search for: 0.13

Hi all, I have 2 questions: 1)How do I calculate the mean on an imported txt file? I've imported the file below and that's what it looks like imported. How do I then calcuate the mean, median, or mode on the column LeafArea using the desktop R package? Any help would be greatly appreciated!! Thanks, Nat LeafType Leaflets LeafArea ShapeRatio LeafWeight LeafThickness 1 1

Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,

Dear R users, I am trying to have an xyplot of a data set which has the following variables: case (n=10,20,30) parameter (parm=a,b) group (grp=g1,g2) y (y values) x (x=2,4,8) My plot should be parameter by case such that I have 2 rows (each row= each parameter) and 3 columns (each column=each case). My R-code is as follows but I am not able to get what I want to: tp1.sim <- xyplot(y~ x | case

Hi, I recompiled my kernel today, and when the btrfs-0.13 option is enabled (CONFIG_BTR_FS=y) I cannot boot on my reiserfs-3.6 partition any more. The kernel says that is cannot mount /dev/sdc6. I can boot the kernel when I recompile it with the same options and CONFIG_BTR_FS=n, and with the same boot options as well. Everything is amd64 on my system (kernel + programs). Here is a screenshot of

Am 18.01.2017 um 20:01 schrieb Matthew Delfino via samba: > UPDATE: These commands seem to have addressed my problem, but I don’t know if it’s a lame or elegant hack: > > ln -s /usr/lib/libwbclient.so.0.13 /usr/lib/x86_64-linux-gnu/libwbclient.so.0.13 > cd /usr/lib/x86_64-linux-gnu/ > rm libwbclient.so.0 > ln -s libwbclient.so.0.13 libwbclient.so.0 looks extremely dirty and

Dear Group, I have the following data matrix which is a timeseries. > dput(tData) structure(list(A = c(0.2, 0.13, 0.05, 0.1, 0.02, 0.18, 0.09, 0.06, 0.13), B = c(0.15, 0.06, 0.09, 0.02, 0.03, 0.12, 0.01, 0.15, 0.06), C = c(-0.1, 0, -0.07, -0.06, -0.05, -0.05, -0.06, -0.08, -0.07), D = c(-0.15, -0.05, -0.1, -0.03, -0.13, -0.04, -0.1, -0.04, -0.15), E = c(-0.17, -0.16, -0.08, -0.07, -0.09,

Hey Rowland, thanks for your quick reply. Answers below… > On 2017.01.18, at 12:41 PM, Rowland Penny via samba <samba at lists.samba.org> wrote: > > On Wed, 18 Jan 2017 11:34:41 -0600 > Matthew Delfino via samba <samba at lists.samba.org> wrote: > >> Hello, >> >> I have an Ubuntu 14.04 server with Samba 4.4.6 and a BIND DLZ backend >> that

Hello, I have an Ubuntu 14.04 server with Samba 4.4.6 and a BIND DLZ backend that I’ve downloaded, configured and installed from source. I’ve downloaded the source for Samba 4.5.4, compiled and installed, and now Samba won’t launch. If I try to run samba, I get the following error: samba: /usr/lib/x86_64-linux-gnu/libwbclient.so.0: version `WBCLIENT_0.13' not found (required by

Hi all, Since 0.13 just got out, I decided to live a little on the edge and upgraded my working 0.12.1 Rails apps to 0.13. Which made them crash with a bang! After a little investigation it looks like even a fresh app will crash with a message: "allocator undefined for proc"... I''m on Win XP, everything was fine under Rails 0.12.1 Any help would be highly appreciated. --

Hello I am a new user of R . and I ve problem with R and netcdf . I succed installation , I could use all examples . But when I take my netcf it is different . I want to do statistic on this kind of file . 1) first calculate mean . my data is like that through ncdump -h test.nc netcdf test { dimensions: lat = 301 ; lon = 401 ; time = UNLIMITED ; // (80 currently)

OK, I give in, why didn't I get the OPs reply to my post ? On Wed, 18 Jan 2017 13:23:16 -0600 Matthew Delfino via samba <samba at lists.samba.org> wrote: > > > On 2017.01.18, at 1:16 PM, Reindl Harald via samba > > <samba at lists.samba.org> wrote: > > > > Am 18.01.2017 um 20:01 schrieb Matthew Delfino via samba: > >> UPDATE: These commands

Hi There, I'm facing one problem to construct a vector using the "for" command: I have one matrix named 'dados' (same as /data/ from portuguese), for example: > dados[140:150,] [,1] [,2] [,3] [1,] 212.7298 0.14 0.11 [2,] 213.3778 0.14 0.11 [3,] 214.0257 0.15 0.11 [4,] 214.6737 0.15 0.12 [5,] 215.3217 0.15 0.12 [6,] 215.9696 0.15 0.12 [7,] 216.6176 0.16

I am trying to investigate the interaction term in the below. The paradigm in aquatic systems is that algal production is either nitrogen (TIN) or Phosphorus limited, and I am trying to investigate this- what is the best way to go about investigating the interaction term. I have some thoughts on the above, but I will withhold them to see what others think. Thanks for your help. d <-

#is there a way to get NA in the table of descriptive statistics instead of the function stopping Thank you in advance #data x.f <- structure(list(Site = structure(c(9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L), .Label = c("BC", "HC", "RM119", "RM148", "RM179", "RM185",

Hi there, Just gave 0.13 a spin against XFS (both with default mkfs options) on my SATA tower and was impressed by how much performance has improved since last time I played with it (v0.5)! It pretty much matched XFS for I/O performance and had much better file creation/deletion performance. http://www.csamuel.org/2008/03/23/btrfs-013-and-xfs-benchmarks cheers, Chris -- Chris Samuel :

I would like to use the data below where the plots are close to what I want. Instead of color I would like to use different symbols, and have the symbols in the legend match the graphs. I am also going to add a regression line to these I know about the type="r" (which is fine for these particular graphs) argument, but it fits the subsets instead of the entire data set-- should I use a

Hello, I am trying to create multiple matrices (to run a PVA) but can't import all of them from a .csv without the numbers treated as labels and not factors. I can enter the matrix slowly: Site05_96 <- matrix(c(0.07,0,0.03,0.00,NA,0.00, 0.09,0.166666667,0.31,0.42,NA,0.00, 0.00,0,0.00,0.00,NA,0.00, 0.00,0,0.00,0.00,NA,0.00,

UPDATE: These commands seem to have addressed my problem, but I don’t know if it’s a lame or elegant hack: ln -s /usr/lib/libwbclient.so.0.13 /usr/lib/x86_64-linux-gnu/libwbclient.so.0.13 cd /usr/lib/x86_64-linux-gnu/ rm libwbclient.so.0 ln -s libwbclient.so.0.13 libwbclient.so.0 Thanks, Matthew > On 2017.01.18, at 12:55 PM, Matthew Delfino via samba <samba at lists.samba.org> wrote:

Hi, I have a 3d array as below, I want to make this array to a matrix of p=50(rows) and n=20(columns) with the coverage values . The code before the array is: library(binom) Loading required package: lattice pi.seq<-seq(from = 0.01, to = 0.5, by = 0.01) no.seq<-seq(from = 5, to = 100, by = 5) cp.all = binom.coverage( p = pi.seq, n = no.seq , conf.level = 0.95, method = "exact")

> On 2017.01.18, at 2:06 PM, Bob of Donelson Trophy via samba <samba at lists.samba.org> wrote: > > On 2017-01-18 13:41, Rowland Penny via samba wrote: > >> OK, I give in, why didn't I get the OPs reply to my post ? >> >> On Wed, 18 Jan 2017 13:23:16 -0600 >> Matthew Delfino via samba <samba at lists.samba.org> wrote: >> >> On