llvm dev - Jan 2017 - Weak symbol/alias semantics

Hi,

I believe we should get it right (and simpler) if (when…) we move to the
representation we discussed last spring:
https://llvm.org/bugs/show_bug.cgi?id=27866
<https://llvm.org/bugs/show_bug.cgi?id=27866>

Our conclusion was that we should always have alias pointing to private
anonymous and nothing else, so when we currently have:

@a = global i32 0
@b = alias @a

It should always become:

@0 = private i32 0
@a = alias @0
@b = alias @0


— 
Mehdi


> On Jan 13, 2017, at 3:21 PM, Peter Collingbourne <peter at pcc.me.uk>
wrote:
> 
> Hi Teresa,
> 
> I think that to answer your question correctly it is helpful to consider
what is going on at the object file level. For your test1.c we conceptually have
a .text section containing the body of f, and then three symbols:
> 
> .weak f
> f = .text
> .globl strongalias
> strongalias = .text
> .weak weakalias
> weakalias = .text
> 
> Note that f, strongalias and weakalias are not related at all, except that
they happen to point to the same place. If f is overridden by a symbol in
another object file, it does not affect the symbols strongalias and weakalias,
so we still need to make them point to .text. I don't think it would be
right to make strongalias and weakalias into copies of f, as that would be
observable through function pointer equality. Most likely all you need to do is
to internalize f and keep strongalias and weakalias as aliases of f.
> 
> If we're resolving strongalias to f at -O2, that seems like a bug to
me. We can probably only resolve an alias to the symbol it references if we are
guaranteed that both symbols will have the same resolution, i.e. we must check
at least that both symbols have strong or internal linkage. If we cared about
symbol interposition, we might also want to check that both symbols have
non-default visibility, but I think that our support for that is still a little
fuzzy at the moment.
> 
> Thanks,
> Peter
> 
> On Fri, Jan 13, 2017 at 2:33 PM, Teresa Johnson <tejohnson at google.com
<mailto:tejohnson at google.com>> wrote:
> Hi Mehdi, Peter and David (and anyone else who sees this),
> 
> I've been playing with some examples to handle the weak symbol cases we
discussed in IRC earlier this week in the context of D28523. I was going to
implement the support for turning aliases into copies in order to enable
performing thinLTOResolveWeakForLinkerGUID on both aliases and aliasees, as a
first step to being able to drop non-prevailing weak symbols in ThinLTO
backends.
> 
> I was wondering though what happens if we have an alias, which may or may
not be weak itself, to a non-odr weak symbol that isn't prevailing. In that
case, do we eventually want references via the alias to go to the prevailing
copy (in another module), or to the original copy in the alias's module? I
looked at some examples without ThinLTO, and am a little confused. Current
(non-ThinLTO) behavior in some cases seems to depend on opt level.
> 
> Example:
> 
> $ cat weak12main.c
> extern void test2();
> int main() {
>   test2();
> }
> 
> $ cat weak1.c
> #include <stdio.h>
> 
> void weakalias() __attribute__((weak, alias ("f")));
> void strongalias() __attribute__((alias ("f")));
> 
> void f () __attribute__ ((weak));
> void f()
> {
>   printf("In weak1.c:f\n");
> }
> void test1() {
>   printf("Call f() from weak1.c:\n");
>   f();
>   printf("Call weakalias() from weak1.c:\n");
>   weakalias();
>   printf("Call strongalias() from weak1.c:\n");
>   strongalias();
> }
> 
> $ cat weak2.c
> #include <stdio.h>
> 
> void f () __attribute__ ((weak));
> void f()
> {
>   printf("In weak2.c:f\n");
> }
> extern void test1();
> void test2()
> {
>   test1();
>   printf("Call f() from weak2.c\n");
>   f();
> }
> 
> If I link weak1.c before weak2.c, nothing is surprising (we always invoke
weak1.c:f at both -O0 and -O2):
> 
> $ clang weak12main.c weak1.c weak2.c -O0
> $ a.out
> Call f() from weak1.c:
> In weak1.c:f
> Call weakalias() from weak1.c:
> In weak1.c:f
> Call strongalias() from weak1.c:
> In weak1.c:f
> Call f() from weak2.c
> In weak1.c:f
> 
> $ clang weak12main.c weak1.c weak2.c -O2
> $ a.out
> Call f() from weak1.c:
> In weak1.c:f
> Call weakalias() from weak1.c:
> In weak1.c:f
> Call strongalias() from weak1.c:
> In weak1.c:f
> Call f() from weak2.c
> In weak1.c:f
> 
> If I instead link weak2.c first, so it's copy of f() is prevailing, I
still get weak1.c:f for the call via weakalias() (both opt levels), and for
strongalias() when building at -O0. At -O2 the compiler replaces the call to
strongalias() with a call to f(), so it get's the weak2 copy in that case.
> 
> $ clang weak12main.c weak2.c weak1.c -O2
> $ a.out
> Call f() from weak1.c:
> In weak2.c:f
> Call weakalias() from weak1.c:
> In weak1.c:f
> Call strongalias() from weak1.c:
> In weak2.c:f
> Call f() from weak2.c
> In weak2.c:f
> 
> $ clang weak12main.c weak2.c weak1.c -O0
> $ a.out
> Call f() from weak1.c:
> In weak2.c:f
> Call weakalias() from weak1.c:
> In weak1.c:f
> Call strongalias() from weak1.c:
> In weak1.c:f
> Call f() from weak2.c
> In weak2.c:f
> 
> I'm wondering what the expected/correct behavior is? Depending on what
is correct, we need to handle this differently in ThinLTO mode. Let's say
weak1.c's copy of f() is not prevailing and I am going to drop it (it needs
to be removed completely, not turned into available_externally to ensure it
isn't inlined since weak isInterposable). If we want the aliases in weak1.c
to reference the original version, then copying is correct (e.g. weakalias and
strong alias would each become a copy of weak1.c's f()). If we however want
them to resolve to the prevailing copy of f(), then we need to turn the aliases
into declarations (external linkage in the case of strongalias and external weak
in the case of weakalias?).
> 
> I also tried the case where f() was in a comdat, because I also need to
handle that case in ThinLTO (when f() is not prevailing, drop it from the comdat
and remove the comdat from that module). Interestingly, in this case when
weak2.c is prevailing, I get the following warning when linking and get a seg
fault at runtime:
> 
> weak1.o:weak1.o:function test1: warning: relocation refers to discarded
section
> 
> Presumably the aliases still refer to the copy in weak1.c, which is in the
comdat that gets dropped by the linker. So is it not legal to have an alias to a
weak symbol in a comdat (i.e. alias from outside the comdat)? We don't
complain in the compiler.
> 
> Thanks,
> Teresa
> -- 
> Teresa Johnson |	 Software Engineer |	 tejohnson at google.com
<mailto:tejohnson at google.com> |	 408-460-2413
<tel:(408)%20460-2413>
> 
> 
> -- 
> -- 
> Peter
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On Fri, Jan 13, 2017 at 9:54 PM, Mehdi Amini <mehdi.amini at apple.com>
wrote:
> Hi,
>
> I believe we should get it right (and simpler) if (when…) we move to the
> representation we discussed last spring: https://llvm.org/bugs/
> show_bug.cgi?id=27866
>
> Our conclusion was that we should always have alias pointing to private
> anonymous and nothing else, so when we currently have:
>
> @a = global i32 0
> @b = alias @a
>
> It should always become:
>
> @0 = private i32 0
> @a = alias @0
> @b = alias @0
>
Yes that has some nice properties. I think it makes at least one case
harder though.

Consider:

1) Original:
define linkonce_odr void @a() { ... }
@b = linkonce_odr alias void (), void ()* @a

2) In the proposed canonical form this becomes:
define private void @0() { ... }
@a = linkonce_odr alias void (), void ()* @0
@b = linkonce_odr alias void (), void ()* @0

And let's say @a and @b are both non-prevailing in this module. I think we
lose inlining ability for these functions when we start dropping
non-prevailing copies.

In 1) we could transform this (as described in my earlier email) to:

define available_externally void @a() { ... }
/* RAUW @b with @a */

and we can inline @a into all callsites (which includes calls original via
@b), before dropping it.

With 2), I think we would need to transform this to:

define private void @0() { ... }
declare void @a()
declare void @b()

and we no longer can inline calls to @a and @b. I suppose we could
intervene and special case this scenario so that it is transformed as for
1) when there are non-prevailing odr aliases.

I need to think through the various permutations of linkage types and see
how they get transformed in the current and proposed canonical forms to see
if there are other cases that need special handling.

Teresa


>
> —
> Mehdi
>
>
>
> On Jan 13, 2017, at 3:21 PM, Peter Collingbourne <peter at pcc.me.uk>
wrote:
>
> Hi Teresa,
>
> I think that to answer your question correctly it is helpful to consider
> what is going on at the object file level. For your test1.c we conceptually
> have a .text section containing the body of f, and then three symbols:
>
> .weak f
> f = .text
> .globl strongalias
> strongalias = .text
> .weak weakalias
> weakalias = .text
>
> Note that f, strongalias and weakalias are not related at all, except that
> they happen to point to the same place. If f is overridden by a symbol in
> another object file, it does not affect the symbols strongalias and
> weakalias, so we still need to make them point to .text. I don't think
it
> would be right to make strongalias and weakalias into copies of f, as that
> would be observable through function pointer equality. Most likely all you
> need to do is to internalize f and keep strongalias and weakalias as
> aliases of f.
>
> If we're resolving strongalias to f at -O2, that seems like a bug to
me.
> We can probably only resolve an alias to the symbol it references if we are
> guaranteed that both symbols will have the same resolution, i.e. we must
> check at least that both symbols have strong or internal linkage. If we
> cared about symbol interposition, we might also want to check that both
> symbols have non-default visibility, but I think that our support for that
> is still a little fuzzy at the moment.
>
> Thanks,
> Peter
>
> On Fri, Jan 13, 2017 at 2:33 PM, Teresa Johnson <tejohnson at
google.com>
> wrote:
>
>> Hi Mehdi, Peter and David (and anyone else who sees this),
>>
>> I've been playing with some examples to handle the weak symbol
cases we
>> discussed in IRC earlier this week in the context of D28523. I was
going to
>> implement the support for turning aliases into copies in order to
enable
>> performing thinLTOResolveWeakForLinkerGUID on both aliases and
aliasees,
>> as a first step to being able to drop non-prevailing weak symbols in
>> ThinLTO backends.
>>
>> I was wondering though what happens if we have an alias, which may or
may
>> not be weak itself, to a non-odr weak symbol that isn't prevailing.
In that
>> case, do we eventually want references via the alias to go to the
>> prevailing copy (in another module), or to the original copy in the
alias's
>> module? I looked at some examples without ThinLTO, and am a little
>> confused. Current (non-ThinLTO) behavior in some cases seems to depend
on
>> opt level.
>>
>> Example:
>>
>> $ cat weak12main.c
>> extern void test2();
>> int main() {
>>   test2();
>> }
>>
>> $ cat weak1.c
>> #include <stdio.h>
>>
>> void weakalias() __attribute__((weak, alias ("f")));
>> void strongalias() __attribute__((alias ("f")));
>>
>> void f () __attribute__ ((weak));
>> void f()
>> {
>>   printf("In weak1.c:f\n");
>> }
>> void test1() {
>>   printf("Call f() from weak1.c:\n");
>>   f();
>>   printf("Call weakalias() from weak1.c:\n");
>>   weakalias();
>>   printf("Call strongalias() from weak1.c:\n");
>>   strongalias();
>> }
>>
>> $ cat weak2.c
>> #include <stdio.h>
>>
>> void f () __attribute__ ((weak));
>> void f()
>> {
>>   printf("In weak2.c:f\n");
>> }
>> extern void test1();
>> void test2()
>> {
>>   test1();
>>   printf("Call f() from weak2.c\n");
>>   f();
>> }
>>
>> If I link weak1.c before weak2.c, nothing is surprising (we always
invoke
>> weak1.c:f at both -O0 and -O2):
>>
>> $ clang weak12main.c weak1.c weak2.c -O0
>> $ a.out
>> Call f() from weak1.c:
>> In weak1.c:f
>> Call weakalias() from weak1.c:
>> In weak1.c:f
>> Call strongalias() from weak1.c:
>> In weak1.c:f
>> Call f() from weak2.c
>> In weak1.c:f
>>
>> $ clang weak12main.c weak1.c weak2.c -O2
>> $ a.out
>> Call f() from weak1.c:
>> In weak1.c:f
>> Call weakalias() from weak1.c:
>> In weak1.c:f
>> Call strongalias() from weak1.c:
>> In weak1.c:f
>> Call f() from weak2.c
>> In weak1.c:f
>>
>> If I instead link weak2.c first, so it's copy of f() is prevailing,
I
>> still get weak1.c:f for the call via weakalias() (both opt levels), and
for
>> strongalias() when building at -O0. At -O2 the compiler replaces the
call
>> to strongalias() with a call to f(), so it get's the weak2 copy in
that
>> case.
>>
>> $ clang weak12main.c weak2.c weak1.c -O2
>> $ a.out
>> Call f() from weak1.c:
>> In weak2.c:f
>> Call weakalias() from weak1.c:
>> In weak1.c:f
>> Call strongalias() from weak1.c:
>> In weak2.c:f
>> Call f() from weak2.c
>> In weak2.c:f
>>
>> $ clang weak12main.c weak2.c weak1.c -O0
>> $ a.out
>> Call f() from weak1.c:
>> In weak2.c:f
>> Call weakalias() from weak1.c:
>> In weak1.c:f
>> Call strongalias() from weak1.c:
>> In weak1.c:f
>> Call f() from weak2.c
>> In weak2.c:f
>>
>> I'm wondering what the expected/correct behavior is? Depending on
what is
>> correct, we need to handle this differently in ThinLTO mode. Let's
say
>> weak1.c's copy of f() is not prevailing and I am going to drop it
(it needs
>> to be removed completely, not turned into available_externally to
ensure it
>> isn't inlined since weak isInterposable). If we want the aliases in
weak1.c
>> to reference the original version, then copying is correct (e.g.
weakalias
>> and strong alias would each become a copy of weak1.c's f()). If we
however
>> want them to resolve to the prevailing copy of f(), then we need to
turn
>> the aliases into declarations (external linkage in the case of
strongalias
>> and external weak in the case of weakalias?).
>>
>> I also tried the case where f() was in a comdat, because I also need to
>> handle that case in ThinLTO (when f() is not prevailing, drop it from
the
>> comdat and remove the comdat from that module). Interestingly, in this
case
>> when weak2.c is prevailing, I get the following warning when linking
and
>> get a seg fault at runtime:
>>
>> weak1.o:weak1.o:function test1: warning: relocation refers to discarded
>> section
>>
>> Presumably the aliases still refer to the copy in weak1.c, which is in
>> the comdat that gets dropped by the linker. So is it not legal to have
an
>> alias to a weak symbol in a comdat (i.e. alias from outside the
comdat)? We
>> don't complain in the compiler.
>>
>> Thanks,
>> Teresa
>> --
>> Teresa Johnson |  Software Engineer |  tejohnson at google.com |
>> 408-460-2413 <(408)%20460-2413>
>>
>
>
>
> --
> --
> Peter
>
>
>

-- 
Teresa Johnson |  Software Engineer |  tejohnson at google.com |  408-460-2413
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> On Jan 14, 2017, at 8:14 AM, Teresa Johnson <tejohnson at google.com>
wrote:
> 
> 
> 
> On Fri, Jan 13, 2017 at 9:54 PM, Mehdi Amini <mehdi.amini at apple.com
<mailto:mehdi.amini at apple.com>> wrote:
> Hi,
> 
> I believe we should get it right (and simpler) if (when…) we move to the
representation we discussed last spring:
https://llvm.org/bugs/show_bug.cgi?id=27866
<https://llvm.org/bugs/show_bug.cgi?id=27866>
> 
> Our conclusion was that we should always have alias pointing to private
anonymous and nothing else, so when we currently have:
> 
> @a = global i32 0
> @b = alias @a
> 
> It should always become:
> 
> @0 = private i32 0
> @a = alias @0
> @b = alias @0
> 
> Yes that has some nice properties. I think it makes at least one case
harder though.
> 
> Consider:
> 
> 1) Original: 
> define linkonce_odr void @a() { ... }
> @b = linkonce_odr alias void (), void ()* @a
> 
> 2) In the proposed canonical form this becomes:
> define private void @0() { ... }
> @a = linkonce_odr alias void (), void ()* @0
> @b = linkonce_odr alias void (), void ()* @0
> 
> And let's say @a and @b are both non-prevailing in this module. I think
we lose inlining ability for these functions when we start dropping
non-prevailing copies.
> 
> In 1) we could transform this (as described in my earlier email) to:
> 
> define available_externally void @a() { ... }
> /* RAUW @b with @a */
> 
> and we can inline @a into all callsites (which includes calls original via
@b), before dropping it.
> 
> With 2), I think we would need to transform this to:
> 
> define private void @0() { ... }
> declare void @a()
> declare void @b()
> 
> and we no longer can inline calls to @a and @b. I suppose we could
intervene and special case this scenario so that it is transformed as for 1)
when there are non-prevailing odr aliases.
The complication is that a cloneFunction() step would be needed right?

Alternatively I can imagine us allowing available_externally alias, I’m not sure
why they are forbidden today other than because we map the object-level
limitations in the IR, but I can miss something (we don’t have alias on Darwin
either…).

— 
Mehdi

> 
> I need to think through the various permutations of linkage types and see
how they get transformed in the current and proposed canonical forms to see if
there are other cases that need special handling.
> 
> Teresa
> 
> 
> 
> 
> — 
> Mehdi
> 
> 
> 
>> On Jan 13, 2017, at 3:21 PM, Peter Collingbourne <peter at pcc.me.uk
<mailto:peter at pcc.me.uk>> wrote:
>> 
>> Hi Teresa,
>> 
>> I think that to answer your question correctly it is helpful to
consider what is going on at the object file level. For your test1.c we
conceptually have a .text section containing the body of f, and then three
symbols:
>> 
>> .weak f
>> f = .text
>> .globl strongalias
>> strongalias = .text
>> .weak weakalias
>> weakalias = .text
>> 
>> Note that f, strongalias and weakalias are not related at all, except
that they happen to point to the same place. If f is overridden by a symbol in
another object file, it does not affect the symbols strongalias and weakalias,
so we still need to make them point to .text. I don't think it would be
right to make strongalias and weakalias into copies of f, as that would be
observable through function pointer equality. Most likely all you need to do is
to internalize f and keep strongalias and weakalias as aliases of f.
>> 
>> If we're resolving strongalias to f at -O2, that seems like a bug
to me. We can probably only resolve an alias to the symbol it references if we
are guaranteed that both symbols will have the same resolution, i.e. we must
check at least that both symbols have strong or internal linkage. If we cared
about symbol interposition, we might also want to check that both symbols have
non-default visibility, but I think that our support for that is still a little
fuzzy at the moment.
>> 
>> Thanks,
>> Peter
>> 
>> On Fri, Jan 13, 2017 at 2:33 PM, Teresa Johnson <tejohnson at
google.com <mailto:tejohnson at google.com>> wrote:
>> Hi Mehdi, Peter and David (and anyone else who sees this),
>> 
>> I've been playing with some examples to handle the weak symbol
cases we discussed in IRC earlier this week in the context of D28523. I was
going to implement the support for turning aliases into copies in order to
enable performing thinLTOResolveWeakForLinkerGUID on both aliases and aliasees,
as a first step to being able to drop non-prevailing weak symbols in ThinLTO
backends.
>> 
>> I was wondering though what happens if we have an alias, which may or
may not be weak itself, to a non-odr weak symbol that isn't prevailing. In
that case, do we eventually want references via the alias to go to the
prevailing copy (in another module), or to the original copy in the alias's
module? I looked at some examples without ThinLTO, and am a little confused.
Current (non-ThinLTO) behavior in some cases seems to depend on opt level.
>> 
>> Example:
>> 
>> $ cat weak12main.c
>> extern void test2();
>> int main() {
>>   test2();
>> }
>> 
>> $ cat weak1.c
>> #include <stdio.h>
>> 
>> void weakalias() __attribute__((weak, alias ("f")));
>> void strongalias() __attribute__((alias ("f")));
>> 
>> void f () __attribute__ ((weak));
>> void f()
>> {
>>   printf("In weak1.c:f\n");
>> }
>> void test1() {
>>   printf("Call f() from weak1.c:\n");
>>   f();
>>   printf("Call weakalias() from weak1.c:\n");
>>   weakalias();
>>   printf("Call strongalias() from weak1.c:\n");
>>   strongalias();
>> }
>> 
>> $ cat weak2.c
>> #include <stdio.h>
>> 
>> void f () __attribute__ ((weak));
>> void f()
>> {
>>   printf("In weak2.c:f\n");
>> }
>> extern void test1();
>> void test2()
>> {
>>   test1();
>>   printf("Call f() from weak2.c\n");
>>   f();
>> }
>> 
>> If I link weak1.c before weak2.c, nothing is surprising (we always
invoke weak1.c:f at both -O0 and -O2):
>> 
>> $ clang weak12main.c weak1.c weak2.c -O0
>> $ a.out
>> Call f() from weak1.c:
>> In weak1.c:f
>> Call weakalias() from weak1.c:
>> In weak1.c:f
>> Call strongalias() from weak1.c:
>> In weak1.c:f
>> Call f() from weak2.c
>> In weak1.c:f
>> 
>> $ clang weak12main.c weak1.c weak2.c -O2
>> $ a.out
>> Call f() from weak1.c:
>> In weak1.c:f
>> Call weakalias() from weak1.c:
>> In weak1.c:f
>> Call strongalias() from weak1.c:
>> In weak1.c:f
>> Call f() from weak2.c
>> In weak1.c:f
>> 
>> If I instead link weak2.c first, so it's copy of f() is prevailing,
I still get weak1.c:f for the call via weakalias() (both opt levels), and for
strongalias() when building at -O0. At -O2 the compiler replaces the call to
strongalias() with a call to f(), so it get's the weak2 copy in that case.
>> 
>> $ clang weak12main.c weak2.c weak1.c -O2
>> $ a.out
>> Call f() from weak1.c:
>> In weak2.c:f
>> Call weakalias() from weak1.c:
>> In weak1.c:f
>> Call strongalias() from weak1.c:
>> In weak2.c:f
>> Call f() from weak2.c
>> In weak2.c:f
>> 
>> $ clang weak12main.c weak2.c weak1.c -O0
>> $ a.out
>> Call f() from weak1.c:
>> In weak2.c:f
>> Call weakalias() from weak1.c:
>> In weak1.c:f
>> Call strongalias() from weak1.c:
>> In weak1.c:f
>> Call f() from weak2.c
>> In weak2.c:f
>> 
>> I'm wondering what the expected/correct behavior is? Depending on
what is correct, we need to handle this differently in ThinLTO mode. Let's
say weak1.c's copy of f() is not prevailing and I am going to drop it (it
needs to be removed completely, not turned into available_externally to ensure
it isn't inlined since weak isInterposable). If we want the aliases in
weak1.c to reference the original version, then copying is correct (e.g.
weakalias and strong alias would each become a copy of weak1.c's f()). If we
however want them to resolve to the prevailing copy of f(), then we need to turn
the aliases into declarations (external linkage in the case of strongalias and
external weak in the case of weakalias?).
>> 
>> I also tried the case where f() was in a comdat, because I also need to
handle that case in ThinLTO (when f() is not prevailing, drop it from the comdat
and remove the comdat from that module). Interestingly, in this case when
weak2.c is prevailing, I get the following warning when linking and get a seg
fault at runtime:
>> 
>> weak1.o:weak1.o:function test1: warning: relocation refers to discarded
section
>> 
>> Presumably the aliases still refer to the copy in weak1.c, which is in
the comdat that gets dropped by the linker. So is it not legal to have an alias
to a weak symbol in a comdat (i.e. alias from outside the comdat)? We don't
complain in the compiler.
>> 
>> Thanks,
>> Teresa
>> -- 
>> Teresa Johnson |	 Software Engineer |	 tejohnson at google.com
<mailto:tejohnson at google.com> |	 408-460-2413
<tel:(408)%20460-2413>
>> 
>> 
>> -- 
>> -- 
>> Peter
> 
> 
> 
> 
> -- 
> Teresa Johnson |	 Software Engineer |	 tejohnson at google.com
<mailto:tejohnson at google.com> |	 408-460-2413
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Mehdi Amini via llvm-dev <llvm-dev at lists.llvm.org> writes:
> Hi,
>
> I believe we should get it right (and simpler) if (when…) we move to the
representation we discussed last spring:
https://llvm.org/bugs/show_bug.cgi?id=27866
<https://llvm.org/bugs/show_bug.cgi?id=27866>
>
> Our conclusion was that we should always have alias pointing to private
anonymous and nothing else, so when we currently have:
>
> @a = global i32 0
> @b = alias @a
>
> It should always become:
>
> @0 = private i32 0
> @a = alias @0
> @b = alias @0
Yes, that would be awesome :-)

Cheers,
Rafael