asterisk users - Jul 2014 - Simultaneous Ring

I have a need to issue a dial command to a number:

same => n,Dial(${DIALGROUP1},${TIMER1},t)

After a number of seconds, let's say 10 seconds. I want to dial another set
of numbers while continuing to ring, or interrupting the first group of numbers.

same => n,Dial(${DIALGROUP2},${TIMER1},t)

Is there a way to do this without interrupting the first call?

Thanks,
Scott Haley




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asterisk-users-bounces at lists.digium.com wrote on 07/16/2014 01:46:09 PM:
> From: "Haley,Scott A" <scott.haley at edwardjones.com>
> To: "asterisk-users at lists.digium.com" <asterisk-users at
lists.digium.com>,
> Date: 07/16/2014 01:46 PM
> Subject: [asterisk-users] Simultaneous Ring
> Sent by: asterisk-users-bounces at lists.digium.com
> 
> I have a need to issue a dial command to a number:
> 
> same => n,Dial(${DIALGROUP1},${TIMER1},t)
> 
> After a number of seconds, let's say 10 seconds. I want to dial 
> another set of numbers while continuing to ring, or interrupting the
> first group of numbers.
> 
> same => n,Dial(${DIALGROUP2},${TIMER1},t)
> 
> Is there a way to do this without interrupting the first call?
> 
> Thanks,
> Scott Haley
I believe that what you want to do is best done with Local Channels. See 
this link:
http://www.asteriskdocs.org/en/3rd_Edition/asterisk-book-html-chunk/DeeperDialplan_id324598.html
for more information.
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>> After a number of seconds, let's say 10 seconds. I want to dial
another set of numbers while continuing to ring, or interrupting the first group
of numbers.
I'd use queues. 

First set of numbers in queue 1, both the first set and second set of number in
queue 2. If the call falls out of queue 1, it should fall into queue 2.

Then use the ringall strategy on both queues 

Doug 

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On Wednesday 16 Jul 2014, Haley,Scott A wrote:
> I have a need to issue a dial command to a number:
> 
> same => n,Dial(${DIALGROUP1},${TIMER1},t)
> 
> After a number of seconds, let's say 10 seconds. I want to dial another
set
> of numbers while continuing to ring, or interrupting the first group of
> numbers.
> 
> same => n,Dial(${DIALGROUP2},${TIMER1},t)
> 
> Is there a way to do this without interrupting the first call?
This sounds exactly like the sort of situation for which local channels were 
invented .....

Dial(${DIALGROUP1}&LOCAL/foo at bar) with a longer timeout than 10 seconds. 
Then
in your local channel, wait 10" and Dial(${DIALGROUP2}).  The first Dial()
will
be satisfied when someone answers either a phone in dial group 1, or a phone in 
dial group 2 set ringing by the Dial() in the local channel.

-- 
AJS

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