Hi With the example, na.locf seems to be the easiest way.> library(zoo)> na.locf(df1)ID ID_2 Firist Value 1 a aa TRUE 2 2 a ab FALSE 2 3 a ac FALSE 2 4 b aa TRUE 5 5 b ab FALSE 5 Cheers Petr> -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Jeff > Newmiller > Sent: Monday, January 8, 2018 9:13 AM > To: r-help at r-project.org; Ek Esawi <esawiek at gmail.com> > Subject: Re: [R] Replace NAs in split lists > > Upon closer examination I see that you are not using the split version of > df1 as I usually would, so here is a reproducible example: > > #---- > df1 <- read.table( text> "ID ID_2 Firist Value > 1 a aa TRUE 2 > 2 a ab FALSE NA > 3 a ac FALSE NA > 4 b aa TRUE 5 > 5 b ab FALSE NA > ", header=TRUE, as.is=TRUE ) > > sdf <- split( df1, df1$ID ) > # note the extra [ 1 ] in case you have more than one non-NA value # per ID > sdf2 <- lapply( sdf > , function( z ) { > z$Value <- ifelse( is.na( z$Value ) > , z$Value[ !is.na( z$Value ) ][ 1 ] > , z$Value > ) > z > } > ) > df2 <- do.call( rbind, sdf2 ) > df2 > #> ID ID_2 Firist Value > #> a.1 a aa TRUE 2 > #> a.2 a ab FALSE 2 > #> a.3 a ac FALSE 2 > #> b.4 b aa TRUE 5 > #> b.5 b ab FALSE 5 > > # or using tidyverse methods > > library(dplyr) > #> > #> Attaching package: 'dplyr' > #> The following objects are masked from 'package:stats': > #> > #> filter, lag > #> The following objects are masked from 'package:base': > #> > #> intersect, setdiff, setequal, union > df3 <- ( df1 > %>% group_by( ID ) > %>% do({ > mutate( . > , Value = ifelse( is.na( Value ) > , Value[ !is.na( Value ) ][ 1 ] > , Value > ) > ) > }) > %>% ungroup > ) > df3 > #> # A tibble: 5 x 4 > #> ID ID_2 Firist Value > #> <chr> <chr> <lgl> <int> > #> 1 a aa T 2 > #> 2 a ab F 2 > #> 3 a ac F 2 > #> 4 b aa T 5 > #> 5 b ab F 5 > #---- > > On Sun, 7 Jan 2018, Jeff Newmiller wrote: > > > Why do you want to modify df1? > > > > Why not just reassemble the parts as a new data frame and use that > > going forward in your calculations? That is generally the preferred > > approach in R so you can re-do your calculations easily if you find a > > mistake later. > > -- > > Sent from my phone. Please excuse my brevity. > > > > On January 7, 2018 7:35:59 PM PST, Ek Esawi <esawiek at gmail.com> wrote: > >> I just came up with a solution right after i posted the question, but > >> i figured there must be a better and shorter one.than my solution > >> sdf1[[1]][1,4]<-lapplyresults[[1]] > >> sdf1[[2]][1,4]<-lapplyresults[[2]] > >> > >> EK > >> > >> On Sun, Jan 7, 2018 at 10:13 PM, Ek Esawi <esawiek at gmail.com> wrote: > >>> Hi all-- > >>> > >>> I stumbled on this problem online. I did not like the solution given > >>> there which was a long UDF. I thought why cannot split and l/s apply > >>> work here. My aim is to split the data frame, use l/sapply, make > >>> changes on the split lists and combine the split lists to new data > >>> frame with the desired changes/output. > >>> > >>> The data frame shown below has a column named ID which has 2 > >> variables > >>> a and b; i want to replace the NAs on the Value column by 2, which > >>> is the only numeric entry, for ID=a and by 5 for ID=b. > >>> > >>> I worked out the solution but could not replace the results in the > >> split lists. > >>> > >>> Original dataframe , df1 > >>> ID ID_2 Firist Value > >>> 1 a aa TRUE 2 > >>> 2 a ab FALSE NA > >>> 3 a ac FALSE NA > >>> 4 b aa TRUE 5 > >>> 5 b ab FALSE NA > >>> Sdf1 > >>> $a > >>> ID ID_2 Firist Value > >>> 1 a aa TRUE 2 > >>> 2 a ab FALSE NA > >>> 3 a ac FALSE NA > >>> $b > >>> ID ID_2 Firist Value > >>> 4 b aa TRUE 5 > >>> 5 b ab FALSE NA > >>> Desired results > >>> ID ID_2 Firist Value > >>> 1 a aa TRUE 2 > >>> 2 a ab FALSE 2 > >>> 3 a ac FALSE 2 > >>> > >>> $b > >>> ID ID_2 Firist Value > >>> 4 b aa TRUE 5 > >>> 5 b ab FALSE 5 > >>> > >>> My code > >>> > >>> sdf <- split(df1,df$ID) > >>> lapply(sdf, function(z) > >> ifelse(is.na(z$Value),z$Value[!is.na(z$Value)],z$Value)) > >>> result: > >>> $ a: num [1:3] 2 2 2 > >>> $ b: num [1:2] 5 5 > >>> > >>> How could I put these two lists back in the split data frame, sdf1? > >>> Then I could use do.call to reassemble a data frame from the split > >>> lists, > >>> > >>> Thanks, > >>> EK > >> > >> ______________________________________________ > >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> https://stat.ethz.ch/mailman/listinfo/r-help > >> PLEASE do read the posting guide > >> http://www.R-project.org/posting-guide.html > >> and provide commented, minimal, self-contained, reproducible code. > > > > ______________________________________________ > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > > > --------------------------------------------------------------------------- > Jeff Newmiller The ..... ..... Go Live... > DCN:<jdnewmil at dcn.davis.ca.us> Basics: ##.#. ##.#. Live Go... > Live: OO#.. Dead: OO#.. Playing > Research Engineer (Solar/Batteries O.O#. #.O#. with > /Software/Embedded Controllers) .OO#. .OO#. rocks...1k > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.________________________________ Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny pouze jeho adres?t?m. Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho syst?mu. Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat. 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Yes, you are right if the IDs are always sequentially-adjacent and the first non-NA value appears in the first record for each ID. -- Sent from my phone. Please excuse my brevity. On January 8, 2018 2:29:40 AM PST, PIKAL Petr <petr.pikal at precheza.cz> wrote:>Hi > >With the example, na.locf seems to be the easiest way. >> library(zoo) > >> na.locf(df1) > ID ID_2 Firist Value >1 a aa TRUE 2 >2 a ab FALSE 2 >3 a ac FALSE 2 >4 b aa TRUE 5 >5 b ab FALSE 5 > >Cheers >Petr > >> -----Original Message----- >> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Jeff >> Newmiller >> Sent: Monday, January 8, 2018 9:13 AM >> To: r-help at r-project.org; Ek Esawi <esawiek at gmail.com> >> Subject: Re: [R] Replace NAs in split lists >> >> Upon closer examination I see that you are not using the split >version of >> df1 as I usually would, so here is a reproducible example: >> >> #---- >> df1 <- read.table( text>> "ID ID_2 Firist Value >> 1 a aa TRUE 2 >> 2 a ab FALSE NA >> 3 a ac FALSE NA >> 4 b aa TRUE 5 >> 5 b ab FALSE NA >> ", header=TRUE, as.is=TRUE ) >> >> sdf <- split( df1, df1$ID ) >> # note the extra [ 1 ] in case you have more than one non-NA value # >per ID >> sdf2 <- lapply( sdf >> , function( z ) { >> z$Value <- ifelse( is.na( z$Value ) >> , z$Value[ !is.na( z$Value ) ][ 1 >] >> , z$Value >> ) >> z >> } >> ) >> df2 <- do.call( rbind, sdf2 ) >> df2 >> #> ID ID_2 Firist Value >> #> a.1 a aa TRUE 2 >> #> a.2 a ab FALSE 2 >> #> a.3 a ac FALSE 2 >> #> b.4 b aa TRUE 5 >> #> b.5 b ab FALSE 5 >> >> # or using tidyverse methods >> >> library(dplyr) >> #> >> #> Attaching package: 'dplyr' >> #> The following objects are masked from 'package:stats': >> #> >> #> filter, lag >> #> The following objects are masked from 'package:base': >> #> >> #> intersect, setdiff, setequal, union >> df3 <- ( df1 >> %>% group_by( ID ) >> %>% do({ >> mutate( . >> , Value = ifelse( is.na( Value ) >> , Value[ !is.na( Value ) ][ 1 ] >> , Value >> ) >> ) >> }) >> %>% ungroup >> ) >> df3 >> #> # A tibble: 5 x 4 >> #> ID ID_2 Firist Value >> #> <chr> <chr> <lgl> <int> >> #> 1 a aa T 2 >> #> 2 a ab F 2 >> #> 3 a ac F 2 >> #> 4 b aa T 5 >> #> 5 b ab F 5 >> #---- >> >> On Sun, 7 Jan 2018, Jeff Newmiller wrote: >> >> > Why do you want to modify df1? >> > >> > Why not just reassemble the parts as a new data frame and use that >> > going forward in your calculations? That is generally the preferred >> > approach in R so you can re-do your calculations easily if you find >a >> > mistake later. >> > -- >> > Sent from my phone. Please excuse my brevity. >> > >> > On January 7, 2018 7:35:59 PM PST, Ek Esawi <esawiek at gmail.com> >wrote: >> >> I just came up with a solution right after i posted the question, >but >> >> i figured there must be a better and shorter one.than my solution >> >> sdf1[[1]][1,4]<-lapplyresults[[1]] >> >> sdf1[[2]][1,4]<-lapplyresults[[2]] >> >> >> >> EK >> >> >> >> On Sun, Jan 7, 2018 at 10:13 PM, Ek Esawi <esawiek at gmail.com> >wrote: >> >>> Hi all-- >> >>> >> >>> I stumbled on this problem online. I did not like the solution >given >> >>> there which was a long UDF. I thought why cannot split and l/s >apply >> >>> work here. My aim is to split the data frame, use l/sapply, make >> >>> changes on the split lists and combine the split lists to new >data >> >>> frame with the desired changes/output. >> >>> >> >>> The data frame shown below has a column named ID which has 2 >> >> variables >> >>> a and b; i want to replace the NAs on the Value column by 2, >which >> >>> is the only numeric entry, for ID=a and by 5 for ID=b. >> >>> >> >>> I worked out the solution but could not replace the results in >the >> >> split lists. >> >>> >> >>> Original dataframe , df1 >> >>> ID ID_2 Firist Value >> >>> 1 a aa TRUE 2 >> >>> 2 a ab FALSE NA >> >>> 3 a ac FALSE NA >> >>> 4 b aa TRUE 5 >> >>> 5 b ab FALSE NA >> >>> Sdf1 >> >>> $a >> >>> ID ID_2 Firist Value >> >>> 1 a aa TRUE 2 >> >>> 2 a ab FALSE NA >> >>> 3 a ac FALSE NA >> >>> $b >> >>> ID ID_2 Firist Value >> >>> 4 b aa TRUE 5 >> >>> 5 b ab FALSE NA >> >>> Desired results >> >>> ID ID_2 Firist Value >> >>> 1 a aa TRUE 2 >> >>> 2 a ab FALSE 2 >> >>> 3 a ac FALSE 2 >> >>> >> >>> $b >> >>> ID ID_2 Firist Value >> >>> 4 b aa TRUE 5 >> >>> 5 b ab FALSE 5 >> >>> >> >>> My code >> >>> >> >>> sdf <- split(df1,df$ID) >> >>> lapply(sdf, function(z) >> >> ifelse(is.na(z$Value),z$Value[!is.na(z$Value)],z$Value)) >> >>> result: >> >>> $ a: num [1:3] 2 2 2 >> >>> $ b: num [1:2] 5 5 >> >>> >> >>> How could I put these two lists back in the split data frame, >sdf1? >> >>> Then I could use do.call to reassemble a data frame from the >split >> >>> lists, >> >>> >> >>> Thanks, >> >>> EK >> >> >> >> ______________________________________________ >> >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> >> https://stat.ethz.ch/mailman/listinfo/r-help >> >> PLEASE do read the posting guide >> >> http://www.R-project.org/posting-guide.html >> >> and provide commented, minimal, self-contained, reproducible code. >> > >> > ______________________________________________ >> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> > https://stat.ethz.ch/mailman/listinfo/r-help >> > PLEASE do read the posting guide >> > http://www.R-project.org/posting-guide.html >> > and provide commented, minimal, self-contained, reproducible code. >> > >> >> >--------------------------------------------------------------------------- >> Jeff Newmiller The ..... ..... Go >Live... >> DCN:<jdnewmil at dcn.davis.ca.us> Basics: ##.#. ##.#. Live >Go... >> Live: OO#.. Dead: OO#.. >Playing >> Research Engineer (Solar/Batteries O.O#. #.O#. with >> /Software/Embedded Controllers) .OO#. .OO#. >rocks...1k >> >> ______________________________________________ >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. > >________________________________ >Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou >ur?eny pouze jeho adres?t?m. >Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? >neprodlen? jeho odes?latele. Obsah tohoto emailu i s p??lohami a jeho >kopie vyma?te ze sv?ho syst?mu. >Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento >email jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat. >Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou >modifikacemi ?i zpo?d?n?m p?enosu e-mailu. > >V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?: >- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? >smlouvy, a to z jak?hokoliv d?vodu i bez uveden? d?vodu. >- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? >p?ijmout; Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky >ze strany p??jemce s dodatkem ?i odchylkou. >- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve >v?slovn?m dosa?en?m shody na v?ech jej?ch n?le?itostech. >- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za >spole?nost ??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? >zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly >adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje, >p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen? >zn?m?. > >This e-mail and any documents attached to it may be confidential and >are intended only for its intended recipients. >If you received this e-mail by mistake, please immediately inform its >sender. Delete the contents of this e-mail with all attachments and its >copies from your system. >If you are not the intended recipient of this e-mail, you are not >authorized to use, disseminate, copy or disclose this e-mail in any >manner. >The sender of this e-mail shall not be liable for any possible damage >caused by modifications of the e-mail or by delay with transfer of the >email. > >In case that this e-mail forms part of business dealings: >- the sender reserves the right to end negotiations about entering into >a contract in any time, for any reason, and without stating any >reasoning. >- if the e-mail contains an offer, the recipient is entitled to >immediately accept such offer; The sender of this e-mail (offer) >excludes any acceptance of the offer on the part of the recipient >containing any amendment or variation. >- the sender insists on that the respective contract is concluded only >upon an express mutual agreement on all its aspects. >- the sender of this e-mail informs that he/she is not authorized to >enter into any contracts on behalf of the company except for cases in >which he/she is expressly authorized to do so in writing, and such >authorization or power of attorney is submitted to the recipient or the >person represented by the recipient, or the existence of such >authorization is known to the recipient of the person represented by >the recipient.
You can enforce these assumptions by sorting on multiple columns, which leads to na.locf(df1[ order(df1$ID,df1$Value), ]) On Mon, Jan 8, 2018 at 4:19 PM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote:> Yes, you are right if the IDs are always sequentially-adjacent and the > first non-NA value appears in the first record for each ID. > -- > Sent from my phone. Please excuse my brevity. > > On January 8, 2018 2:29:40 AM PST, PIKAL Petr <petr.pikal at precheza.cz> > wrote: > >Hi > > > >With the example, na.locf seems to be the easiest way. > >> library(zoo) > > > >> na.locf(df1) > > ID ID_2 Firist Value > >1 a aa TRUE 2 > >2 a ab FALSE 2 > >3 a ac FALSE 2 > >4 b aa TRUE 5 > >5 b ab FALSE 5 > > > >Cheers > >Petr > > > >> -----Original Message----- > >> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Jeff > >> Newmiller > >> Sent: Monday, January 8, 2018 9:13 AM > >> To: r-help at r-project.org; Ek Esawi <esawiek at gmail.com> > >> Subject: Re: [R] Replace NAs in split lists > >> > >> Upon closer examination I see that you are not using the split > >version of > >> df1 as I usually would, so here is a reproducible example: > >> > >> #---- > >> df1 <- read.table( text> >> "ID ID_2 Firist Value > >> 1 a aa TRUE 2 > >> 2 a ab FALSE NA > >> 3 a ac FALSE NA > >> 4 b aa TRUE 5 > >> 5 b ab FALSE NA > >> ", header=TRUE, as.is=TRUE ) > >> > >> sdf <- split( df1, df1$ID ) > >> # note the extra [ 1 ] in case you have more than one non-NA value # > >per ID > >> sdf2 <- lapply( sdf > >> , function( z ) { > >> z$Value <- ifelse( is.na( z$Value ) > >> , z$Value[ !is.na( z$Value ) ][ 1 > >] > >> , z$Value > >> ) > >> z > >> } > >> ) > >> df2 <- do.call( rbind, sdf2 ) > >> df2 > >> #> ID ID_2 Firist Value > >> #> a.1 a aa TRUE 2 > >> #> a.2 a ab FALSE 2 > >> #> a.3 a ac FALSE 2 > >> #> b.4 b aa TRUE 5 > >> #> b.5 b ab FALSE 5 > >> > >> # or using tidyverse methods > >> > >> library(dplyr) > >> #> > >> #> Attaching package: 'dplyr' > >> #> The following objects are masked from 'package:stats': > >> #> > >> #> filter, lag > >> #> The following objects are masked from 'package:base': > >> #> > >> #> intersect, setdiff, setequal, union > >> df3 <- ( df1 > >> %>% group_by( ID ) > >> %>% do({ > >> mutate( . > >> , Value = ifelse( is.na( Value ) > >> , Value[ !is.na( Value ) ][ 1 ] > >> , Value > >> ) > >> ) > >> }) > >> %>% ungroup > >> ) > >> df3 > >> #> # A tibble: 5 x 4 > >> #> ID ID_2 Firist Value > >> #> <chr> <chr> <lgl> <int> > >> #> 1 a aa T 2 > >> #> 2 a ab F 2 > >> #> 3 a ac F 2 > >> #> 4 b aa T 5 > >> #> 5 b ab F 5 > >> #---- > >> > >> On Sun, 7 Jan 2018, Jeff Newmiller wrote: > >> > >> > Why do you want to modify df1? > >> > > >> > Why not just reassemble the parts as a new data frame and use that > >> > going forward in your calculations? That is generally the preferred > >> > approach in R so you can re-do your calculations easily if you find > >a > >> > mistake later. > >> > -- > >> > Sent from my phone. Please excuse my brevity. > >> > > >> > On January 7, 2018 7:35:59 PM PST, Ek Esawi <esawiek at gmail.com> > >wrote: > >> >> I just came up with a solution right after i posted the question, > >but > >> >> i figured there must be a better and shorter one.than my solution > >> >> sdf1[[1]][1,4]<-lapplyresults[[1]] > >> >> sdf1[[2]][1,4]<-lapplyresults[[2]] > >> >> > >> >> EK > >> >> > >> >> On Sun, Jan 7, 2018 at 10:13 PM, Ek Esawi <esawiek at gmail.com> > >wrote: > >> >>> Hi all-- > >> >>> > >> >>> I stumbled on this problem online. I did not like the solution > >given > >> >>> there which was a long UDF. I thought why cannot split and l/s > >apply > >> >>> work here. My aim is to split the data frame, use l/sapply, make > >> >>> changes on the split lists and combine the split lists to new > >data > >> >>> frame with the desired changes/output. > >> >>> > >> >>> The data frame shown below has a column named ID which has 2 > >> >> variables > >> >>> a and b; i want to replace the NAs on the Value column by 2, > >which > >> >>> is the only numeric entry, for ID=a and by 5 for ID=b. > >> >>> > >> >>> I worked out the solution but could not replace the results in > >the > >> >> split lists. > >> >>> > >> >>> Original dataframe , df1 > >> >>> ID ID_2 Firist Value > >> >>> 1 a aa TRUE 2 > >> >>> 2 a ab FALSE NA > >> >>> 3 a ac FALSE NA > >> >>> 4 b aa TRUE 5 > >> >>> 5 b ab FALSE NA > >> >>> Sdf1 > >> >>> $a > >> >>> ID ID_2 Firist Value > >> >>> 1 a aa TRUE 2 > >> >>> 2 a ab FALSE NA > >> >>> 3 a ac FALSE NA > >> >>> $b > >> >>> ID ID_2 Firist Value > >> >>> 4 b aa TRUE 5 > >> >>> 5 b ab FALSE NA > >> >>> Desired results > >> >>> ID ID_2 Firist Value > >> >>> 1 a aa TRUE 2 > >> >>> 2 a ab FALSE 2 > >> >>> 3 a ac FALSE 2 > >> >>> > >> >>> $b > >> >>> ID ID_2 Firist Value > >> >>> 4 b aa TRUE 5 > >> >>> 5 b ab FALSE 5 > >> >>> > >> >>> My code > >> >>> > >> >>> sdf <- split(df1,df$ID) > >> >>> lapply(sdf, function(z) > >> >> ifelse(is.na(z$Value),z$Value[!is.na(z$Value)],z$Value)) > >> >>> result: > >> >>> $ a: num [1:3] 2 2 2 > >> >>> $ b: num [1:2] 5 5 > >> >>> > >> >>> How could I put these two lists back in the split data frame, > >sdf1? > >> >>> Then I could use do.call to reassemble a data frame from the > >split > >> >>> lists, > >> >>> > >> >>> Thanks, > >> >>> EK > >> >> > >> >> ______________________________________________ > >> >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> >> https://stat.ethz.ch/mailman/listinfo/r-help > >> >> PLEASE do read the posting guide > >> >> http://www.R-project.org/posting-guide.html > >> >> and provide commented, minimal, self-contained, reproducible code. > >> > > >> > ______________________________________________ > >> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> > https://stat.ethz.ch/mailman/listinfo/r-help > >> > PLEASE do read the posting guide > >> > http://www.R-project.org/posting-guide.html > >> > and provide commented, minimal, self-contained, reproducible code. > >> > > >> > >> > >----------------------------------------------------------- > ---------------- > >> Jeff Newmiller The ..... ..... Go > >Live... > >> DCN:<jdnewmil at dcn.davis.ca.us> Basics: ##.#. ##.#. Live > >Go... > >> Live: OO#.. Dead: OO#.. > >Playing > >> Research Engineer (Solar/Batteries O.O#. #.O#. with > >> /Software/Embedded Controllers) .OO#. .OO#. > >rocks...1k > >> > >> ______________________________________________ > >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> https://stat.ethz.ch/mailman/listinfo/r-help > >> PLEASE do read the posting guide > >http://www.R-project.org/posting-guide.html > >> and provide commented, minimal, self-contained, reproducible code. > > > >________________________________ > >Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou > >ur?eny pouze jeho adres?t?m. > >Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? > >neprodlen? jeho odes?latele. 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