Rails spinoffs - Apr 2008 - How to pass variable to $$()?

Hi all,

      I want the $$() method to take the selector as an variable. See
below, I am trying to pass the class name as javascript variable so I
can write a generic function in my application but $$() returns
nothing for the following line

var currentHightLightGroup ="amountsFields";//This one comes as a
function parameter
$$(''span[class=\''''+currentHightLightGroup+''\'']'')
-> returns nothing.

Any help is much appericated.
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why not use class syntax?

"span.amountsFields"

On 4/28/08, kishore.sayee-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org
<kishore.sayee-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:
>
>  Hi all,
>
>       I want the $$() method to take the selector as an variable. See
>  below, I am trying to pass the class name as javascript variable so I
>  can write a generic function in my application but $$() returns
>  nothing for the following line
>
>  var currentHightLightGroup ="amountsFields";//This one comes as
a
>  function parameter
> 
$$(''span[class=\''''+currentHightLightGroup+''\'']'')
>  -> returns nothing.
>
>  Any help is much appericated.
>  >
>
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$$(''span.'' + currentHighlightGroup);

// or

$$(''span'').findAll(function(el){
  return el.hasClassName(currentHighlightGroup)
});

// the latter one will actually be much slower...

- kangax

On Apr 28, 2:42 pm,
"kishore.sa...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org"
<kishore.sa...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:
> Hi all,
>
>       I want the $$() method to take the selector as an variable. See
> below, I am trying to pass the class name as javascript variable so I
> can write a generic function in my application but $$() returns
> nothing for the following line
>
> var currentHightLightGroup ="amountsFields";//This one comes as a
> function parameter
>
$$(''span[class=\''''+currentHightLightGroup+''\'']'')
> -> returns nothing.
>
> Any help is much appericated.
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Thanks much, It worked.

On Apr 28, 3:39 pm, kangax
<kan...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:
> $$(''span.'' + currentHighlightGroup);
>
> // or
>
> $$(''span'').findAll(function(el){
>   return el.hasClassName(currentHighlightGroup)
>
> });
>
> // the latter one will actually be much slower...
>
> - kangax
>
> On Apr 28, 2:42 pm,
"kishore.sa...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org"
>
> <kishore.sa...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote:
> > Hi all,
>
> >       I want the $$() method to take the selector as an variable. See
> > below, I am trying to pass the class name as javascript variable so I
> > can write a generic function in my application but $$() returns
> > nothing for the following line
>
> > var currentHightLightGroup ="amountsFields";//This one comes
as a
> > function parameter
> >
$$(''span[class=\''''+currentHightLightGroup+''\'']'')
> > -> returns nothing.
>
> > Any help is much appericated.
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