CentOS - Dec 2010 - bash increment in a given way

It's ok, that i can use this, when i want an incrementing sequence, in a
given way:

# {START..END..INCREMENT}
$ for i in {0..10..2}; do echo "Welcome $i times"; done
Welcome 0 times
Welcome 2 times
Welcome 4 times
Welcome 6 times
Welcome 8 times
Welcome 10 times
$

but what's the "magic" for this? :

$ MAGIC; do echo "Welcome $i times"; done
Welcome 0 times
Welcome 1 times
Welcome 4 times
Welcome 5 times
Welcome 8 times
Welcome 9 times
$

thanks:\



      
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On Sat, Dec 11, 2010 at 06:34:25AM -0800, S Mathias wrote:
> # {START..END..INCREMENT}
> $ for i in {0..10..2}; do echo "Welcome $i times"; done
> but what's the "magic" for this? :
> 
> $ MAGIC; do echo "Welcome $i times"; done
> Welcome 0 times
> Welcome 1 times
> Welcome 4 times
> Welcome 5 times
> Welcome 8 times
> Welcome 9 times
You might just have to hard-code the sequence:

  for i in 0 1 4 5 8 9; do ....

-- 

rgds
Stephen

On Sat, Dec 11, 2010 at 8:34 AM, S Mathias <smathias1972 at yahoo.com>
wrote:
>
> It's ok, that i can use this, when i want an incrementing sequence, in
a given way:
>
> # {START..END..INCREMENT}
> $ for i in {0..10..2}; do echo "Welcome $i times"; done
> Welcome 0 times
> Welcome 2 times
> Welcome 4 times
> Welcome 6 times
> Welcome 8 times
> Welcome 10 times
> $
>
The old-school bourne compatible way is:

START=0
END=10
i=$START
while [ "$i" -le "$END" ]
do
 echo "Welcome $i times"
 i=`expr $i + 1`
done

But for a small number of iterations I'd just use for with a list.

-- 
  Les Mikesell
   lesmikesell at gmail.com