R devel - Mar 2002 - should lapply preserve attributes?

I have an application where I need to preserve object attributes across
calls to 'lapply'. The current definition is:

lapply <- function (X, FUN, ...) 
{
    FUN <- match.fun(FUN)
    if (!is.list(X)) 
        X <- as.list(X)
    rval <- .Internal(lapply(X, FUN))
    names(rval) <- names(X)
    return(rval)
}

Would it make sense to replace

	names(rval) <- names(X)

with

	attributes(rval) <- attributes(X)

?? I can, of course, make a local function for this, but wondered if
this change would be useful in general.

Cheers,
Tim

-- 
Timothy H. Keitt
Department of Ecology and Evolution
State University of New York at Stony Brook
Stony Brook, New York 11794 USA
Phone: 631-632-1101, FAX: 631-632-7626
http://life.bio.sunysb.edu/ee/keitt/
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On 19 Mar 2002, Timothy H. Keitt wrote:
> I have an application where I need to preserve object attributes across
> calls to 'lapply'. The current definition is:
>
> lapply <- function (X, FUN, ...)
> {
>     FUN <- match.fun(FUN)
>     if (!is.list(X))
>         X <- as.list(X)
>     rval <- .Internal(lapply(X, FUN))
>     names(rval) <- names(X)
>     return(rval)
> }
>
> Would it make sense to replace
>
> 	names(rval) <- names(X)
>
> with
>
> 	attributes(rval) <- attributes(X)
>
> ?? I can, of course, make a local function for this, but wondered if
> this change would be useful in general.
No, it would be positively harmful.  X might be a data frame, or a time
series .., but rval is only guaranteed to be the same length as X.  If you
know more, adjust the object returned by lapply.

-- 
Brian D. Ripley,                  ripley@stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford,             Tel:  +44 1865 272861 (self)
1 South Parks Road,                     +44 1865 272860 (secr)
Oxford OX1 3TG, UK                Fax:  +44 1865 272595

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