R help - Jan 2015 - problem with conditional column sums

Hi, 

  I think you need quotation around I like the
following:
> status
   2010 2011 2012
1     A    A    A
2     A    I    I
3     A    A    A
4     U    U    U
5     A    A    A
6     I    I    I
7     U    I    I
8     A    U    A
9     I    A    U
10    I    I    I
> apply(start,2,function(x) {sum(x=="I",na.rm=TRUE)})
X2010 X2011 X2012 
    3     4     4 



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Or, you can also do the same job using 'colSums()' as shown in the
below:

 > colSums(status=="I")
2010 2011 2012
    3    4    4
 >

I hope this helps.

Chel Hee Lee

On 1/28/2015 7:31 PM, JSHuang wrote:
> Hi,
>
>    I think you need quotation around I like the following:
>> status
>     2010 2011 2012
> 1     A    A    A
> 2     A    I    I
> 3     A    A    A
> 4     U    U    U
> 5     A    A    A
> 6     I    I    I
> 7     U    I    I
> 8     A    U    A
> 9     I    A    U
> 10    I    I    I
>> apply(start,2,function(x) {sum(x=="I",na.rm=TRUE)})
> X2010 X2011 X2012
>      3     4     4
>
>
>
> --
> View this message in context:
http://r.789695.n4.nabble.com/problem-with-conditional-column-sums-tp4702426p4702434.html
> Sent from the R help mailing list archive at Nabble.com.
>
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