llvm dev - Jan 2011 - [LLVMdev] llvm::Pass::Pass(llvm::PassKind, intptr_t): Assertion `pid && "pid cannot be 0"' failed.

I have written a new pass, it compiles ok but crashes when i run it
with error (llvm::Pass::Pass(llvm::PassKind, intptr_t): Assertion `pid
&& "pid cannot be 0"' failed.).

The pass is :

using namespace llvm;
namespace
{
  struct Dfl : public FunctionPass {
    static char ID;
    Dfl() : FunctionPass(ID) { }
    virtual bool runOnFunction(Function &F) {
      bool modified=false;
      errs() << "In Dfl for Function : " << F.getName();
      if (F.empty()) errs() << " is empty."  <<
"\n";
      else errs()  << "\n";
      return modified;
    };
    // pass interface to other passes
    virtual void getAnalysisUsage(AnalysisUsage &AU) const {
       AU.setPreservesAll();
       AU.addRequired<DominatorTree>();
    }
  };  // end struc Dfl
  // Identifier variable for the pass
  char Dfl::ID = 0;
  // Register the pass
  static RegisterPass<Dfl> X("dfl","emit cfg in dfl
format"
                             , false, false);
}

llvm/include/llvm/Pass.h:93: llvm::Pass::Pass(llvm::PassKind,
intptr_t): Assertion `pid && "pid cannot be 0"' failed.


On Mon, Jan 31, 2011 at 3:55 PM, Surinder <surifilms at gmail.com>
wrote:
> I have written a new pass, it compiles ok but crashes when i run it
> with error (llvm::Pass::Pass(llvm::PassKind, intptr_t): Assertion `pid
> && "pid cannot be 0"' failed.).
>
> The pass is :
>
> using namespace llvm;
> namespace
> {
>  struct Dfl : public FunctionPass {
>    static char ID;
>    Dfl() : FunctionPass(ID) { }
>    virtual bool runOnFunction(Function &F) {
>      bool modified=false;
>      errs() << "In Dfl for Function : " <<
F.getName();
>      if (F.empty()) errs() << " is empty."  <<
"\n";
>      else errs()  << "\n";
>      return modified;
>    };
>    // pass interface to other passes
>    virtual void getAnalysisUsage(AnalysisUsage &AU) const {
>       AU.setPreservesAll();
>       AU.addRequired<DominatorTree>();
>    }
>  };  // end struc Dfl
>  // Identifier variable for the pass
>  char Dfl::ID = 0;
>  // Register the pass
>  static RegisterPass<Dfl> X("dfl","emit cfg in dfl
format"
>                             , false, false);
> }
>

Got the solution, &ID and not ID should be passed to  Dfl() :
FunctionPass(&ID) { }

On Mon, Jan 31, 2011 at 3:57 PM, Surinder <surifilms at gmail.com>
wrote:
> llvm/include/llvm/Pass.h:93: llvm::Pass::Pass(llvm::PassKind,
> intptr_t): Assertion `pid && "pid cannot be 0"'
failed.
>
>
> On Mon, Jan 31, 2011 at 3:55 PM, Surinder <surifilms at gmail.com>
wrote:
>> I have written a new pass, it compiles ok but crashes when i run it
>> with error (llvm::Pass::Pass(llvm::PassKind, intptr_t): Assertion `pid
>> && "pid cannot be 0"' failed.).
>>
>> The pass is :
>>
>> using namespace llvm;
>> namespace
>> {
>>  struct Dfl : public FunctionPass {
>>    static char ID;
>>    Dfl() : FunctionPass(ID) { }
>>    virtual bool runOnFunction(Function &F) {
>>      bool modified=false;
>>      errs() << "In Dfl for Function : " <<
F.getName();
>>      if (F.empty()) errs() << " is empty."  <<
"\n";
>>      else errs()  << "\n";
>>      return modified;
>>    };
>>    // pass interface to other passes
>>    virtual void getAnalysisUsage(AnalysisUsage &AU) const {
>>       AU.setPreservesAll();
>>       AU.addRequired<DominatorTree>();
>>    }
>>  };  // end struc Dfl
>>  // Identifier variable for the pass
>>  char Dfl::ID = 0;
>>  // Register the pass
>>  static RegisterPass<Dfl> X("dfl","emit cfg in dfl
format"
>>                             , false, false);
>> }
>>
>