So running the code in my head....as long as that column's data type is a
vector of characters then it should work.
Did you try it out?
On Sat, Aug 18, 2018, 5:02 PM Jeff Reichman <reichmanj at sbcglobal.net>
wrote:
> Given it?s a variable would I just change the 12.6 in
> as.numeric(gsub(pattern = "%","","12.6%"))
>
> To the variable name say ? as.numeric(gsub(pattern =
"%","",df$variable))
>
>
>
>
>
> *From:* GALIB KHAN <ghk18 at scarletmail.rutgers.edu>
> *Sent:* Saturday, August 18, 2018 4:23 PM
> *To:* reichmanj at sbcglobal.net
> *Cc:* r-help at r-project.org
> *Subject:* Re: [R] Converting chr to num
>
>
>
> Hey there,
>
>
>
> as.numeric(gsub(pattern = "%","","12.6%"))
>
>
>
> On Sat, Aug 18, 2018 at 4:20 PM, Jeff Reichman <reichmanj at
sbcglobal.net>
> wrote:
>
> R-Help Forum
>
>
>
> How do I convert a chr variable that contains percentages to an integer
>
>
>
> Example 12.6% (chr) to 12.6 (int)
>
>
>
> Jeff
>
>
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>
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