Hi all, We've got a department that has 5 phones using a * 1.0.9 box. They need to have an extension that rings all 5 phones at the same time. Getting all of the phones to ring isn't a problem, but they are running into a problem with the phones ringing in their ears when they are already on a call. Example: Caller one calls the queue, all of the phones rings, and employee one picks up. Caller two calls the queue, all of the phones ring including the one that Employee one is talking on, and both Caller one and Employee one are distracted. We're locked into using the current softphones, and there doesn't seem to be a way to limit them to just one line. We've tried both a true queue with the strategy set to ringall and just having the exten => Dial(SIP/ext1&SIP/ext2&etc). We also tried using SetGroup and CheckGroup(1), but that resulted in only one call reaching the phones at a time, even though the other 4 were free. What we really want to have happen is for all 5 phones to ring at once, except the ones that are already in use. It seems like there should be an easy way to do this, but I'm not seeing it. Anyone got any hints? Skippy
If you can do this is a dial plan have you tried chanisavail
application? Seems like that should work for you.
on Wednesday 08/31/2005 "Eric \"Skippy\"
Hope"(ehope@intrex.net) wrote
> Hi all,
>
> We've got a department that has 5 phones using a * 1.0.9 box. They
need
> to have an extension that rings all 5 phones at the same time. Getting
> all of the phones to ring isn't a problem, but they are running into a
> problem with the phones ringing in their ears when they are already on a
> call.
>
> Example:
> Caller one calls the queue, all of the phones rings, and employee one
> picks up.
> Caller two calls the queue, all of the phones ring including the one
> that Employee one is talking on, and both Caller one and Employee one
> are distracted.
>
> We're locked into using the current softphones, and there doesn't
seem
> to be a way to limit them to just one line.
>
> We've tried both a true queue with the strategy set to ringall and
just
> having the exten => Dial(SIP/ext1&SIP/ext2&etc). We also tried
using
> SetGroup and CheckGroup(1), but that resulted in only one call reaching
> the phones at a time, even though the other 4 were free.
>
> What we really want to have happen is for all 5 phones to ring at once,
> except the ones that are already in use. It seems like there should be
> an easy way to do this, but I'm not seeing it. Anyone got any hints?
>
> Skippy
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On 10:22, Wed 31 Aug 05, Eric Skippy Hope wrote:> Hi all, > > We've got a department that has 5 phones using a * 1.0.9 box. They need > to have an extension that rings all 5 phones at the same time. Getting > all of the phones to ring isn't a problem, but they are running into a > problem with the phones ringing in their ears when they are already on a > call. > > Example: > Caller one calls the queue, all of the phones rings, and employee one > picks up. > Caller two calls the queue, all of the phones ring including the one > that Employee one is talking on, and both Caller one and Employee one > are distracted. > > We're locked into using the current softphones, and there doesn't seem > to be a way to limit them to just one line. > > We've tried both a true queue with the strategy set to ringall and just > having the exten => Dial(SIP/ext1&SIP/ext2&etc). We also tried using > SetGroup and CheckGroup(1), but that resulted in only one call reaching > the phones at a time, even though the other 4 were free. > > What we really want to have happen is for all 5 phones to ring at once, > except the ones that are already in use. It seems like there should be > an easy way to do this, but I'm not seeing it. Anyone got any hints? >If the phones are SIP you can try incoming-limit in the sip.conf entry. For the new CVS version this has changed to call-limit I think. -- Michiel van Baak http://michiel.vanbaak.info michiel@vanbaak.info GnuPG key: http://pgp.mit.edu:11371/pks/lookup?op=get&search=0x7E0B9A2D "Why is it drug addicts and computer afficionados are both called users?"