R help - Apr 2023 - detect and replace outliers by the averaged

There is at least one outliers package on CRAN.

el
On 20/04/2023 20:43, AbouEl-Makarim Aboueissa wrote:
> Dear All:  *please discard my previous email*
> 
> 
> 
> *Re:* detect and replace outliers by the average
> 
> 
> 
> The dataset, please see attached, contains a group factoring column ?
> *factor*? and two columns of data ?x1? and ?x2? with some NA values. I need
> some help to detect the outliers and replace it and the NAs with the
> average within each level (0,1,2) for each variable ?x1? and ?x2?.
> 
> 
> 
> I tried the below code, but it did not accomplish what I want to do.
> 
> 
> 
> 
> 
> data<-read.csv("G:/20-Spring_2023/Outliers/data.csv",
header=TRUE)
> 
> data
> 
> replace_outlier_with_mean <- function(x) {
> 
>   replace(x, x %in% boxplot.stats(x)$out, mean(x, na.rm=TRUE))  #### ,
> na.rm=TRUE NOT working
> 
> }
> 
> data[] <- lapply(data, replace_outlier_with_mean)
> 
> 
> 
> 
> 
> Thank you all very much for your help in advance.
> 
> 
> 
> 
> 
> with many thanks
> 
> abou
> 
> 
> ______________________
> 
> 
> *AbouEl-Makarim Aboueissa, PhD*
> 
> *Professor, Mathematics and Statistics*
> *Graduate Coordinator*
> 
> *Department of Mathematics and Statistics*
> *University of Southern Maine*

0

On April 21, 2023 4:08:08 AM GMT+09:00, Dr Eberhard W Lisse <nospam at
lisse.NA> wrote:
>There is at least one outliers package on CRAN.
>
>el
>On 20/04/2023 20:43, AbouEl-Makarim Aboueissa wrote:
>> Dear All:  *please discard my previous email*
>> 
>> 
>> 
>> *Re:* detect and replace outliers by the average
>> 
>> 
>> 
>> The dataset, please see attached, contains a group factoring column ?
>> *factor*? and two columns of data ?x1? and ?x2? with some NA values. I
need
>> some help to detect the outliers and replace it and the NAs with the
>> average within each level (0,1,2) for each variable ?x1? and ?x2?.
>> 
>> 
>> 
>> I tried the below code, but it did not accomplish what I want to do.
>> 
>> 
>> 
>> 
>> 
>> data<-read.csv("G:/20-Spring_2023/Outliers/data.csv",
header=TRUE)
>> 
>> data
>> 
>> replace_outlier_with_mean <- function(x) {
>> 
>>   replace(x, x %in% boxplot.stats(x)$out, mean(x, na.rm=TRUE))  #### ,
>> na.rm=TRUE NOT working
>> 
>> }
>> 
>> data[] <- lapply(data, replace_outlier_with_mean)
>> 
>> 
>> 
>> 
>> 
>> Thank you all very much for your help in advance.
>> 
>> 
>> 
>> 
>> 
>> with many thanks
>> 
>> abou
>> 
>> 
>> ______________________
>> 
>> 
>> *AbouEl-Makarim Aboueissa, PhD*
>> 
>> *Professor, Mathematics and Statistics*
>> *Graduate Coordinator*
>> 
>> *Department of Mathematics and Statistics*
>> *University of Southern Maine*
>
>______________________________________________
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