Dear Shadee,
If you have a data.frame with the following columns:
n = 100; # population size
x = data.frame(
??????Sex = sample(c("M","F"), n, T),
??????Country = sample(c("AA", "BB", "US"), n, T),
??????Income = as.factor(sample(1:3, n, T))
)
# Dummy variable
ONE = rep(1, nrow(x))
r = aggregate(ONE ~ Sex + Income + Country, length, data = x)
r = r[, c("Country", "Income", "Sex")]
print(r)
It is possible to write more simple code, if you need only the particular
combination of variables (which you specified in your mail). But this is the
more general approach.
Note: you may want to use "sum" instead of "length", e.g. if
you have a column specifying the number of individuals in that category.
Hope this helps,
Leonard
[[alternative HTML version deleted]]
?s 18:34 de 02/06/2024, Leo Mada via R-help escreveu:> Dear Shadee, > > If you have a data.frame with the following columns: > > n = 100; # population size > x = data.frame( > ??????Sex = sample(c("M","F"), n, T), > ??????Country = sample(c("AA", "BB", "US"), n, T), > ??????Income = as.factor(sample(1:3, n, T)) > ) > > # Dummy variable > ONE = rep(1, nrow(x)) > > r = aggregate(ONE ~ Sex + Income + Country, length, data = x) > r = r[, c("Country", "Income", "Sex")] > print(r) > > It is possible to write more simple code, if you need only the particular combination of variables (which you specified in your mail). But this is the more general approach. > > Note: you may want to use "sum" instead of "length", e.g. if you have a column specifying the number of individuals in that category. > > > Hope this helps, > > Leonard > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.Hello, The following is simpler. r2 <- xtabs(~ ., x) |> as.data.frame() r2[-4L] # or r2[names(r2) != "Freq"] Hope this helps, Rui Barradas -- Este e-mail foi analisado pelo software antiv?rus AVG para verificar a presen?a de v?rus. www.avg.com
Correcting a small glitch - see new code.
________________________________
From: Leo Mada <leo.mada at syonic.eu>
Sent: Sunday, June 2, 2024 8:34 PM
To: Shadee Ashtari <shadee.ashtari at gmail.com>
Cc: r-help at r-project.org <r-help at r-project.org>
Subject: [R] R code for overlapping variables -- count
Dear Shadee,
If you have a data.frame with the following columns:
n = 100; # population size
x = data.frame(
??????Sex = sample(c("M","F"), n, T),
??????Country = sample(c("AA", "BB", "US"), n, T),
??????Income = as.factor(sample(1:3, n, T))
)
# Dummy variable
ONE = rep(1, nrow(x))
# corrected
r = aggregate(ONE ~ Sex + Income + Country, length, data = x)
r = r[, c("Country", "Income", "Sex",
"ONE")]
names(r)[4] = "Count"
print(r)
It is possible to write more simple code, if you need only the particular
combination of variables (which you specified in your mail). But this is the
more general approach.
Note: you may want to use "sum" instead of "length", e.g. if
you have a column specifying the number of individuals in that category.
Hope this helps,
Leonard
[[alternative HTML version deleted]]