Hi all,
I would like to use a loop for tasks that occurs repeatedly:
# Groups
# Umsatz <= 0: 1 (NICHT kaufend)
# Umsatz > 0: 2 (kaufend)
for (year in c("2011", "2012", "2013",
"2014", "2015")) {
paste0("Kunden$Kunde_real_", year) <-
(paste0("Kunden$Umsatz_", year) <= 0) * 1 +
(paste0("Kunden$Umsatz_",
year) > 0) * 2
paste0("Kunden$Kunde_real_", year) <-
factor(paste0("Kunden$Umsatz_", year),
levels = c(1, 2),
labels = c("NICHT
kaufend", "kaufend"))
}
This actually does not work due to the fact that the expression
"paste0("Kunden$Kunde_real_", year)" ist not interpreted as
a variable name by the R script language interpreter.
Is there a way to assembly variable names on the fly in R?
Regards
Georg
The direct answer to your question is to look at ?get and ? assign. The R-ish answer to your question is to store the data as elements of a list rather than separate files and use lapply() instead. Sarah On Friday, April 22, 2016, <G.Maubach at gmx.de> wrote:> Hi all, > > I would like to use a loop for tasks that occurs repeatedly: > > # Groups > # Umsatz <= 0: 1 (NICHT kaufend) > # Umsatz > 0: 2 (kaufend) > for (year in c("2011", "2012", "2013", "2014", "2015")) { > paste0("Kunden$Kunde_real_", year) <- (paste0("Kunden$Umsatz_", year) <> 0) * 1 + > (paste0("Kunden$Umsatz_", year) > > 0) * 2 > paste0("Kunden$Kunde_real_", year) <- factor(paste0("Kunden$Umsatz_", > year), > levels = c(1, 2), > labels = c("NICHT kaufend", > "kaufend")) > } > > This actually does not work due to the fact that the expression > "paste0("Kunden$Kunde_real_", year)" ist not interpreted as a variable name > by the R script language interpreter. > > Is there a way to assembly variable names on the fly in R? > > Regards > > Georg > > ______________________________________________ > R-help at r-project.org <javascript:;> mailing list -- To UNSUBSCRIBE and > more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >-- Sarah Goslee http://www.stringpage.com http://www.sarahgoslee.com http://www.functionaldiversity.org [[alternative HTML version deleted]]
Hi Georg, The " around Kunden$* looks unintentional to me. Second: haveyou considered using a long table? Then you would fill a known set of columns. Third if you must have columns based on year I believe df[[a.column.name]] will work. Best Ulrik <G.Maubach at gmx.de> schrieb am Sa., 23. Apr. 2016 07:33:> Hi all, > > I would like to use a loop for tasks that occurs repeatedly: > > # Groups > # Umsatz <= 0: 1 (NICHT kaufend) > # Umsatz > 0: 2 (kaufend) > for (year in c("2011", "2012", "2013", "2014", "2015")) { > paste0("Kunden$Kunde_real_", year) <- (paste0("Kunden$Umsatz_", year) <> 0) * 1 + > (paste0("Kunden$Umsatz_", year) > > 0) * 2 > paste0("Kunden$Kunde_real_", year) <- factor(paste0("Kunden$Umsatz_", > year), > levels = c(1, 2), > labels = c("NICHT kaufend", > "kaufend")) > } > > This actually does not work due to the fact that the expression > "paste0("Kunden$Kunde_real_", year)" ist not interpreted as a variable name > by the R script language interpreter. > > Is there a way to assembly variable names on the fly in R? > > Regards > > Georg > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]
I'm going to assume that Kunden is a data frame, and it has columns
(variables) with names like
Umstatz_2011
and that you want to create new columns with names like
Kunde_real_2011
If that is so, then try this (not tested):
for (year in 2011:2015) {
nmK <- paste0("Kunde_real_", year)
nmU <- paste0("Umsatz_", year)
cat('Creating',nmK,'from',nmU,'\n')
Kunden[[ nmK ]] <- ifelse( Kunden[[ nmU ]] <= 0, 1, 2)
Kunden[[ nmK ]] <- factor( Kunden[[ nmK ]],
levels=c(1,2),
labels= c("NICHT kaufend", "kaufend")
)
}
This little example should illustrate the method:
> foo <- data.frame(a=1:4)
> foo
a
1 1
2 2
3 3
4 4> foo[['b']] <- foo[['a']]*3
> foo
a b
1 1 3
2 2 6
3 3 9
4 4 12
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 4/22/16, 8:52 AM, "R-help on behalf of G.Maubach at gmx.de"
<r-help-bounces at r-project.org on behalf of G.Maubach at gmx.de> wrote:
>Hi all,
>
>I would like to use a loop for tasks that occurs repeatedly:
>
># Groups
># Umsatz <= 0: 1 (NICHT kaufend)
># Umsatz > 0: 2 (kaufend)
>for (year in c("2011", "2012", "2013",
"2014", "2015")) {
> paste0("Kunden$Kunde_real_", year) <-
(paste0("Kunden$Umsatz_", year)
><= 0) * 1 +
> (paste0("Kunden$Umsatz_",
year) >
> 0) * 2
> paste0("Kunden$Kunde_real_", year) <-
factor(paste0("Kunden$Umsatz_",
>year),
> levels = c(1, 2),
> labels = c("NICHT
>kaufend", "kaufend"))
> }
>
>This actually does not work due to the fact that the expression
>"paste0("Kunden$Kunde_real_", year)" ist not interpreted
as a variable
>name by the R script language interpreter.
>
>Is there a way to assembly variable names on the fly in R?
>
>Regards
>
>Georg
>
>______________________________________________
>R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
G.Maubach at weinwolf.de
2016-Apr-26 06:44 UTC
[R] Antwort: Fw: Re: Creating variables on the fly (SOLVED)
Hi Don,
Hi to all readers,
many thanks for all your answers and all your help.
I adapted Don's code to my data and Don's code does the trick:
str(Kunden01)
for (year in 2011:2015) {
Reeller_Kunde <- paste0("Reeller_Kunde_", year)
Umsatz <- paste0("Umsatz_", year)
cat('Creating', Reeller_Kunde,'from', Umsatz,'\n')
Kunden01[[ Reeller_Kunde ]] <- ifelse( Kunden01[[ Umsatz ]] >= 0, 1, 2)
Kunden01[[ Reeller_Kunde ]] <- factor( Kunden01[[ Reeller_Kunde ]],
levels=c(1,2),
labels= c("NICHT kaufend",
"kaufend")
)
}
str(Kunden01)
This way a new variable is created by building it from a string
concatenation.
I also like the cat() function to document the process within the loop
while running the program.
Many thanks for your help.
Kind regards
Georg
Von: G.Maubach at gmx.de
An: g.maubach at weinwolf.de,
Datum: 25.04.2016 21:37
Betreff: Fw: Re: [R] Creating variables on the fly
> Gesendet: Montag, 25. April 2016 um 19:35 Uhr
> Von: "MacQueen, Don" <macqueen1 at llnl.gov>
> An: "G.Maubach at gmx.de" <G.Maubach at gmx.de>,
"r-help at r-project.org"
<r-help at r-project.org>> Betreff: Re: [R] Creating variables on the fly
>
> I'm going to assume that Kunden is a data frame, and it has columns
> (variables) with names like
> Umstatz_2011
> and that you want to create new columns with names like
> Kunde_real_2011
>
> If that is so, then try this (not tested):
>
> for (year in 2011:2015) {
> nmK <- paste0("Kunde_real_", year)
> nmU <- paste0("Umsatz_", year)
> cat('Creating',nmK,'from',nmU,'\n')
> Kunden[[ nmK ]] <- ifelse( Kunden[[ nmU ]] <= 0, 1, 2)
> Kunden[[ nmK ]] <- factor( Kunden[[ nmK ]],
> levels=c(1,2),
> labels= c("NICHT kaufend", "kaufend")
> )
>
> }
>
> This little example should illustrate the method:
>
>
> > foo <- data.frame(a=1:4)
> > foo
> a
> 1 1
> 2 2
> 3 3
> 4 4
> > foo[['b']] <- foo[['a']]*3
> > foo
> a b
> 1 1 3
> 2 2 6
> 3 3 9
> 4 4 12
>
>
>
> --
> Don MacQueen
>
> Lawrence Livermore National Laboratory
> 7000 East Ave., L-627
> Livermore, CA 94550
> 925-423-1062
>
>
>
>
>
> On 4/22/16, 8:52 AM, "R-help on behalf of G.Maubach at gmx.de"
> <r-help-bounces at r-project.org on behalf of G.Maubach at gmx.de>
wrote:
>
> >Hi all,
> >
> >I would like to use a loop for tasks that occurs repeatedly:
> >
> ># Groups
> ># Umsatz <= 0: 1 (NICHT kaufend)
> ># Umsatz > 0: 2 (kaufend)
> >for (year in c("2011", "2012", "2013",
"2014", "2015")) {
> > paste0("Kunden$Kunde_real_", year) <-
(paste0("Kunden$Umsatz_", year)
> ><= 0) * 1 +
> >
(paste0("Kunden$Umsatz_", year)
>
> > 0) * 2
> > paste0("Kunden$Kunde_real_", year) <-
factor(paste0("Kunden$Umsatz_",
> >year),
> > levels = c(1, 2),
> > labels = c("NICHT
> >kaufend", "kaufend"))
> > }
> >
> >This actually does not work due to the fact that the expression
> >"paste0("Kunden$Kunde_real_", year)" ist not
interpreted as a variable
> >name by the R script language interpreter.
> >
> >Is there a way to assembly variable names on the fly in R?
> >
> >Regards
> >
> >Georg
> >
> >______________________________________________
> >R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> >https://stat.ethz.ch/mailman/listinfo/r-help
> >PLEASE do read the posting guide
> >http://www.R-project.org/posting-guide.html
> >and provide commented, minimal, self-contained, reproducible code.
>
>
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