llvm dev - Jun 2011 - [LLVMdev] Explanation

Hi All,
  I am trying to check if a Value type is a int32 pointer by using


if(T == Type::getInt1PtrTy(Context, AS)) ...


I am trying to understand the AS (address space).

How do I get it? Thanks.



George


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On 6 June 2011 17:08, George Baah <georgebaah at gmail.com>
wrote:
> if(T == Type::getInt1PtrTy(Context, AS)) ...
Hi,

You don't need to care about address spaces to check for an int32*:

if (T->isPointerTy()) {
  const Type* intT = cast<PointerType>(T)->getElementType();
  if (intT->isIntegerTy() && intT->getPrimitiveSizeInBits() == 32)
    cout << "Yeah!" << endl;
}

Also, to create a pointer type, if you don't care about address space
at all, use the unqualified version:

const Type* ptrT = PointerType::getUnqual(intT);

cheers,
--renato

On Jun 6, 2011, at 10:05 AM, Renato Golin wrote:
> On 6 June 2011 17:08, George Baah <georgebaah at gmail.com> wrote:
>> if(T == Type::getInt1PtrTy(Context, AS)) ...
> 
> You don't need to care about address spaces to check for an int32*:
> 
> if (T->isPointerTy()) {
>  const Type* intT = cast<PointerType>(T)->getElementType();
>  if (intT->isIntegerTy() && intT->getPrimitiveSizeInBits() ==
32)
>    cout << "Yeah!" << endl;
> }
The more idiomatic way would be:
  if (const PointerType *Ptr = dyn_cast<PointerType>(T))
    if (Ptr->getElementType()->isIntegerTy(32))
      cout << "Yeah!" << endl;

John.