Hi,
I have a Linux machine with kernel 2.6 and 3 network cards. I would
like to ask what rules should I have in the routing table so that:
192.168.254.0/25 is routed through eth1
192.168.254.128/25 is routed through eth2
eth0 is my internal interface and eth1/eth2 are the external
interfaces.
* What is particulary specific for this case is that ipaddr_eth1 is in
the same network as ipaddr_eth2 and that ipaddr_gateway_eth1 is the
same as ipaddr_gateway_eth2.
Here is what I have done so far:
r2 root # ip rule ls
0: from all lookup local
32764: from 192.168.254.0/25 lookup 230
32765: from 192.168.254.128/25 lookup 231
32766: from all lookup main
32767: from all lookup default
r2 root # ip route ls
A.B.C.0/24 dev eth2 proto kernel scope link src A.B.C.X
A.B.C.0/24 dev eth1 proto kernel scope link src A.B.C.Y
192.168.254.0/24 dev eth0 proto kernel scope link src 192.168.254.1
default via A.B.C.D dev eth1
r2 root # ip route ls table 230
A.B.C.0/24 dev eth1 scope link src A.B.C.X
A.B.C.0/24 dev eth0 scope link src 192.168.254.1
default via A.B.C.D dev eth1
r2 root # ip route ls table 231
A.B.C.0/24 dev eth2 scope link src A.B.C.Y
A.B.C.0/24 dev eth0 scope link src 192.168.254.1
default via A.B.C.D dev eth2
As a result the network segment 192.168.254.128/25 does not have
access to Internet. Any ideas why? Is it a problem that eth1 is in the
same network as eth2?
Thanks in advance,
--
Kamen TOMOV
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