CentOS - Jun 2014 - parsing out adjacent text

hey all,

 I'm trying to figure out how to use apache's mod_status module to
figure
out which of the web servers in a farm of six are processing more requests
than others.

 I'm writing a script to grep out requests per second from the status
module like this:

 [root at uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  | grep
-i  requests/sec
<dt>4.08 requests/sec - 80.9 kB/second - 19.8 kB/request</dt>


That works ok. And next I'm grepping it back down and awking it to just the
part I'm interested in:

[root at uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  | grep -i
-e request -e requests/sec | grep -i -v -e currently  -e code  -e ss | awk
'{print $1}'
<dt>4.08

But now I need to get rid of just the <dt> in front of the 4.08?

I think I may be able to use the 'cut' command to do this, but I'm
unsure
how.

Any thoughts?

Thanks
Tim



-- 
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op 03-06-14 15:18, schreef Tim Dunphy:
>   [root at uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  |
grep
> -i  requests/sec
> <dt>4.08 requests/sec - 80.9 kB/second - 19.8 kB/request</dt>
>
>
> That works ok. And next I'm grepping it back down and awking it to just
the
> part I'm interested in:
>
> [root at uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  | grep
-i
> -e request -e requests/sec | grep -i -v -e currently  -e code  -e ss | awk
> '{print $1}'
> <dt>4.08
>
> But now I need to get rid of just the <dt> in front of the 4.08?
cut --delimiter=">" --field=2

you could even get rid of the awk and pipe your grep to cut
--delimiter=">" --field=2 | cut --delimiter=" " --field=1

But there are many different ways to solve this.

greetings
Patrick