CentOS - Dec 2005 - OT ? Shell script

Does anyone have an elegant solution for finding the date of the 3rd 
Monday each month and the date of the Sunday preceding?  (Sunday 
shouldn't be beyond my capabilities, once the Monday part is worked out.)
For the past several years, I've been handling the chore using a file 
with a manually input list of dates -- which is about as elegant as 
driving a tack with a sledge hammer.

How about something like:

YEAR=2005
MONTH=12
for ((DAY=1;DAY<=31;++DAY)); do
   LC_ALL=C TZ=UTC date -d "$YEAR-$MONTH-$DAY"
done | grep "^Mon " | head -n 3 | tail -n 1

Possibly without the TZ=UTC depending on your needs...

Cheers
MaZe?

On Sun, 4 Dec 2005, Robert wrote:
> Does anyone have an elegant solution for finding the date of the 3rd Monday
> each month and the date of the Sunday preceding?  (Sunday shouldn't be
beyond
> my capabilities, once the Monday part is worked out.)
> For the past several years, I've been handling the chore using a file
with a
> manually input list of dates -- which is about as elegant as driving a tack
> with a sledge hammer.
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