and Cumulative Var values from factanal
Hi R users,
I need some help in the followings:
I'm doing factor analysis and I need to extract the loading values and
the Proportion Var and Cumulative Var values one by one.
Here is what I am doing:
> fact <- factanal(na.omit(gnome_freq_r2),factors=5);
> fact$loadings
Loadings:
Factor1 Factor2 Factor3 Factor4 Factor5
b1freqr2 0.246 0.486 0.145
2008 May 08
2
acf function
Dear all,
I have an annual time-series of population numbers and I would like to
estimate the auto-correlation. Can I use acf() function and judge
whether auto-correlation is significant by the plots? The acf array, eg:
Autocorrelations of series 'x$log.s.r', by lag
0 1 2 3 4 5 6 7 8 9
10 11 12
1.000 0.031 -0.171
2007 Mar 26
1
Network freezes - possibly yum?
Hi. I have a CentOS 4.2 server running. I've just experience that it
stops responding (http, ssh) when doing yum update pam xorg-x11 gnupg
This has happened two times in a row, so I'm curious if anyone has
experienced anything like this? Could it be yum or should I look for the
explanation elsewhere?
[root at machine ~]# yum update pam xorg-x11 gnupg
Setting up Update Process
Setting
2017 Jun 30
0
Multiple "scale_color_manual" statements in one plot (ggplot2, flexible legend challenge)
Dear list,
I am facing an unusual situation where I need to create two sets of legends
based on the color mapping. Can't get exactly what I want and really
appreciate any advice from ggplot experts.
Let's say I have the first dataset "df1" that draws some points and based
on which a "loess" line with confidence interval is added. Then the second
dataset
2012 Jun 19
1
Scaling a "density".
Folks,
I have a small dataset of counts of recoveries on defaulted loans:
recoveries<-structure(c(0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1,
0, 0, 0, 0, 0, 4, 0, 1, 2, 2, 12), .Dim = c(11L, 2L), .Dimnames = list(
NULL, c("pcts", "counts")))
Here is the data in columnar form:
pcts counts
[1,] 0.0 0
[2,] 0.1 0
[3,] 0.2 0
[4,] 0.3
2010 Feb 17
2
extract the data that match
Hi r-users,
I would like to extract the data that match. Attached is my data:
I'm interested in matchind the value in column 'intg' with value in column 'rand_no'
> cbind(z=z,intg=dd,rand_no = rr)
z intg rand_no
[1,] 0.00 0.000 0.001
[2,] 0.01 0.000 0.002
[3,] 0.02 0.000 0.002
[4,] 0.03 0.000 0.003
[5,] 0.04 0.000 0.003
[6,]
2002 Jan 04
1
glm deviance question
I am comparing the Splus and R fits of a simple glm.
In the following, foo is generated from rbinom with size = 20 p = 0.5.
The coefficients (and SE's0 of the fitted models are the same, but the
estimated deviances are quite different. Could someone please tell me why
they are so different? I am using R version 1.3.1 and Splus 2000 release 3
on windows 2000.
++++++++++++++++++++++
foo
2003 Jan 20
1
make check for R-1.6.2 on IBM AIX
Dear all,
The 'make check' step fails for the pacakge mva on IBM AIX.
The tail of the Rout log file looks like:
> for(factors in 2:4) print(update(Harman23.FA, factors = factors))
Call:
factanal(factors = factors, covmat = Harman23.cor)
Uniquenesses:
height arm.span forearm lower.leg weight
0.170 0.107 0.166
2003 Aug 18
1
R and Poisson
Hi, I wonder if anyone can answer the following or point me in the direction of
how to obtain answers to the questions. Below is Output from R and further down
are the questions raised and explanation of the study.
Output from R:
glm(formula = CB95TO00 ~ URB + INC, family = poisson)
Deviance Residuals:
Min 1Q Median 3Q Max
-1.2272 -1.1290 0.2709 0.4272 2.1376
2009 Feb 23
1
why results from regression tree (rpart) are totally inconsistent with ordinary regression
Hi,
In my analysis of impacts of insecticide-treated bednets on malaria, I
look at the relationship between malaria incidence and mosquito
behaviors. The condensed data set is copied here. Ordinary regression
(lm) shows that Incidence was negatively related to Mortality. This
makes sense because the latter reflected the strength of killing
mosquitoes by insecticide-treated nets. Since the
2008 Nov 26
1
multiple imputation with fit.mult.impute in Hmisc - how to replace NA with imputed value?
I am doing multiple imputation with Hmisc, and
can't figure out how to replace the NA values with
the imputed values.
Here's a general ourline of the process:
> set.seed(23)
> library("mice")
> library("Hmisc")
> library("Design")
> d <- read.table("DailyDataRaw_01.txt",header=T)
> length(d);length(d[,1])
[1] 43
[1] 2666